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218-(x+31)=x-29
218-x-31=x-29
(218-31)-x=x-29
187-x=x-29 -x=x-29-187 -2x=-158 x=-158/-2 x=79218 - (x +31) = x - 29
218 - x -31 = x - 29
(218 - 31) - x = x - 29
187 - x = x - 29 - x = x - 29 -187 - 2x = -158x = -158x-2x = 79
218-(x+31)=x-29
218-31=x+x-29
2x=218-31+29=218-(31-29)
2x=218-2=216
x=216/2
x=108
\(218-\left(x+31\right)=x-29\)
\(\Leftrightarrow\)\(218-x-31=x-29\)
\(\Leftrightarrow\)\(187-x=x-29\)
\(\Leftrightarrow\)\(2x=216\)
\(\Leftrightarrow\)\(x=108\)
Vậy....
218-(x + 31) = x - 29
=> 218 - x - 31 = x - 29
=> (218-31) - x = x - 29
=> 187 - x = x - 29
=> -x - x = -29 - 187
=> -2x = -216
=> x = -216 : (-2)
=> x = 108
a) <=> -218 - x - 31 = x - 29
<=> 2x = -220
<=> x = -110
b) <=> -12x + 60 + 21 - 7x = 5
<=> -19x = -76
<=> x = 4
c) <=> 3x + 21 + 28 = 9 - 2x - 10
<=> 5x = -50
<=> x = -10
d) <=> 2x + 6 - 3x + 15 = 12 - 4x - 18
<=> 3x = -27
<=> x = -9
\(a,\left(\frac{31}{20}-\frac{26}{45}\right)\cdot\left(\frac{-36}{35}\right)< x< \left(\frac{51}{56}+\frac{8}{21}+\frac{1}{3}\right)\cdot\frac{8}{13}\)
\(taco:\left(\frac{31}{20}-\frac{26}{45}\right)\cdot\left(\frac{-36}{35}\right)=\frac{35}{36}\cdot\frac{-36}{35}=-1\)
\(\left(\frac{51}{56}+\frac{8}{21}+\frac{1}{3}\right)\cdot\frac{8}{13}=\frac{13}{8}\cdot\frac{8}{13}=1\)
\(=>x=0\)
\(b,\frac{-5}{6}+\frac{8}{3}+\frac{29}{-3}< x< \frac{-1}{2}+2+\frac{5}{2}\)(dau <co dau gach ngang o duoi nha)
\(taco:\frac{-5}{6}+\frac{8}{3}+\frac{29}{-3}=\frac{-5}{6}+\frac{8}{3}+\frac{-29}{3}=\frac{-5}{6}+\frac{16}{6}+\frac{-58}{6}=\frac{-47}{6}=-7,8\)
\(\frac{-1}{2}+2+\frac{5}{2}=\frac{3}{2}+\frac{5}{2}=4\)
tu do \(=>x=-7,8;...;0;1;2;3;4\)
Ta có : 218 - ( x + 81 ) = x - 29
\( \implies\) 218 - x - 81 = x - 29
\( \implies\) 137 - x = x - 29
\( \implies\) 2x = 166
\( \implies\) x = 83
218 - (x +31)=x - 29
218 - x -31=x-29
218-x=x-29+31
218-x=x+2
x+2=218-x
2=218-x-x
2=218-Xx2
xX2=218-2
Xx2=216
x=216:2
x=108