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x:6=24+6
x:6=30
x=30 x 6
x=180
23+x:2=37
x:2=37-23
x:2=14
x=14 x 2
x=28
214-136:x=197
136:x=214-197
136:x=17
x=136:17
x=8
(x-4):6:5=10
(x-4):6=10 x 5=50
(x-4)=50 x 6
x-4=300
x=300+4=304
(x+1)+(x+2)+...+(x+10)=755
10x + (1+2+...+10)=755
10x + (1+10) x [(10-1):1+1]:2=755
10x + 55 = 755
10x=755-55
10x=700
x=700:10=70
chúc bạn học tốt nha
Sửa đề \(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=\frac{2015}{2016}\)
\(\Leftrightarrow\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+..+\frac{2}{x\left(x+1\right)}=\frac{2015}{2016}\)
\(\Leftrightarrow\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+..+\frac{2}{x\left(x+1\right)}=\frac{2015}{2016}\)
\(\Leftrightarrow2\cdot\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x}-\frac{1}{x+1}\right)=\frac{2015}{2016}\)
\(\Leftrightarrow\frac{1}{2}-\frac{1}{x+1}=\frac{2015}{2016}\div2\)
\(\Leftrightarrow\frac{1}{2}-\frac{1}{x+1}=\frac{2015}{4032}\)
\(\Leftrightarrow\frac{1}{x+1}=\frac{1}{2}-\frac{2015}{4032}\Leftrightarrow\frac{1}{x+1}=\frac{1}{4032}\)
\(\Leftrightarrow x+1=4032\Rightarrow x=4031\)
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+...+\left(x+\frac{1}{512}\right)=1\)
\(9x+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{512}\right)=1\)
\(9x+\left[\left(1-\frac{1}{2}\right)+\left(\frac{1}{2}-\frac{1}{4}\right)+\left(\frac{1}{4}-\frac{1}{8}\right)+....+\left(\frac{1}{256}-\frac{1}{512}\right)\right]=1\)
\(9x+\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+...+\frac{1}{512}\right)=1\)
\(9x+\left(1-\frac{1}{512}\right)=1\)
\(9x+\frac{511}{512}=1\)
\(9x=1-\frac{511}{512}\)
\(9x=\frac{1}{512}\)
\(\Rightarrow x=\frac{1}{512}\div9=\frac{1}{4608}\)
a,
x.2/7.3/4=5/21
x.3/14=5/21
x=5/21:3/14
x=10/9
b,
x.1/2=1/3
x=1/3:1/2
x=2/3
c,
x:4/5=25/8:5/4
x:4/5=5/2
x=5/2.4/5=2
A, x= 5/25 : 3/4 : 2/7 = 14/15
B, x=1/3 : 1/2 = 2/3
C, x=(25/8 : 5/4)x4/5 = 5/2 x 4/5 = 2
x = 45
**** tớ nha bui phi hùng