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29.19 -29.13-19.29+19.13=(29.19-19.29)+13.(19-29)=0+13.(-10)=-130. Tìm x +2 =1 => x=1-2=-1
a. x50 = x60
=> x =\(\pm\) 1 hoặc x=0
b.3.5x +15 = 192 + 29
3.5x = 192 +19-15
3.5x =361 +4
3.5x = 365
5x = 121,(6)
Ko có giá trị cho x
1,7-(18+x)=-15
<=>18+x=7+15
<=>18+x=22
<=>x=4
2,(x-17)-(-3)=0
<=>x-17+3=0
<=>x-17=-3
,<=>x=14
<=>
1,
7 - ( 18 + x ) = - 15
18 + x = 7 + 15
18 + x = 22
x = 22 - 18
x = 4
2,
( x - 17 ) - ( - 3 ) = 0
( x - 17 ) + 3 = 0
x - 17 = - 3
x = -3 + 17
x = 14
3, -18 - ( x - 6 ) = 0
-18 = x- 6
x = - 18 + 6
x = - 12
4, 29 - ( 10 + 29 ) = x - ( 27 - 9 )
-10 = x - 18
x = - 10 + 18
x = 8
\(\left(2008-x\right):29+32=100\)
\(\Leftrightarrow\left(2008-x\right):29=68\)
\(\Leftrightarrow2008-x=1972\)
\(\Leftrightarrow x=36\)
(Tíck cho mìk vs nhá!)
( 2008 - x ) : 29 + 32 = 100
( 2008 - x ) : 29 = 100 - 32
( 2008 - x ) : 29 = 68
2008 - x = 68 x 29
2008 - x = 1972
x = 2008 - 1972
x = 36
Vậy x = 36
\(a,0,5x-\frac{2}{3}x=\frac{7}{12}\Rightarrow\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow x\left(\frac{1}{2}-\frac{2}{3}\right)=\frac{7}{12}\Rightarrow x\cdot\left(\frac{3}{6}-\frac{4}{6}\right)=\frac{7}{12}\)
\(\Rightarrow x\cdot\left(-1\right)=\frac{7}{12}\Rightarrow x=\frac{7}{12}:\left(-1\right)=\frac{7}{-12}\)
\(c,\frac{\left(x-5\right)}{12}\cdot\frac{9}{29}=\frac{-6}{29}\Rightarrow\frac{\left(x-5\right)}{12}=\frac{-6}{29}:\frac{9}{26}\)
\(\frac{\Rightarrow\left(x-5\right)}{12}=\frac{-6}{9}=\frac{-2}{3}\Rightarrow x-5=-\frac{2}{3}\cdot12\)
\(\Rightarrow x-5=\frac{-24}{3}=-8\Rightarrow x=-8+5=-3\)
\(a,0,5x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow-\frac{1}{6}x=\frac{7}{12}\)
\(\Rightarrow x=-\frac{7}{2}\)
\(c,\frac{x-5}{12}\cdot\frac{9}{29}=-\frac{6}{29}\)
\(\Rightarrow\frac{x-5}{12}=-\frac{2}{3}\)
\(\Rightarrow x-5=12.\left(-\frac{2}{3}\right)\)
\(\Rightarrow x-5=-8\)
\(\Rightarrow x=-3\)
(29-x)(29+x)=-60
29-x=-60
x=-29-(-60)
x=.........
(29+x)=-60
x=-60-29
x=.............