Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\left(x\times1\right)+\left(x\times2\right)+\left(x\times3\right)+....+\left(x\times10\right)=240\)
\(\left(x\times x\times x\times....\times x\right)\times\left(1+2+3+...+10\right)=240\)
\(1x\times\frac{\left(10+1\right).10}{2}=240\)
\(1x\times55=240\)
\(1x=240\div55\)
\(1x=\frac{48}{11}\)
\(\Rightarrow x=\frac{48}{11}\)
11 x 10 - 10 x 9 + 9 x 8 - 8 x 7 + 7 x 6 - 6 x 5 + 5 x 4 - 4 x 3 + 3 x 2 - 2 x 1 = 60
1> a) \(\frac{5}{7}x4:\frac{5}{9}=\frac{5}{7}:\frac{5}{9}x4=\frac{5}{7}x\frac{9}{5}x4=\frac{9}{7}x4=\frac{9x4}{7}=\frac{36}{7}\)
\(b,8x\frac{2}{3}:\frac{1}{2}=8x\frac{2}{3}x\frac{2}{1}=8x2x\frac{2}{3}=16x\frac{2}{3}=\frac{32}{3}\)
\(c,6:\frac{3}{5}-\frac{7}{6}x\frac{6}{7}=6x\frac{5}{3}-1=10-1=9\)
\(\frac{21}{5}x\frac{10}{11}+\frac{57}{11}=\frac{42}{11}+\frac{57}{11}=\frac{99}{11}=9\)
2) a) \(\frac{35}{9}:x=\frac{35}{6}\)
\(x=\frac{35}{9}:\frac{35}{6}\)
\(x=\frac{35}{9}x\frac{6}{35}\)
\(x=\frac{2}{3}\)
b) \(\left(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}\right)x10-X=0\)
\(\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+.....+\frac{1}{5}-\frac{1}{6}\right)x10-X=0\)
\(\left(\frac{1}{1}-\frac{1}{6}\right)x10-X=10\)
\(\frac{5}{6}x10-X=0\)
\(X=\frac{5}{6}x10=\frac{25}{3}\)
Đúng nha !!!!
1/a/\(\frac{5}{7}\cdot4:\frac{5}{9}=\frac{20}{7}:\frac{5}{9}=\frac{20}{7}\cdot\frac{9}{5}=\frac{36}{7}\)
b/\(8\cdot\frac{2}{3}:\frac{1}{2}=\frac{16}{3}:\frac{1}{2}=\frac{16}{3}\cdot\frac{2}{1}=\frac{32}{3}\)
c/\(6:\frac{3}{5}-\frac{7}{6}\cdot\frac{6}{7}=6\cdot\frac{5}{3}-1=10-1=9\)
2/a/\(\frac{35}{9}:x=\frac{35}{6}\)
\(x=\frac{35}{9}:\frac{35}{6}=\frac{35}{9}\cdot\frac{6}{35}\)
\(x=\frac{2}{3}\)
b/\(\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}\right)\cdot10-x=0\)
\(\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}\right)\cdot10-x=0\)
\(\left(\frac{30}{60}+\frac{10}{60}+\frac{5}{60}+\frac{2}{30}\right)\cdot10-x=0\)
\(\frac{47}{60}\cdot10-x=0\)
\(\frac{47}{6}-x=0\)
\(x=\frac{47}{6}-0\)
\(x=\frac{47}{6}\)
a)\(\frac{5}{6}+\frac{3}{4}x=3\Leftrightarrow\frac{3}{4}x=\frac{13}{6}\Leftrightarrow x=\frac{26}{9}\)
b)\(\frac{8}{x}\cdot\frac{3}{4}=\frac{9}{10}\Leftrightarrow\frac{8}{x}=\frac{6}{5}\Leftrightarrow x=\frac{8\cdot5}{6}=\frac{20}{3}\)
c)\(3\cdot\left(x+\frac{1}{2}\right)-\frac{1}{3}=\frac{2}{5}\Leftrightarrow3\left(x+\frac{1}{2}\right)=\frac{11}{15}\Leftrightarrow x+\frac{1}{2}=\frac{11}{45}\Leftrightarrow x=-\frac{23}{90}\)
d)\(\frac{1}{4}+\frac{x}{3}=\frac{5}{6}\Leftrightarrow\frac{x}{3}=\frac{7}{12}\Leftrightarrow x=\frac{7\cdot3}{12}=\frac{7}{4}\)
Bạn ơi , cái dấu hai chiều là sao ? trả lời nhanh cho mình nhé !
c] 7 * x + 8 * x + 9 * x + .... + 100 * x = 1025
(7+8+9+...+100)*x=1025
Coi A= 7+8+...+100
Số các số hạng của A là:
(100-7):1+1=94 (số)
=>A=(100+7)*94:2=5029
Ta lại có:
5029*x=1025
=>x=1025:5019=1025/5019
a, \(x.\left(\frac{3}{2}+\frac{1}{4}-\frac{1}{2}\right)=x.\left(\frac{6}{4}+\frac{1}{4}-\frac{2}{4}\right)=\frac{10}{9}\)
\(x.\frac{5}{4}=\frac{10}{9}\)
\(x=\frac{10}{9}:\frac{5}{4}=\frac{10}{9}.\frac{4}{5}=\frac{8}{9}\)
a,(x+1)+(x+2)+(x+3)+....+(x+9)+(x+10)=240
Từ 1 đến 10 có số số hạng là:(10-1):1+1=10
Từ 1 đến 10 có tổng là:(10+1)x10:2=55
Ta có:(Xx10)+55=240
Xx10 =240-55
Xx10 =185
X =185:10
X =18,5