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1 tháng 8 2016

\(=\frac{\frac{5}{11.2}+\frac{3}{13}-\frac{1}{2}}{\frac{4}{13}-\frac{1}{11}+\frac{3}{2}}=\frac{5}{\frac{2}{4}}=\frac{5}{\frac{1}{2}}\)

1 tháng 8 2016

bn giải bài rõ ràng hưn giùm mk cái nha

a: \(=\dfrac{17}{4}-\dfrac{37}{100}+\dfrac{1}{8}-\dfrac{32}{25}-\dfrac{5}{2}+\dfrac{7}{2}\)

\(=\dfrac{35}{8}+\dfrac{8}{8}-\dfrac{37}{100}-\dfrac{128}{100}\)

\(=\dfrac{43}{8}-\dfrac{165}{100}=\dfrac{149}{40}\)

b: \(=\left(\dfrac{22\cdot26+3\cdot10-65}{130}\right):\left(\dfrac{4\cdot22-2\cdot26+3\cdot143}{286}\right)\)

\(=\dfrac{537}{130}\cdot\dfrac{286}{465}=\dfrac{1969}{775}\)

15 tháng 8 2016

Thiếu đề

hik như x=2010

3 tháng 1 2017

Ta có :

(x+1)/2009 + (x+2)/2008 = (x+3)/2007 + (x+4)/2006
<=> (x+1)/2009 + 1 + (x+2)/2008 + 1 = (x+3)/2007 +1 + (x+4)/2006 + 1
<=> (x+2010)/2009 + (x+2010)/2008 = (x+2010)/2007 + (x+2010)/2006
<=> (x + 2010).[ 1/2009 + 1/2008 - 1/2007 - 1/2006 ] = 0
<=> x = -2010

10 tháng 5 2016

Ta có: \(1+2+3+...+n=\frac{n.\left(n+1\right)}{2}\)

\(Q=\frac{1}{1+2}+\frac{1}{1+2+3}+....+\frac{1}{1+2+3+...+10}\)

\(Q=\frac{1}{\frac{2.\left(2+1\right)}{2}}+\frac{1}{\frac{3.\left(3+1\right)}{2}}+....+\frac{1}{\frac{10.\left(10+1\right)}{2}}\)

\(Q=\frac{1}{\frac{2.3}{2}}+\frac{1}{\frac{3.4}{2}}+....+\frac{1}{\frac{10.11}{2}}\)

\(Q=\frac{2}{2.3}+\frac{2}{3.4}+...+\frac{2}{10.11}\)

\(\frac{1}{2}Q=\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{10.11}\)

\(\frac{1}{2}Q=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{10}-\frac{1}{11}=\frac{1}{2}-\frac{1}{11}=\frac{9}{22}\)

=>\(Q=\frac{9}{22}.2=\frac{9}{11}\)

10 tháng 5 2016

 

\(Q=\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{55}\\ \Rightarrow\frac{1}{2}Q=\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{110}\)

Tiếp theo tự tính nhéhahaToán lớp 6

2 tháng 7 2016

m​inh lam bai nay roi nhung minh ko co nha nen minh ko nho

2 tháng 7 2016

bn cố nhớ đi, giúp mk

15 tháng 8 2016

cảm ơn bn ok

15 tháng 5 2016

Ta có : 

\(B=\frac{5}{2\cdot1}+\frac{4}{1\cdot11}+\frac{3}{11\cdot2}+\frac{1}{2\cdot15}+\frac{13}{15\cdot4}\)

\(=>\frac{B}{7}=\frac{5}{2\cdot7}+\frac{4}{7\cdot11}+\frac{3}{11\cdot14}+\frac{1}{14\cdot15}+\frac{13}{15\cdot28}\)

\(=>\frac{B}{7}=\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{28}\)

\(=>\frac{B}{7}=\frac{1}{2}-\frac{1}{28}=\frac{14}{28}-\frac{1}{28}=\frac{13}{28}\)

\(=>B=\frac{13}{28}\cdot7=\frac{13}{4}\)

15 tháng 5 2016

Khó wá

23 tháng 5 2016

\(\frac{1}{7}\)B=\(\frac{5}{2.7.1}+\frac{4}{1.7.11}+\frac{3}{11.2.7}+\frac{1}{2.7.15}+\frac{13}{15.4.7}\)

\(\frac{1}{7}\)B=\(\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.28}\)

\(\frac{1}{7}B=\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{28}\)

\(\frac{1}{7}B=\frac{1}{2}-\frac{1}{28}\)

\(\frac{1}{7}B=\frac{13}{28}\)

B=\(\frac{13}{28}:\frac{1}{7}\)

B=\(\frac{13}{4}\)

1 tháng 5 2019

1717B=52.7.1+41.7.11+311.2.7+12.7.15+1315.4.752.7.1+41.7.11+311.2.7+12.7.15+1315.4.7

1717B=52.7+47.11+311.14+114.15+1315.2852.7+47.11+311.14+114.15+1315.28

17B=12−17+17−111+111−114+114−115+115−12817B=12−17+17−111+111−114+114−115+115−128

17B=12−12817B=12−128

17B=132817B=1328

B=1328:171328:17

B=134

1717B=52.7.1+41.7.11+311.2.7+12.7.15+1315.4.752.7.1+41.7.11+311.2.7+12.7.15+1315.4.7

1717B=52.7+47.11+311.14+114.15+1315.2852.7+47.11+311.14+114.15+1315.28

17B=12−17+17−111+111−114+114−115+115−12817B=12−17+17−111+111−114+114−115+115−128

17B=12−12817B=12−128

17B=132817B=1328

B=1328:171328:17

B=134

1717B=52.7.1+41.7.11+311.2.7+12.7.15+1315.4.752.7.1+41.7.11+311.2.7+12.7.15+1315.4.7

1717B=52.7+47.11+311.14+114.15+1315.2852.7+47.11+311.14+114.15+1315.28

17B=12−17+17−111+111−114+114−115+115−12817B=12−17+17−111+111−114+114−115+115−128

17B=12−12817B=12−128

17B=132817B=1328

B=1328:171328:17

B=134

1717B=52.7.1+41.7.11+311.2.7+12.7.15+1315.4.752.7.1+41.7.11+311.2.7+12.7.15+1315.4.7

1717B=52.7+47.11+311.14+114.15+1315.2852.7+47.11+311.14+114.15+1315.28

17B=12−17+17−111+111−114+114−115+115−12817B=12−17+17−111+111−114+114−115+115−128

17B=12−12817B=12−128

17B=132817B=1328

B=1328:171328:17

B=134

1717B=52.7.1+41.7.11+311.2.7+12.7.15+1315.4.752.7.1+41.7.11+311.2.7+12.7.15+1315.4.7

1717B=52.7+47.11+311.14+114.15+1315.2852.7+47.11+311.14+114.15+1315.28

17B=12−17+17−111+111−114+114−115+115−12817B=12−17+17−111+111−114+114−115+115−128

17B=12−12817B=12−128

17B=132817B=1328

B=1328:171328:17

B=134

1717B=52.7.1+41.7.11+311.2.7+12.7.15+1315.4.752.7.1+41.7.11+311.2.7+12.7.15+1315.4.7

1717B=52.7+47.11+311.14+114.15+1315.2852.7+47.11+311.14+114.15+1315.28

17B=12−17+17−111+111−114+114−115+115−12817B=12−17+17−111+111−114+114−115+115−128

17B=12−12817B=12−128

17B=132817B=1328

B=1328:171328:17

B=134

1717B=52.7.1+41.7.11+311.2.7+12.7.15+1315.4.752.7.1+41.7.11+311.2.7+12.7.15+1315.4.7

1717B=52.7+47.11+311.14+114.15+1315.2852.7+47.11+311.14+114.15+1315.28

17B=12−17+17−111+111−114+114−115+115−12817B=12−17+17−111+111−114+114−115+115−128

17B=12−12817B=12−128

17B=132817B=1328

B=1328:171328:17

B=134

1717B=52.7.1+41.7.11+311.2.7+12.7.15+1315.4.752.7.1+41.7.11+311.2.7+12.7.15+1315.4.7

1717B=52.7+47.11+311.14+114.15+1315.2852.7+47.11+311.14+114.15+1315.28

17B=12−17+17−111+111−114+114−115+115−12817B=12−17+17−111+111−114+114−115+115−128

17B=12−12817B=12−128

17B=132817B=1328

B=1328:171328:17

B=134