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a) \(\frac{-2}{3}.\left|x\right|=16\)
\(\left|x\right|=16:\frac{-2}{3}\)
\(\left|x\right|=-24\)
\(\Rightarrow\text{ x không tồn tại}\)
b) \(\frac{-1}{2}.x+\frac{2}{3}.\frac{-5}{4}=\frac{3}{5}-\frac{5}{6}\)
\(\frac{-1}{2}.x+\left(\frac{-5}{6}\right)=-\frac{7}{30}\)
\(\frac{-1}{2}.x=\frac{-7}{30}+\frac{5}{6}\)
\(-\frac{1}{2}.x=\frac{3}{5}\)
\(x=\frac{3}{5}:\frac{-1}{2}\)
\(x=-\frac{6}{5}\)
c) \(2.\left(x+1\right)=3x-4\)
\(2x+2=3x-4\)
\(4+2=3x-2x\)
\(x=6\)
Ta có : (6 - x)2014 = (6 - x)2015
=> (6 - x)2014 - (6 - x)2015 = 0
<=> (6 - x)2014(1 - 6 - x) = 0
<=> \(\orbr{\begin{cases}\left(6-x\right)^{2014}=0\\1-6-x=0\end{cases}}\)
<=> \(\orbr{\begin{cases}6-x=0\\-5-x=0\end{cases}}\)
<=> \(\orbr{\begin{cases}x=6\\x=-5\end{cases}}\)
sory bạn trừng hợp hai mk nhầm :
1 - (6 - x) = 0
=> 1 - 6 + x = 0
=> -5 + x = 0
=> x = 5
a. \(x-\frac{3}{7}:\frac{9}{14}=-\frac{7}{6}\Rightarrow x-\frac{2}{3}=-\frac{7}{6}\Rightarrow x=-\frac{1}{2}\)
b. \(\frac{3}{4}+\frac{1}{4}x=\frac{5}{8}\Rightarrow\frac{1}{4}x=-\frac{1}{8}\Rightarrow x=-\frac{1}{2}\)
c. \(\left|4x-1\right|-\frac{1}{2}=3\Rightarrow\left|4x-1\right|=\frac{7}{2}\Leftrightarrow\orbr{\begin{cases}4x-1=\frac{7}{2}\\4x-1=-\frac{7}{2}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{9}{8}\\x=-\frac{5}{8}\end{cases}}}\)
d. \(25\%x+x=-1,25\Rightarrow125\%x=-1,25\Rightarrow\frac{5}{4}x=-\frac{5}{4}\Rightarrow x=-1\)
a\()\)\(x+\frac{3}{4}\)=\(\frac{-3}{3}\)
x=\(-1\)-\(\frac{3}{4}\)
x=\(\frac{-7}{4}\)
b\()\)\(\frac{1}{2}\)-x=\(\frac{7}{2}\)
x=\(\frac{1}{2}\)-\(\frac{7}{2}\)
x=\(\frac{-6}{2}\)
x= -3
c\()\)\(\frac{3}{4}\)x+\(\frac{1}{5}\)=\(\frac{1}{6}\)
\(\frac{3}{4}\)x=\(\frac{-1}{30}\)
x=\(\frac{-1}{30}\)\(\div\)\(\frac{3}{4}\)
x=\(\frac{-2}{45}\)
d\()\)\(\frac{x}{16}\)=\(\frac{1}{4}\)
4x=16
x=4
Good luck