Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a,x/9=5/3 = x=15
b,17/x=85/105 = x = 21
c,6/8=15/x = x = 20
d,x/8=2/3 = x = 6
a) \(-27.43+x=27.57\)\(\Leftrightarrow x=27.57-\left(-27.43\right)\)
\(\Leftrightarrow x=27.57+27.43\)\(\Leftrightarrow x=27.\left(57+43\right)\)
\(\Leftrightarrow x=27.100\)\(\Leftrightarrow x=2700\)
Vậy \(x=2700\)
b) \(3\left(x-2\right)+5\left(3-x\right)=3\)\(\Leftrightarrow3x-6+15-5x=3\)
\(\Leftrightarrow3x-5x=3+6-15\)\(\Leftrightarrow-2x=-6\)\(\Leftrightarrow x=3\)
Vậy \(x=3\)
c) \(3^x=27\)\(\Leftrightarrow3^x=3^3\)\(\Leftrightarrow x=3\)
Vậy \(x=3\)
d) \(2^x+17=-15\)\(\Leftrightarrow2^x=-32\)( vô nghiệm )
Vậy \(x\in\varnothing\)
e) \(\left(x-2\right)^2=9\)\(\Leftrightarrow\orbr{\begin{cases}x-2=-3\\x-2=3\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-1\\x=5\end{cases}}\)
Vậy \(x=-1\)hoặc \(x=5\)
f) \(\left(x-2\right)^3=27\)\(\Leftrightarrow\left(x-2\right)^3=3^3\)\(\Leftrightarrow x-2=3\)\(\Leftrightarrow x=5\)
Vậy \(x=5\)
g) \(\left(x-2\right)^3=-27\)\(\Leftrightarrow\left(x-2\right)^3=\left(-3\right)^3\)\(\Leftrightarrow x-2=-3\)\(\Leftrightarrow x=-1\)
Vậy \(x=-1\)
a) \(3^{x+1}.15=135\)
\(\Rightarrow3^{x+1}=9\)
\(\Rightarrow3^{x+1}=3^2\)
\(\Rightarrow x+1=2\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
b) \(x+2x+2^2x+....+2^{2016}x=2^{2017}-1\\ \Rightarrow x\left(2+2^2+...+2^{2016}\right)=2^{2017}-1\\ \Rightarrow x\left(2^{2017}-2\right)=2^{2017}-1\)
c) \(x\left(x-1\right)+\left(x-1\right)^2=0\\ \Rightarrow x\left(x-1\right)+\left(x-1\right)\left(x-1\right)=0\\ \Rightarrow\left(x-1\right)\left(x+\left(x-1\right)\right)=0\\ \Rightarrow\left(x-1\right)\left(2x-1\right)=0\\ \Rightarrow\begin{cases}x-1=0\\2x-1=0\end{cases}\)
d) \(2^2.2^5\le2^{x-5}\le2^{10}\\ \Rightarrow2^7\le2^{x-5}\le2^{10}\)
a) 3/x-7 = 27/135
3/x-7 = 3/15
x - 7 = 15
x = 15 + 7
x = 22
a) \(\frac{3}{x-7}=\frac{27}{135}\)
\(\Rightarrow\)\(\left(x-7\right).27=3.135\)
\(\Rightarrow\)\(\left(x-7\right).27=405\)
\(\Rightarrow\)\(x-7=15\)
\(\Rightarrow\)\(x=22\)
Vậy \(x=22\)
b ) \(71+65.4=\frac{x+140}{x}+260\)
\(71+260=\frac{x+140}{x}+260\)
\(331=\frac{x+140}{x}+260\)
\(331-260=\frac{x+140}{x}\)
\(71=\frac{x+140}{x}\)
\(71=\frac{x}{x}+\frac{140}{x}\)
\(71=1+\frac{140}{x}\)
\(70=\frac{140}{x}\)
\(x=140\div70\)
\(x=20\)
Vậy \(x=20\)
#TQY
a) Ta có: \(\frac{x}{5}=\frac{x+6}{15}\Rightarrow15x=5\left(x+6\right)\)
\(\Rightarrow15x=5x+30\)
\(\Rightarrow10x=30\)
=> x = 3
Vậy x = 3
b) \(\frac{x+10}{27}=\frac{x}{9}\Rightarrow9\left(x+10\right)=27x\)
\(\Rightarrow9x+90=27x\)
\(\Rightarrow18x=90\)
=> x = 5
Vậy x = 5
c) \(\frac{x+16}{35}=\frac{x}{7}\Rightarrow7\left(x+16\right)=35x\)
\(\Rightarrow7x+112=35x\)
\(\Rightarrow28x=112\)
=>x = 4
Vậy x = 4
NĂM MỚI AN LÀNH
ai làm nhanh mk sẽ cho và tặng quà nha nhớ để lại địa chỉ qua tết mk sẽ gửi
a)\(\frac{x}{15}=\frac{2}{5}\)=> x=\(\frac{15.2}{5}=6\)
b) \(\frac{3}{x^7}hay\frac{3}{x.7}\)