Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a, ( -18 + 25 ) - ( 125 - 18 + 25 )
= -18+25-125+18-25
= (-18+18) +(25-25) -125
= 0+0-125
= -125
b, 45 . ( 18 - 15 ) -18 . ( 45 + 45 )
= 45.18 - 45.15 -18.45 +18.45
= 45(18-15-18+18)
= 45.3=135
a ) = -18 + 25 - 125 + 18 - 25
= (-18 + 18 ) - ( 25 -25 ) + 125
= 0 - 0 + 125
=125
a, ( -18 + 25 ) - ( 125 - 18 + 25 )
= -18 + 25 + 125 + 18 - 25
= [(-18) + 18] + (25 - 25) + 125
= 0 + 0 + 125
= 125
b, 45 . ( 18 - 15 ) - 18 . ( 45 + 45 )
= 45 . 18 - 45 . 15 - 18 . 45 - 18 . 45
= (45 . 18 - 18 . 45) - (45 . 15 - 18 . 45)
= 0 - 45 . (15 - 18)
= 0 - 45 . -3
= 0 - (-135)
= 135
a,[(-18)+(-17)+10]-(-18)
=-18-17+10+18
=(-18+18)+(-17+10)
=0-7
=-7
b,(-11+14).(-3+7)
=-11.(-3)+(-11).7+14.(-3)+14.7
=33+(-77)+(-42)+98
=(33+98)+[-77+(-42)]
=131-119
=12
c,45.(-10)+3.15.(-2)+2.45
=45.[(-10)+3.(-2)+2]
=45.-14
=-630
a) \(\text{ }\left[\left(-18\right)+\left(-17\right)+10\right]-\left(-18\right)\)
\(=\text{ }\left[\left(-18\right)+\left(-17\right)+10\right]+18\)
\(=\left(-18\right)+\left(-17\right)+10+18\)
\(=\text{ }\left[\left(-18\right)+18\right]+\text{ }\left[\left(-17\right)+10\right]\)
\(=0+\left(-7\right)\)
\(=-7\)
a)\(\frac{-5}{18}+\frac{32}{45}-\frac{9}{10}\)
\(=\frac{-25}{90}+\frac{64}{90}-\frac{81}{90}\)
\(=-\frac{42}{90}=-\frac{7}{15}\)
b)\(\frac{3}{4}-\left(-\frac{5}{8}\right)+\frac{9}{4}-\frac{3}{16}\)
\(=\frac{3}{4}+\frac{5}{8}+\frac{9}{4}-\frac{3}{16}\)
\(=\frac{12}{16}+\frac{10}{16}+\frac{36}{16}-\frac{3}{16}\)
\(=\frac{58}{16}=\frac{29}{8}\)
c) \(\frac{11}{125}-\frac{17}{18}-\frac{5}{7}+\frac{4}{9}+\frac{17}{14}=\frac{11}{125}\)
d) \(\frac{-2}{5}-\frac{3}{10}-\left(-\frac{1}{2}\right)\)
\(=-\frac{2}{5}-\frac{3}{10}+\frac{1}{2}\)
\(=-\frac{4}{10}-\frac{3}{10}+\frac{5}{10}\)
\(=-\frac{2}{10}=-\frac{1}{5}\)
Bài 3 .
a.25.(-70).2.(-4)
=[25.(-4)].[(-70).2]
=(-100).(-140)
=14000
b.16.(12-6)-12.(16-6)
=(16.12-16.6)-(12.16-12.6)
=16.12-16.6-12.16+12.6
=(16.12-12.16)-(16.6-12.6)
=0-6.(16-12)
=0-24=-24
c.125.(-24)+24.255
=24.[(-125)+255]
=24.100
=2400
d)25.(-55)+(-25).45
=25.[(-55)+(-45)]
=25.(-100)
=-2500
Bài 4
a.3x+18=3
3x =3-18
3x =-15
x =-15:3
x =-5
Vậy x=-5
b)\(4\left|x\right|=16\)
\(\left|x\right|\)=16:4
\(\left|x\right|\)=4
⇒\(\left[{}\begin{matrix}x=-4\\x=4\end{matrix}\right.\)
Vậy x∈{-4;4}
3)a)=(25.2).[(-70).(-4)]
=50.(-280)
=-14000
b)=16.6-12.10
=96-120
=-24
c)=-3000+6120
=3120
d)=1375+-1125
=250
4)a) 3x=3-18
3x=-15
x=-15:3
x=-5
b) \x\=16:4
\x\=4
suy ra x=4;-4
= ( -25) x 1 +72 x (-25) + (-25) x27
= (- 25) x ( 1 + 72 + 27 )
= (-25) x 100
=-2500
b
c 37 x ( 25 + 37 ) - 27 x ( 37 + 25 )
= 37 x 25 + 37 x 37 -27x37 -27x25
= ( 37 x25 -27x25 )+(37x37-27+37)
=25 x ( 37 -27 ) + 37 x (37 - 27)
= 25 x10 + 37x10
= 250 + 370
= 770
a) =-25.( 1+72+27)
=-25.100= - 2500
b) = -36.45 + (-36) . 15 - (-36) . 40
= - 36. ( 45+15-40)
= -36 . 20= -720
c) =37.62 - 27 .62
= 62. ( 37 - 27 )
= 62 . 10
= 620
Câu 1:
a) 25-(30+x) = x-(27-8)
25-30-x = x-19
-5-x = x-19
(-5)+19 = x+x
14 = 2x
x = 7
Vậy x = 7
b) (x-12)-15 = (20-7)-(18+x)
x-12-15 = 13-18-x
x-(12+15)= -5-x
x-27 = -5-x
x+x = -5+27
2x = 22
x = 11
Câu 2:
a) 4573+46-4573+35-16-5
= (4573-4573)+(46-16)+(35-5)
= 0+30+30
= 60
b) 32+34+36+38-10-12-14-16-18
= (32-12)+(34-14)+(36-16)+(38-18)-10
= 10+10+10+10-10
= 30
1, a) 25 - (30 + x) = x - (27 - 8)
25 - 30 - x = x - 27 + 8
-x - x = -27 + 8 - 25 + 30
-2x = -14
x = -14 : (-2)
x = 7
b) (x - 12) - 15 = (20 - 7) - (18 + x)
x - 12 - 15 = 20 - 7 - 18 - x
x + x = 20 - 7 - 18 + 12 + 15
2x = 22
x = 22 : 2
x = 11
2, a) 4573 + 46 - 4573 + 35 - 16 - 5
= (4573 - 4573) + (46 - 16) + (35 - 5)
= 0 + 30 + 30
= 60
b) 32 + 34 + 36 + 38 - 10 - 12 - 14 - 16 - 18
= (32 - 10) + (34 - 12) + (36 - 14) + (38 - 16) - 18
= 22 + 22 + 22 + 22 - 18
= 22 x 4 - 18
= 88 - 18
= 70
phần đầu sai đề
(-18+25)-(125-18+25)
=-18 + 25 -125 + 18 - 25
= -18 +25 +(-125) +18 + (-25)
= [(-18)+18] + [25 +(-25)] + (-125)
= 0 + 0 + (-125)
= -125
Bài 1:
\(10-|x-3|=16\)
\(\Rightarrow|x-3|=-6\)
Mà Ix-3I >= 0 với mọi x
Mà -6<0 => PT vô nghiệm