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\(x^2-x\left(x+2\right)=6\)
\(\Leftrightarrow x^2-x^2-2x=6\)
<=> -2x = 6
<=> x = -3
\(3x\left(x-2\right)+2x\left(2-x\right)=x^2-8\)
\(\Leftrightarrow3x\left(x-2\right)-2x\left(x-2\right)=x^2-8\)
\(\Leftrightarrow\left(x-2\right)\left(3x-2x\right)=x^2-8\)
\(\Leftrightarrow\left(x-2\right)x=x^2-8\)
\(\Leftrightarrow x^2-2x=x^2-8\)
\(\Leftrightarrow2x=8\)
<=> x = 4
a/ \(x^2-x\left(x+2\right)=6\)
<=> \(x^2-x^2-2x=6\)
<=> \(-2x=6\)
<=> \(x=-3\)
b/ \(3x\left(x-2\right)+2x\left(2-x\right)=x^2-8\)
<=> \(3x^2-6x+4x-2x^2=x^2-8\)
<=> \(3x^2-2x-2x^2-x^2+8=0\)
<=> \(-2x+8=0\)
<=> \(-2x=-8\)
<=> \(x=4\)
c/ \(3\left(5x-1\right)-x\left(x+1\right)+x^2=14\)
<=> \(15x-3-x^2-x+x^2=14\)
<=> \(14x-3=14\)
<=> \(-3=14-14x\)
<=> \(14\left(1-x\right)=-3\)
<=> \(1-x=\frac{-3}{14}\)
<=> \(-x=\frac{-3}{14}-1\)
<=> \(x=\frac{3}{14}+1\)
<=> \(x=\frac{17}{14}\)
Tuyet Anh Nguyen
1.a)(3x-2)(4x+5)=0
12x^2+7x-10=0>>x1=2/3,x2=-5/4
b)4x^3+2x^2+4x+2=0>>x=-1
c)0,23x^2-4,21x-13,8=0>>x1=21,14,x2=-2,8...
d)10x^3-13x^2-178x-35=0>>x1=5,x2=-1/5
b2/a)2x^3+5x^2-3x=0>>x1=1/2,x2=-3
b)(3x-1)(x^2-7x+12)=0>>x1=1/3,x2=4,x3=...
b3/
a)x^2+x-2=0>>x1=1,x2=-2
b)x1=-1,x2=-6
b4/a)0,5x^2-1,5x-1,5x^2+x+4,5x-3=0>>-x...
b)3x/7-1=3x/7-x>>x=1
c)2x^2-13x+15=0>>x1=5,x2=3/2
P/s: Tham khảo nha
x(x+1)(x-6)-x3 = 5x
<=>(x2+x)(x-6)-x3=5x
<=>x3-6x2+x2-6x-x3=5x
<=>-5x2-6x=5x
<=>-5x2-6x-5x=0
<=>-5x2-11x=0
<=>-x.(5x-11)=0
<=>x=0 hoặc 5x-11=0
<=>x=0 hoặc x=11/5
1/ (x+1)(-3)+5(x-4)=-3
\(\Leftrightarrow\)-3x - 3 + 5x - 20= -3
\(\Leftrightarrow\)2x - 23=-3
\(\Leftrightarrow\)x=10
2/3(5x-1) -x (x+1)+x2=14
\(\Leftrightarrow\)15x - 3 - x2 -x + x2=14
\(\Leftrightarrow\)14x=17
\(\Leftrightarrow\)x=17/14
3/2(x-1)-x(3-x)=x2
\(\Leftrightarrow\)2x - 2 - 3x + x2=x2
\(\Leftrightarrow\)2x-3x+x2-x2=2
\(\Leftrightarrow\)x= -2
4/ 3x(x+5)-2(x+5)=3x2
\(\Leftrightarrow\)3x2 + 15x - 2x - 10=3x2
\(\Leftrightarrow\)13x = 10
\(\Leftrightarrow\)x=10/13
5/ 4x(x+2)+x(4-x)=3x2+12
\(\Leftrightarrow\)4x2 + 8x + 4x - x2 = 3x2 + 12
\(\Leftrightarrow\)12x=12
\(\Leftrightarrow\)x=1
làm bừa thui,ai tích mình mình tích lại
Số số hạng là :
Có số cặp là :
50 : 2 = 25 ( cặp )
Mỗi cặp có giá trị là :
99 - 97 = 2
Tổng dãy trên là :
25 x 2 = 50
Đáp số : 50
a) \(f\left(x\right)=x^3+2x^2+x+2=0\)
\(\Leftrightarrow\)\(\left(x+2\right)\left(x^2+1\right)=0\)
\(\Leftrightarrow\)\(x+2=0\)
\(\Leftrightarrow\)\(x=-2\)
Vậy...
b) \(g\left(x\right)=\left(x-1\right)x^2+\left(x-1\right)x+4x+4=0\)
\(\Leftrightarrow\)\(x\left(x-1\right)\left(x+1\right)+4\left(x+1\right)=0\)
\(\Leftrightarrow\)\(\left(x+1\right)\left(x^2-x+4\right)=0\)
\(\Leftrightarrow\)\(x+1=0\)
\(\Leftrightarrow\)\(x=-1\)
Vậy...
c) \(h\left(x\right)=x^4-x^3+5x^2-5x=0\)
\(\Leftrightarrow\)\(x\left(x-1\right)\left(x^2+5\right)=0\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
Vậy...
Tim x, bt:
a) 4.(18- 5x) - 12.( 3x-7) =15.(2x-16) - 6.(x+14)
b) 5.(3x+5) - 4.(2x-3) =5x + 3x(2x-12) +1
a) 4.(18- 5x) - 12.( 3x-7) =15.(2x-16) - 6.(x+14)
72 - 20x - 36x + 84 = 30x - 240 - 6x - 84
-20x - 36x - 30x + 6x = -240 - 84 - 72 -84
-80x = -480
x= 6
4.(18 - 5x) - 12.(3x - 7) = 15.(2x - 16) - 6.(x+14)
4.18 - 4.5x - 12.3x + 12.7 = 15.2x - 15.16 - 6x - 6.14
72 - 20x - 36x + 84 = 30x - 240 - 6x - 84
72 + 84 - 20x - 36x = 30x - 6x - 240 - 84
156 - 56x = 24x - 324
156 = 24x - 324 + 56x
156 = 80x - 324
80x - 324 = 156
80x = 156 + 324
80x = 480
x = 480:80
x = 6
câu b giải tương tự
Bài làm :
a) x( 2x - 7 ) - 4x + 14 = 0
<=> x( 2x - 7 ) - 2( 2x - 7 ) = 0
<=> ( 2x - 7 )( x - 2 ) = 0
\(\Leftrightarrow\orbr{\begin{cases}2x-7=0\\x-2=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{7}{2}\\x=2\end{cases}}\)
b) Sửa đề : 5x3 + x2 - 4x + 9 = 0
<=>( 5x3 + 5 ) + (x2 - 4x +4)=0
<=> 5(x3 + 1) + (x-2)2 = 0
<=> 5(x+1)(x2 - x +1) + (x+2)2 =0
\(\Leftrightarrow\orbr{\begin{cases}x=-1\\x=-2\end{cases}}\)
c) 3x3 - 7x2 + 6x - 14 = 0
<=> 3x2( x - 7/3 ) + 6( x - 7/3 ) = 0
<=> ( x - 7/3 )( 3x2 + 6 ) = 0
\(\Leftrightarrow\orbr{\begin{cases}x-\frac{7}{3}=0\\3x^2+6=0\end{cases}}\Leftrightarrow x=\frac{7}{3}\)
d) 5x2 - 5x = 3( x - 1 )
<=> 5x( x - 1 ) - 3( x - 1 ) = 0
<=> ( x - 1 )( 5x - 3 ) = 0
\(\Leftrightarrow\orbr{\begin{cases}x-1=0\\5x-3=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=1\\x=\frac{3}{5}\end{cases}}\)
e) 4x2 - 25 - ( 4x - 10 ) = 0
<=> ( 2x - 5 )( 2x + 5 ) - 2( 2x - 5 ) = 0
<=> ( 2x - 5 )( 2x + 5 - 2 ) = 0
<=> ( 2x - 5 )( 2x + 3 ) = 0
\(\Leftrightarrow\orbr{\begin{cases}2x-5=0\\2x+3=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{5}{2}\\x=-\frac{3}{2}\end{cases}}\)
f) x3 + 27 + ( x + 3 )( x - 9 ) = 0
<=> ( x + 3 )( x2 - 3x + 9 ) + ( x + 3 )( x - 9 ) = 0
<=> ( x + 3 )( x2 - 3x + 9 + x - 9 ) = 0
<=> ( x + 3 )( x2 - 2x ) = 0
<=> x( x + 3 )( x - 2 ) = 0
\(\Leftrightarrow\orbr{\begin{cases}\\\end{cases}}\begin{cases}x=0\\x=-3\\x=2\end{cases}\)
\(3\left(5x-1\right)-x\left(x+1\right)+x^2=14\)
\(\Leftrightarrow15x-3-x^2-x+x^2=14\)
\(\Leftrightarrow\left(x^2-x^2\right)+\left(15x-x\right)-3=14\)
\(\Leftrightarrow14x=17\)
\(\Leftrightarrow x=\frac{17}{14}\)
Vậy \(x=\frac{17}{14}\)
3(5x - 1) - x(x+1)+x 2 = 14
➡️15x - 3 - x 2 - x + x 2 = 14
➡️(15x - x ) + ( -x 2 + x 2 ) - 3= 14
➡️14x -3 = 14
➡️14x = 14+3
➡️14x = 17
➡️x = 17/14
Hok tốt~