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TBR, Ta có:
(100 – 4x) + 120 : 23 = 1 + 42
\(\Rightarrow\) 10 – 4x + 15 = 17
= 25 – 4x = 17 \(\Rightarrow\) 4x = 25 – 17 \(\Rightarrow\) 4x = 25 – 17
\(\Rightarrow\) 4x = 8 \(\Rightarrow\)x = 8 : 4 = 2
\(\left(10-4x\right)+120:2^3=1+4^2\)
\(\Rightarrow\) \(\left(10-4x\right)+120:8=17\)
\(\Rightarrow\) \(\left(10-4x\right)+15=17\)
\(\Rightarrow\) \(10-4x=2\)
\(\Rightarrow\) \(4x=8\)
\(\Rightarrow\) \(x=2\)
Tìm x, biết:
a) 198 - ( x + 4 ) = 120
(x+4) = 198-120
x+ 4 =78
x= 78 - 4
x= 74
b) 2(x-51) = 2.23 + 20
2(x-51)=36
x-51 = 36:2
x-51=18
x=18+51
x=69
c) 450 : ( x - 19 ) = 50
x-19= 450:50
x-19=9
x=9+19
x=28
d)4(x-3) = 72 - 110
4(x-3) =48
x-3 = 48:4
x-3=12
x=12+3
x=15
a) 198 - ( x + 4 ) = 120
=>x+4=78
=>x=744
b) 2(x-51) = 2.23 + 20
=>
1. a) 17.85 + 15.17 - 120
= 17.( 85 + 15) - 120
= 17. 100 -120
= 1700 - 120
= 1580
b) 20 - [ 30 - (5 - 1)2 ]
= 20 - [ 30 - 42 ]
= 20 - [ 30 - 16 ]
= 20 - 14
= 6
2. a) 70 - 5.(x - 3) = 45
5.(x - 3) = 70 - 45
5.(x -3) = 25
x - 3 = 25 : 5
x - 3 = 5
x = 5 + 3
x = 8
b) 10 + 2.x = 45 : 43
10 + 2.x = 42
10 + 2.x = 16
2.x = 16 - 10
2.x = 6
x = 6 : 2
x =3
1)a:17.85+15.17-120=17.(85+15)-120=17.100-120=1700-120=1580
b: 20-[30-(5-1)^2 = 20-[30-4^2]=20-(30-16)=20-15=5
2)
a: 70-5(x-3)=45
5(x-3) = 70-45=25
x-3 = 25:5=5
x= 5+3=8
b: 10+2x = 4^5:4^3
10+2x = 4^2
10+2x = 16
2x = 16-10=6
x = 6:2=3
1, 4\(^{x+1}\) + 4\(^0\) = 65
\(\Rightarrow\)4\(^{x+1}\) = 65 - 1
\(\Rightarrow\)x + 1 = 64 : 4
\(\Rightarrow\)x + 1 = 16
\(\Rightarrow\)x = 15
2) 10 + 2x = 16\(^{^2}\): 4\(^3\)
\(\Rightarrow\)10 + 2x = 4
\(\Rightarrow\)2x = 4 - 10
\(\Rightarrow\)2x = -6
\(\Rightarrow\)x = -3
Ta có:
10 - 4x + 120:23 = 1 + 42
=> 10 - 4x + 15 = 1 + 16
=> 4x - 5 = 17
=> 4x = 17 + 5 = 22
=> x = 22/4
Vậy: x = 22/4
\(\left(10-4x\right)+120:2^3=1+4^2\)
\(\Rightarrow\left(10-4x\right)+120:8=1+16\)
\(\Rightarrow\left(10-4x\right)+15=17\)
\(\Rightarrow\left(10-4x\right)=17-15=2\)
\(\Rightarrow4x=10-2=8\)
\(\Rightarrow x=8:4=2\)