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0,9+0,3*4+0,3*93
=0,3*3+0,3*4+0,3*93
=0,3*(3+4+93)
=0,3*100
=30
0,9+0,3x4+0,3x93
= 0,3x(4+93)+0,9
= 0,3x97+0,9
= 29,1+0,9
=30
a)1 /3 +1/4+2/3+3/4=\(\frac{1}{3}\)+\(\frac{2}{3}\)+\(\frac{1}{4}\)+\(\frac{3}{4}\)=1+1=2
b)1/2 +/3 -/5 +1/6=4/5
a,1/3+1/4+2/3+3/4
=(1/3+2/3)+(1/4+3/4)
= 1 + 1
= 2
nha, còn phàn b mình chưa biết
a)1/3+1/4+2/3+3/4
=(1/3+2/3)+(1/4+3/4)
=1+1
=2.
b)1/2+1/3-1/5+1/6
=(1/2+1/3+1/6)-1/5
=1-1/5
=4/5
c)2/3x4/5+1/3x4/5
=4/5x(2/3+1/3)
=4/5x1
=4/5
d)2/3x4/5-1/3x4/5
=4/5x(2/3-1/3)
=4/5x1/3
=4/15
\(\frac{2}{9}+\frac{1}{5}+\frac{7}{9}+\frac{4}{5}=\left(\frac{2}{9}+\frac{7}{9}\right)+\left(\frac{1}{5}+\frac{4}{5}\right)=\frac{9}{9}+\frac{5}{5}=1+1=2\)
\(\frac{2}{9}+\frac{1}{5}+\frac{7}{9}+\frac{4}{5}=\left(\frac{2}{9}+\frac{7}{9}\right)+\left(\frac{1}{5}+\frac{4}{5}\right)=1+1=2\)
a) = \(\frac{1+2+3+..+11}{3}=\frac{\left(1+11\right)+\left(2+9\right)+..+\left(5+7\right)+6}{3}=\frac{12.5+6}{3}=\frac{66}{3}=22\)
b) A = \(9+\frac{9}{2}+\frac{9}{4}+\frac{9}{8}+...+\frac{9}{128}+\frac{9}{256}\)
2 x A = 18 + 9 + \(\frac{9}{2}+\frac{9}{4}+\frac{9}{8}+...+\frac{9}{128}\)
Lấy 2 x A - A = 18 - \(\frac{9}{256}\)
A = 4599/256