Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Câu a :
\(\dfrac{5}{12}+\dfrac{3}{4}+\dfrac{1}{3}\\ =\dfrac{5}{12}+\dfrac{9}{12}+\dfrac{4}{12}=\dfrac{3}{2}\)
câu b :
\(\dfrac{1}{4}+\dfrac{3}{7}+\dfrac{11}{14}\\ =\dfrac{7}{28}+\dfrac{12}{28}+\dfrac{22}{28}=\dfrac{41}{28}\)
câu c :
\(\dfrac{1}{4}+\dfrac{3}{12}+\dfrac{12}{36}\\ =\dfrac{3}{12}+\dfrac{3}{12}+\dfrac{4}{12}\\ =\dfrac{10}{12}=\dfrac{5}{6}\)
10/29+11/29+12/29+...+19/29
=10+11+12+13+14+15+=16+17+18+19/29
=145/29
\(\dfrac{11}{2}\): \(\dfrac{1}{4}\) \(\times\) \(\dfrac{5}{3}\)
= \(\dfrac{11}{2}\) \(\times\) \(\dfrac{4}{1}\) \(\times\) \(\dfrac{5}{3}\)
= 22 \(\times\) \(\dfrac{5}{3}\)
= \(\dfrac{110}{3}\)
\(\dfrac{5}{2}-\dfrac{1}{4}+\dfrac{5}{3}\)
= \(\dfrac{30}{12}-\dfrac{3}{12}+\dfrac{20}{12}\)
= \(\dfrac{7}{12}\)
\(\dfrac{14}{5}\times\dfrac{2}{3}\)+ 5
= \(\dfrac{28}{15}\) + 5
= \(\dfrac{28}{15}\) + \(\dfrac{75}{15}\)
= \(\dfrac{103}{15}\)
5/12 + 3/4 - 1/3 = 7/6 - 1/3 = 1/2
1/4 - 3/7 + 11/14 = -5/28 + 11/14 = 17/28
a) \(\frac{5}{12}+\frac{3}{4}-\frac{1}{3}=\frac{5}{12}+\frac{9}{12}-\frac{4}{12}=\frac{5+9-4}{12}=\frac{10}{12}=\frac{5}{6}\)
b) \(\frac{1}{4}-\frac{3}{7}+\frac{11}{14}=\frac{7}{28}-\frac{12}{28}+\frac{22}{28}=\frac{7-12+22}{28}=\frac{17}{28}\)
\(\frac{8}{14}+\frac{5}{12}+\frac{6}{14}+\frac{8}{12}-\frac{1}{12}\)
\(=\left(\frac{8}{14}+\frac{6}{14}\right)+\left(\frac{5}{12}+\frac{8}{12}-\frac{1}{12}\right)\)
\(=1+1\)
\(=2\)
\(\frac{8}{14}+\frac{5}{12}+\frac{6}{14}+\frac{8}{12}-\frac{1}{12}\)
\(=\)\(\left(\frac{8}{14}+\frac{6}{14}\right)+\left(\frac{5}{12}+\frac{8}{12}-\frac{1}{12}\right)\)
\(=\)\(1+1\)
\(=\)\(2\)
( 8/14 + 6/14 ) + ( 5/12 - 1/12 + 8/12 )
= 1 + ( 4/12 + 8/12 )
= 1 + 1 = 2
\(=\dfrac{8}{5}+\dfrac{18+2-14-6}{11}+\dfrac{8}{5}=\dfrac{16}{5}\)
=28/14+22/11=2+2=4
( 24/14 + 4/14) + (12/11 + 10/11)
=28/14 +22/11
=2+2
=4