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KH
15 tháng 10 2016
\(\frac{3}{34}+\frac{34}{34}.\frac{3}{4}=\frac{3}{34}+1.\frac{3}{4}=\frac{3}{34}+\frac{3}{4}=\frac{57}{68}\)
\(\frac{23}{3}.\frac{56}{6}+\frac{86}{78}=\frac{23}{3}.\frac{28}{3}+\frac{43}{39}=\frac{644}{9}+\frac{28}{3}=\frac{728}{9}\)
\(\frac{3}{45}:\frac{1}{4}=\frac{1}{15}.4=\frac{4}{15}\)
\(\frac{5}{34}-\frac{3}{6}=\frac{5}{34}-\frac{1}{2}=\frac{3}{4}\)
9 tháng 8 2020
\(\left(a\right)\frac{34-x}{30}=\frac{5}{6}\)
\(\frac{34-x}{30}=\frac{25}{30}\)
34 - x = 25
x = 34 - 25 = 9
\(\left(b\right)\frac{x+13}{34}=\frac{12}{17}\)
\(\frac{x+13}{34}=\frac{24}{34}\)
x + 13 = 24
x = 24 - 13 = 11
\(\left(c\right)\left(x+\frac{1}{3}\right)+\left(x+\frac{1}{9}\right)+\left(x+\frac{1}{27}\right)+\left(x+\frac{1}{81}\right)=\frac{56}{81}\)
\(4x+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}=\frac{56}{81}\)
Đặt \(A=\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)
Ta có : \(3A=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}\)
\(3A-A=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}-\frac{1}{3}-\frac{1}{9}-\frac{1}{27}-\frac{1}{81}\)
\(2A=1-\frac{1}{81}=\frac{80}{81}\)
\(A=\frac{80}{81}\div2=\frac{40}{81}\)
\(\Rightarrow4x+\frac{40}{81}=\frac{56}{81}\)
\(4x=\frac{56}{81}-\frac{40}{81}\)
\(4x=\frac{16}{81}\)
\(x=\frac{16}{81}\div4=\frac{4}{81}\)
SH
5
BI
18 tháng 4 2016
\(\frac{56-x}{34}=\frac{144}{96}=\frac{3}{2}\)
\(\Rightarrow\left(56-x\right)2=34\cdot3=102\)
\(\Rightarrow56-x=102\div2\)
\(\Rightarrow56-x=51\)
\(\Rightarrow x=56-51\)
\(\Rightarrow x=5\)
BI
18 tháng 4 2016
\(56-\frac{x}{34}=\frac{144}{96}\)
\(\Rightarrow\frac{x}{34}=56-\frac{144}{96}\)
\(\Rightarrow\frac{x}{34}=\frac{109}{2}\)
\(\Rightarrow2x=109\cdot34=3706\)
\(\Rightarrow x=3706\div2\)
\(\Rightarrow x=1853\)
NN
Nguyễn Ngọc Anh Minh
CTVHS
VIP
3 tháng 11 2018
a/
\(1\frac{1}{2}x1\frac{1}{3}x1\frac{1}{4}x1\frac{1}{5}x1\frac{1}{6}=\frac{3}{2}x\frac{4}{3}x\frac{5}{4}x\frac{6}{5}x\frac{7}{6}=\frac{7}{2}=3\frac{1}{2}\)
b/
x=0; y=5
DH
17 tháng 5 2021
\(\frac{4}{x}\) \(=\frac{1}{5}\)
Ta có :
\(\frac{4}{x}\) \(=\frac{4}{20}\)
=> \(x=20\)
#Ninh Nguyễn
7 tháng 6 2018
\(x(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{132}=\) \(5\frac{1}{2}\)
\(x\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{11\cdot12}\right)=\frac{11}{2}\)
\(x\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{11}-\frac{1}{12}\right)=\frac{11}{2}\)
\(x\left(1-\frac{1}{12}\right)=\frac{11}{2}\)
\(x\cdot\frac{11}{12}=\frac{11}{2}\)
\(x=\frac{11}{2}:\frac{11}{12}\)
\(x=6\)
Vậy x = 6
7 tháng 6 2018
\(\frac{x}{2}+\frac{x}{6}+\frac{x}{12}+\frac{x}{20}+...+\frac{x}{132}=5\frac{1}{2}\)
\(\Rightarrow x\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{132}\right)=\frac{11}{2}\)
\(\Rightarrow x\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{11.12}\right)=\frac{11}{2}\)
\(\Rightarrow x\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{11}-\frac{1}{12}=\frac{11}{2}\right)\)
\(\Rightarrow x\left(1-\frac{1}{12}\right)=\frac{11}{2}\)
\(\Rightarrow x.\frac{11}{12}=\frac{11}{12}\)
\(\Rightarrow x=\frac{11}{12}:\frac{11}{12}=1\)
Vậy x = 1
\(\frac{56-x}{34}=\frac{144}{96}\)
\(=\frac{56-x}{34}=\frac{3}{2}\)
\(=\frac{56-x}{34}=\frac{51}{34}\)
\(\Rightarrow56-x=51\)
\(=-x=51-56\)
\(\Rightarrow x=5\)
x bang 2