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\(a,0,5x-\frac{2}{3}x=\frac{7}{12}\Rightarrow\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow x\left(\frac{1}{2}-\frac{2}{3}\right)=\frac{7}{12}\Rightarrow x\cdot\left(\frac{3}{6}-\frac{4}{6}\right)=\frac{7}{12}\)
\(\Rightarrow x\cdot\left(-1\right)=\frac{7}{12}\Rightarrow x=\frac{7}{12}:\left(-1\right)=\frac{7}{-12}\)
\(c,\frac{\left(x-5\right)}{12}\cdot\frac{9}{29}=\frac{-6}{29}\Rightarrow\frac{\left(x-5\right)}{12}=\frac{-6}{29}:\frac{9}{26}\)
\(\frac{\Rightarrow\left(x-5\right)}{12}=\frac{-6}{9}=\frac{-2}{3}\Rightarrow x-5=-\frac{2}{3}\cdot12\)
\(\Rightarrow x-5=\frac{-24}{3}=-8\Rightarrow x=-8+5=-3\)
\(a,0,5x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow-\frac{1}{6}x=\frac{7}{12}\)
\(\Rightarrow x=-\frac{7}{2}\)
\(c,\frac{x-5}{12}\cdot\frac{9}{29}=-\frac{6}{29}\)
\(\Rightarrow\frac{x-5}{12}=-\frac{2}{3}\)
\(\Rightarrow x-5=12.\left(-\frac{2}{3}\right)\)
\(\Rightarrow x-5=-8\)
\(\Rightarrow x=-3\)
a, \(0,5x-\frac{2}{3}x=\frac{7}{12}\)
=> \(x\left(0,5-\frac{2}{3}\right)=\frac{7}{12}\)
=>\(\frac{-1}{6}x=\frac{7}{12}\)=> \(x=\frac{7}{12}:\frac{-1}{6}=\frac{-7}{2}\)
b, \(x:\frac{13}{3}=-2,5\)
=>\(x=\left(-2,5\right):\frac{13}{3}=\frac{-7,5}{13}\)
c, \(5,5x=\frac{13}{15}\)
=>\(x=\frac{13}{15}:5,5=\frac{13}{82,5}\)
d, \(\left(\frac{3x}{7}+1\right):\left(-4\right)=\frac{-1}{28}\)
=>\(\left(\frac{3x}{7}+1\right)=\frac{-1}{28}:\left(-4\right)=\frac{1}{7}\)
=>\(\frac{3x}{7}=\frac{1}{7}-1=\frac{-6}{7}\)
=>\(3x=-6\)
=> \(x=\left(-6\right):3=-3\)
a: =>1/2x-2/3x=7/12
=>-1/6x=7/12
hay x=-7/2
b: \(\Leftrightarrow x=-\dfrac{5}{2}\cdot\dfrac{13}{3}=\dfrac{-65}{6}\)
c: =>x=13/15:11/2=26/165
d: =>3/7x+1=1/7
=>3/7x=-6/7
hay x=-2
x. (0,5-2/3)= 5/12
x. -1/6= 5/12
x= 5/12 : -1/6
x= -5/2
0,5x-2/3x=7/12
=>(1/2-2/3).x=7/12
=>-1/6x=7/12
=>x=7/12:1/6
=>x=7/2
b, x:4 1/3=-2,5
=>x:13/3=-2,5
=>x=-5/2x13/3
=>x=-13
c,5,5x=13/15
=>11/2x=13/15
=>x=13/15:11/2
=>x=26/165
d,(3x/7+1):-4=-1/28
=>3x/7+1=-1/28x(-4)
=>3x/7+1=-1/7
=>3x/7=-1/7-1
=>3x/7=-8/7
=>3x=-8/7x7
=>3x=8
=>x=8:3
=>x=8/3
\(0,5x-\frac{2}{3}x=\frac{7}{12}\)
\(\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(\left(\frac{1}{2}-\frac{2}{3}\right)x=\frac{7}{12}\)
\(\frac{-1}{6}x=\frac{7}{12}\)
\(x=-21\)
b,c,d tương tự
\(0,5x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow x\left(0,5-\frac{2}{3}\right)=\frac{7}{12}\)
\(\Rightarrow-\frac{1}{6}x=\frac{7}{12}\)
\(\Rightarrow x=-\frac{7}{2}=-3,5\)
Tớ không biết xin lỗi cậu nhé
dễ mà bn, ta sử dụng tính chất phân phối của phép trừ đối với phép nhân:
0,5=\(\frac{1}{2}\)
\(\frac{1}{2}\)x - \(\frac{2}{3}\)x = \(\frac{7}{12}\)
x ( \(\frac{1}{2}\)- \(\frac{2}{3}\)) = \(\frac{7}{12}\)
x . \(\frac{-1}{6}\)= \(\frac{7}{12}\)
x = \(\frac{7}{12}\): \(\frac{-1}{6}\)
x = \(\frac{7}{12}\). -6
x = \(-3\frac{1}{2}\)
( like cho mk lunk ha, bài này dễ, kiểm tra lại ha! Nếu mk làm sai thì còn sửa nữa!!!!!!!!!)