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[x+1]+[x+2]+[x+3]+[x+4]+[x+5]=45
=[x+x+x+x+x]+[1+2+3+4+5]=45
=5x+15=45
5x=30
x=30:5
x=6
Vậy x=6
(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=45
(x+x+x+x+x)+1+2+3+4+5=45
5x+15=45
5x=45-15
5x=30
x=30:5
x=6
vậy x=6
Hình chữ nhật có diện tích 5/7 m², chiều dài 3/5 m tính chu vi hình chữ nhật đó
\(\left(\dfrac{1}{2}+\dfrac{1}{3}\right)\times\dfrac{2}{5}=\dfrac{5}{6}\times\dfrac{2}{5}=\dfrac{2}{6}=\dfrac{1}{3}\)
\(\left(\dfrac{1}{2}+\dfrac{1}{3}\right)\times\dfrac{2}{5}=\left(\dfrac{3}{6}+\dfrac{2}{6}\right)\times\dfrac{2}{5}=\dfrac{5}{6}\times\dfrac{2}{5}=\dfrac{1}{3}\times\dfrac{1}{1}=\dfrac{1}{3}\)
\(12:y=\frac{3}{4}+\frac{4}{5}\)
\(12:y=\frac{15}{20}+\frac{16}{20}\)
\(12:y=\frac{31}{20}\)
\(y=12:\frac{31}{20}\)
\(y=12x\frac{20}{31}\)
\(y=\frac{240}{31}\)
\(\frac{4}{5}xY=1\)
\(y=1:\frac{4}{5}\)
\(y=1x\frac{5}{4}\)
\(y=\frac{5}{4}\)
\(\frac{37}{63}-y=\frac{1}{7}\)
\(y=\frac{37}{63}-\frac{1}{7}\)
\(y=\frac{37}{63}-\frac{9}{63}\)
\(y=\frac{28}{63}\)
\(y=\frac{4}{9}\)
\(y:\frac{3}{7}=\frac{3}{42}+\frac{5}{7}\)
\(y:\frac{3}{7}=\frac{3}{42}+\frac{30}{42}\)
\(y:\frac{3}{7}=\frac{33}{42}\)
\(y:\frac{3}{7}=\frac{11}{14}\)
\(y=\frac{11}{14}x\frac{3}{7}\)
\(y=\frac{33}{98}\)
\(12:y=\frac{3}{4}+\frac{4}{5}\) \(\frac{37}{63}-y=\frac{1}{7}\)
\(12:y=\frac{31}{20}\) \(y=\frac{37}{63}-\frac{1}{7}\)
\(y=12:\frac{31}{20}\) \(y=\frac{4}{9}\)
\(y=\frac{240}{31}\)
\(\frac{4}{5}\cdot y=1\) \(y:\frac{3}{7}=\frac{3}{42}+\frac{5}{7}\)
\(y=1:\frac{4}{5}\) \(y:\frac{3}{7}=\frac{11}{14}\)
\(y=\frac{5}{4}\) \(y=\frac{11}{14}.\frac{3}{7}\)
\(y=\frac{33}{98}\)
\(y+\dfrac{4}{5}=\dfrac{4}{5}-\left(\dfrac{3}{7}+\dfrac{3}{5}\right)\)
\(y=\dfrac{4}{5}-\left(\dfrac{3}{7}+\dfrac{3}{5}\right)-\dfrac{4}{5}\)
\(y=\dfrac{36}{35}\)
...
( là mở ngoặc
y + 4/5 = 4/5 - (3/7 + 3/5)
y + 4/5 = 4/5 - 36/35
Lỗi đề :v