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\(F=\frac{15}{14}-\left(\frac{17}{23}-\frac{80}{87}+\frac{5}{4}\right)+\left(\frac{17}{23}-\frac{15}{4}+\frac{1}{4}\right)\)
\(F=\frac{15}{14}-\frac{17}{23}+\frac{80}{87}-\frac{5}{4}+\frac{17}{23}-\frac{15}{4}+\frac{1}{4}\)
\(F=\frac{15}{14}+\left(\frac{-17}{23}+\frac{17}{23}\right)+\left(\frac{-5}{4}+\frac{-15}{4}+\frac{1}{4}\right)+\frac{80}{87}\)
\(F=\frac{15}{14}+0+\frac{-19}{4}+\frac{80}{87}\)
\(\frac{15}{14}-\left(\frac{17}{23}-\frac{80}{87}+\frac{5}{4}\right)+\left(\frac{17}{23}-\frac{15}{4}+\frac{1}{4}\right)\)
\(=\frac{15}{14}-\frac{8561}{8004}+\left(-\frac{127}{46}\right)\)
\(=-2,759031199\)
\(G=\frac{1}{25}-\frac{4}{27}+\left(\frac{-23}{27}+\frac{-1}{25}-\frac{5}{43}\right)+\frac{5}{43}-\frac{4}{7}\)
\(=\frac{1}{25}-\frac{4}{27}+\frac{-23}{27}+\frac{-1}{25}-\frac{5}{43}+\frac{5}{43}-\frac{4}{7}\)
\(=\left(\frac{1}{25}+\frac{-1}{25}\right)+\left(\frac{-4}{27}+\frac{-23}{27}\right)+\left(\frac{-5}{43}+\frac{5}{43}\right)-\frac{4}{7}\)
\(=0+\left(-1\right)+0-\frac{4}{7}\)
\(=\frac{-11}{7}\)
\(\frac{11}{15}+\frac{23}{16}-\left(5+\frac{27}{16}-\frac{19}{15}\right)+\left(\frac{-1}{2}\right)^2\)
\(=\frac{11}{15}+\frac{23}{16}-5-\frac{27}{16}+\frac{19}{15}+\frac{1}{4}\)
\(=\left(\frac{11}{15}+\frac{19}{15}\right)+\left(\frac{23}{16}-\frac{27}{16}\right)-5+\frac{1}{4}\)
\(=\frac{30}{15}-\frac{4}{16}-5+\frac{1}{4}\)
\(=2-\frac{1}{4}-5+\frac{1}{4}\)
\(=-3\)
học tốt ngôlãmtân
\(\frac{11}{15}+\frac{23}{16}-\left(5+\frac{27}{16}-\frac{19}{15}\right)+\left(-\frac{1}{2}\right)^2\) = \(\frac{11}{15}+\frac{23}{16}-5-\frac{27}{16}+\frac{19}{15}+\frac{1}{4}\)
\(=2-\frac{1}{4}-5+\frac{1}{4}=2-5=-3\)
Kb với mình nha!
3) C thiếu đề
4) \(D=\frac{1}{9}-\left|\frac{-5}{23}\right|-\left(\frac{-5}{23}+\frac{1}{9}+\frac{25}{7}\right)+\frac{50}{4}-\frac{7}{30}\)
\(D=\frac{1}{9}-\frac{5}{23}+\frac{5}{23}-\frac{1}{9}-\frac{25}{7}+\frac{50}{4}-\frac{7}{30}\)
\(D=\frac{1}{9}-\frac{1}{9}-\frac{5}{23}+\frac{5}{23}+\frac{-25}{7}+\frac{50}{4}-\frac{7}{30}\)
\(D=0+0+\frac{125}{14}-\frac{7}{30}\)
\(D=\frac{913}{105}\)
\(\Rightarrow A=\frac{14}{15}.\frac{20}{21}.\frac{41}{42}.....\frac{209}{210}\)
\(=\frac{4.7}{5.6}.\frac{5.8}{6.7}.\frac{6.9}{7.8}.....\frac{19.22}{20.21}\)
\(=\frac{22}{6}=\frac{11}{3}\)
\(e,\frac{22}{15}-x=-\frac{8}{27}\)
=> \(x=\frac{22}{15}-\left[-\frac{8}{27}\right]\)
=> \(x=\frac{22}{15}+\frac{8}{27}\)
=> \(x=\frac{198}{135}+\frac{40}{135}=\frac{198+40}{135}=\frac{238}{135}\)
\(g,\left[\frac{2x}{5}-1\right]:\left[-5\right]=\frac{1}{4}\)
=> \(\left[\frac{2x}{5}-\frac{1}{1}\right]=\frac{1}{4}\cdot\left[-5\right]\)
=> \(\left[\frac{2x}{5}-\frac{5}{5}\right]=-\frac{5}{4}\)
=> \(\frac{2x-5}{5}=-\frac{5}{4}\)
=> \(2x-5=-\frac{5}{4}\cdot5=-\frac{25}{4}\)
=> \(2x=-\frac{5}{4}\)
=> \(x=-\frac{5}{8}\)
\(h,-2\frac{1}{4}x+9\frac{1}{4}=20\)
=> \(-\frac{9}{4}x+\frac{37}{4}=20\)
=> \(-\frac{9}{4}x=20-\frac{37}{4}=\frac{43}{4}\)
=> \(x=\frac{43}{4}:\left[-\frac{9}{4}\right]=\frac{43}{4}\cdot\left[-\frac{4}{9}\right]=\frac{43}{1}\cdot\left[-\frac{1}{9}\right]=-\frac{43}{9}\)
\(i,-4\frac{3}{5}\cdot2\frac{4}{23}\le x\le-2\frac{3}{5}:1\frac{6}{15}\)
=> \(-\frac{23}{5}\cdot\frac{50}{23}\le x\le-\frac{13}{5}:\frac{21}{15}\)
=> \(-\frac{1}{1}\cdot\frac{10}{1}\le x\le-\frac{13}{5}\cdot\frac{15}{21}\)
=> \(-10\le x\le-\frac{13}{1}\cdot\frac{3}{21}\)
=> \(-10\le x\le-\frac{13}{1}\cdot\frac{1}{7}\)
=> \(-10\le x\le-\frac{13}{7}\)
Đến đây tìm x
\(H=\frac{4}{15}-\frac{23}{28}-\left(-\frac{23}{28}+\frac{-11}{15}-\frac{24}{27}\right)-\frac{2}{27}\)
\(H=\frac{4}{15}+\frac{-23}{28}+\frac{23}{28}+\frac{11}{15}+\frac{24}{27}+\frac{-2}{27}\)
\(H=\left(\frac{4}{15}+\frac{11}{15}\right)+\left(\frac{-23}{28}+\frac{23}{28}\right)+\left(\frac{24}{27}+\frac{-2}{27}\right)\)
\(H=1+0+\frac{22}{27}\)
\(H=1+\frac{22}{27}\)
\(H=\frac{27}{27}+\frac{22}{27}=\frac{49}{27}\)
\(H=\frac{4}{15}-\frac{23}{28}-\left(\frac{-23}{28}+\frac{-11}{15}-\frac{24}{27}\right)-\frac{2}{27}\)
\(H=\frac{4}{15}-\frac{23}{28}+\frac{23}{28}+\frac{11}{15}+\frac{24}{27}-\frac{2}{27}\)
\(H=\left(\frac{4}{15}+\frac{11}{15}\right)+\left(\frac{-23}{28}+\frac{23}{28}\right)+\left(\frac{24}{27}-\frac{2}{27}\right)\)
\(H=1+0+\frac{22}{27}\)
\(H=\frac{49}{27}\)