Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(3A=\frac{6}{3\times\left(3+6\right)}+\frac{15}{9\times\left(9+15\right)}+...+\frac{39}{84\times\left(84+39\right)}\)
\(=\frac{1}{3}-\frac{1}{9}+\frac{1}{9}-\frac{1}{24}+...+\frac{1}{84}-\frac{1}{123}=\frac{1}{3}-\frac{1}{123}=\frac{40}{123}\)
\(\Rightarrow A=\frac{40}{3.123}=\frac{40}{369}\)
\(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{8.9.10}=\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{2.3}\right)+\frac{1}{2}.\left(\frac{1}{2.3}-\frac{1}{3.4}\right)+...+\frac{1}{2}.\left(\frac{1}{8.9}-\frac{1}{9.10}\right)\)
\(=\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{8.9}-\frac{1}{9.10}\right)\)
\(\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{9.10}\right)=\frac{1}{2}.\frac{22}{45}=\frac{11}{45}\)
\(=\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{11}\)
\(=\frac{1}{1}-\frac{1}{11}=\frac{10}{11}\)
2222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222225444444455555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555
a \(\frac{4}{18}+\frac{5}{13}+\frac{7}{9}+\frac{21}{13}\)
= \(\left(\frac{4}{18}+\frac{7}{9}\right)+\left(\frac{5}{13}+\frac{21}{13}\right)\)
= \(1+2\)
= \(3\)
b \(\frac{4}{3}-\frac{2}{7}-\frac{5}{7}+\frac{2}{3}\)
= \(\left(\frac{4}{3}-\frac{2}{3}\right)-\left(\frac{2}{7}+\frac{5}{7}\right)\)
= \(\frac{2}{3}-1\)
= \(-\frac{1}{3}\)
27/8 - 7/3 + 4/3 - 2
= 27/8 - (7/3 - 4/3) - 2
= 27/8 - 1 - 2
=27/8 - 3
= 3/8
a ) \(=\frac{35\cdot42}{5\cdot2}=\frac{7\cdot5\cdot2\cdot21}{5\cdot2}\)
\(=\frac{7\cdot21}{1}=147\)
b) \(=\frac{54\cdot35}{7\cdot9}\)
\(=\frac{6\cdot9\cdot7\cdot5}{7\cdot9}\)
\(=\frac{6\cdot5}{1}=30\)
Dễ mà bạn cũng ko biết sao để mình giải cho
0,25 + 9998 +4/5+1/5+3/4
= 1/4+9998+4/5+1/5+3/4
=(1/4+3/4)+(4/5+1/5)+9998
=1+1+9998
=2+9998
=10000
Nhớ k và ấn đúng cho mình nhé !
Lần sau khó mình giúp tiếp cho
\(\dfrac{42x45}{5x7}=\dfrac{7x6x5x9}{5x7}=\dfrac{54}{1}=54\)
\(\dfrac{54x56}{7x9}=\dfrac{6x9x7x8}{7x9}=\dfrac{48}{1}=48\)
`(42 xx45)/(5xx7) =( 6xx7xx9xx5)/(5xx7) = 6 xx9 = 54`
`(54xx56)/(7xx9) = (9xx6xx7xx8)/(7xx9) = 6xx8 = 48`