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\(5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(5^{x+3}\left(5-3\right)=2.5^{11}\)
\(5^{x+3}.2=2.5^{11}\)
\(5^{x+3}=5^{11}\)
\(x+3=11\)
\(x=8\)
\(4^{x+3}-3.4^{x+1}=13.4^{11}\)
\(4^{x+1}\left(4^2-3\right)=13.4^{11}\)
\(4^{x+1}.13=13.4^{11}\)
\(4^{x+1}=4^{11}\)
\(x+1=11\)
\(x=10\)
\(5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(5^{x+3}.5-3.5^{x+3}=2.5^{11}\)
\(5^{x+3}.\left(5-3\right)-2.5^{11}=0\)
\(5^{x+3}.2-2.5^{11}=0\)
\(2\left(5^{x+3}-5^{11}\right)=0\)
\(\Rightarrow5^{x+3}-5^{11}=0\)
\(\Rightarrow5^{x+3}=5^{11}\)
\(\Rightarrow x+3=11\)
\(\Rightarrow x=8\)
vậy \(x=8\)
sai đề rồi bạn oi 5x+4-3.5x+3=0 mà sao mà bằng 2.511được
\(5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(\Rightarrow5^{x+3}\left(5-3\right)=2.5^{11}\)
\(\Rightarrow5^{x+3}=5^{11}\)
\(\Rightarrow x+3=11\)
\(\Rightarrow x=8\)
\(5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(\Rightarrow5^x.5^4-3.5^x.5^3=2.5^{11}\)
\(\Rightarrow5^x.5^3\left(5-3\right)=2.5^{11}\)
\(\Rightarrow5^x.2=2.5^8\)
\(\Rightarrow5^x=5^8\)
\(\Rightarrow x=8\)
Vậy \(x=8\)
\(5^{x+3}(5-3)=2.5^{11}\)
<=>\(2.5^{x+3}=2.5^{11}\)
<=>\(5^{x+3}=5^{11}\)
<=>x+3=11
<=>x=8
a) Tìm \(n\in N\), biết:
\(3.5^{2n+1}-3.25^n=300\)
b) Tìm x để:
\(f\left(x\right)=6x^{^{ }4}-2x^3+5=5\)
a)\(3\cdot5^{2n+1}-3\cdot25^n=300\)
\(3\cdot5^{2n}\cdot5-3\cdot25^n=300\)
\(15\cdot25^n-3\cdot25^n=300\)
\(25^n\cdot12=300\)
\(25^n=25\)
\(\Rightarrow n=1\)
b)\(f\left(x\right)=6x^4-2x^3+5=5\)
\(6x^4-2x^3=0\)
\(6x^4=2x^3\)
\(3x^4=x^3\)
\(3x^4-x^3=0\)
\(x^3\left(3x-1\right)=0\)
\(\Rightarrow x^3=0\) hoặc 3x-1=0
\(\Rightarrow x=0,3x=1\)
\(\Rightarrow x=0,x=\frac{1}{3}\)(loại vì \(x\in N\))
Vậy x=0
Bài làm
a) 64 . 4x = 168
=> 43 . 4x = ( 42 )8
=> 43 . 4x = 416
=> 43+x = 416
=> 3 + x = 16
=> x = 13
Vậy x = 13
b) x10 = 1x
Ta có: x10 = 1x
<=> x = 1
Hay 110 = 11
=> 1 = 1
Vậy x = 1
c) ( 7x - 11 )3 = 25 . 52 + 200
=> ( 7x - 11 )3 = 32 . 25 + 200
=> ( 7x - 11 )3 = 1000
=> ( 7x - 11 )3 = 103
=> 7x - 11 = 10
=> 7x = 21
=> x = 3
Vậy x = 3
# Học tốt #