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\(2\left(x-1\right)+3\left(3x-2\right)=x-4\)
\(2x-2+9x-6=x-4\)
\(2x+9x-x-2-6=-4\)
\(10x-2-6=-4\)
\(10x-2=2\)
\(10x=4\)
\(x=\frac{2}{5}\)
Vậy \(x=\frac{2}{5}\)
\(3\left(4-x\right)-2\left(x-1\right)=x+20\)
\(12-3x-2x+2=x+20\)
\(12-5x+2=x+20\)
\(12-5x-x+2=20\)
\(12-6x+2=20\)
\(12-6x=18\)
\(6x=-6\)
\(x=-1\)
Vậy \(x=-1.\)
\(4\left(2x+7\right)-3\left(3x-2\right)=24\)
\(8x+28-9x+6=24\)
\(8x-9x+28+6=24\)
\(-x+34=24\)
\(-x=-10\)
\(x=10\)
Vậy \(x=10\)
\(3\left(x-2\right)+2x=10\)
\(3x-6+2x=10\)
\(3x+2x-6=10\)
\(5x=16\)
\(x=\frac{16}{5}\)
Vậy \(x=\frac{16}{5}\)
2(x-1)+3(3x-2)=x-4
=>2x-2=9x-6-x+4=0
=>10x-4=0
=>x=\(\frac{2}{5}\)
c) 135 - | 9 - x | = 3
| 9 - x | = 135 - 3
| 9 - x | = 132
=> 9 - x = 132
x = 9 - 132
x = 123
hoặc 9 - x = - 132
x = 9 - ( - 132 )
x = 9 + 132
x = 141
Vậy ..................
c) 135 - | 9 - x | = 35
\(2\left(x-1\right)+3\left(x-2\right)=x-4\)
\(2x-2+3x-6=x-4\)
\(5x-8=x-4\)
\(5x-8-x+4=0\)
\(4x-4=0\)
\(4x=4\)
\(x=1\)
\(3\left(4-x\right)-2\left(x-1\right)=x+20\)
\(12-x-2x+2=x+20\)
\(14-3x=x+20\)
\(14-3x-x-20=0\)
\(-6-4x=0\)
\(4x=-6\)
\(x=-\frac{3}{2}\)
\(\left|2x+3\right|=5\)
\(\Rightarrow\orbr{\begin{cases}2x=2\\2x=-8\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=-4\end{cases}}}\)
\(x:2-4=3\)
\(x:2=3+4\)
\(x:2=7\)
\(x=7\cdot2\)
\(x=14\)
\(\left(x+1\right):x=2\)
\(x+1=2x\)
\(x=1\)
\(5\left(x-3\right)-4\left(x-1\right)=20\)
\(2x-15-4x+4=20\)
\(2x-4x=20+15-4\)
\(-2x=31\)
\(x=31:\left(-2\right)\)
\(x=-\frac{31}{2}\)
a) Ta có: \(\left(x-\frac{1}{3}\right)^2-\frac{1}{4}=0\)
\(\Rightarrow\left(x-\frac{1}{2}\right)^2=\frac{1}{4}\)
\(\Rightarrow x-\frac{1}{2}=\frac{1}{2}\Rightarrow x=1\)
hoặc \(x-\frac{1}{2}=-\frac{1}{2}\Rightarrow x=-\frac{1}{2}+\frac{1}{2}=0\)
Vậy \(x\in\left\{1;0\right\}\)
b)\(20\%.x+\frac{2}{5}x=x-4\)
\(\Rightarrow\frac{1}{5}x+\frac{2}{5}x-x=-4\)
\(\Rightarrow\frac{-2}{5}x=-4\)
\(\Rightarrow x=-4:\left(-\frac{2}{5}\right)=10\)
Vậy x=10
c) 3(x+1)+4(x+3)-2(x+16) = 18
=> 3x+3+4x+12-2x-32 =18
=> (3x+4x-2x)+(3+12-32)=18
=> 5x - 17 = 18
=> 5x = 18 + 17 = 35
=> x = 35 : 5 = 7
Vậy x = 7
Tìm x biết: 3. (4 – x) – 2. ( x- 1) = x + 20
12 - 3x - 2x + 2 = x + 20
-5x + 14 = x + 20
-5x + 14 - x - 20 =0
-6x - 6 = 0
-6x = 6
x = -1
\(3\left(4-x\right)-2\left(x-1\right)=x+20\)
\(\Leftrightarrow12-3x-2x+2=x+20\)
\(\Leftrightarrow14-5x=x+20\)
\(\Leftrightarrow14-20=x+5x\)
\(\Leftrightarrow-6=6x\)
\(\Leftrightarrow x=-6\div6\)
\(\Leftrightarrow x=-1\)
\(3.\left(4-x\right)-2.\left(x-1\right)=x+20\)
\(12-3x-2x+2=x+20\)
\(-3x-2x-x=20-12-2\)
\(-6x=6\)
\(x=-1\)