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a) (27+65)+(346-27-65)
= 27+65+346-27-65
= (27-27)+(65-65)+346
= 0 + 0 + 346
= 346
b) (42-69+17)-(42+17)
= 42-69+17 – 42 – 17
= (42-42)+(17-17)-69
= 0 + 0 – 69
= -69
a)(27+65)+(346-27-65)
=27+65+345-27-65
=(27-27)+(65-65)+346
=0+0+346
=346
b) (42-69+17)-(42+17)
=42-69+17-42-17
=(42-42)-69+(17-17)
=0-69+0
=-69
a)=27+65+346-27-65
=(27-27)+(65-65)+346
=0+0+346
=346
b)=42+69-17-42+17-35
=(42-42)+(17-17)+(69-35)
=0+0+34
=34
Thực hiện phép tính:
( 42 - 69 + 17 ) - ( 42 + 17)
= 42 - 69 + 17 - 42 + 17
= ( 42 - 42) - ( 17 - 17 ) - 69
= 0 - 0 - 69
= - 69
Ủng hộ nha! :)
( 42 - 69 + 17 ) - ( 42 + 17 )
= 42 - 69 + 17 - 42 - 17
= 42 - 42 + 17 - 17 - 69
= 0 + 0 - 69
= - 69
a,\(25-\left(-75\right)+32-\left(32+75\right)\))
=\(25+75+32-32-75\)
=\(\left(75-75\right)+\left(32-32\right)+25\)
=\(0+0+25=25\)
\(b,\left|-127\right|-18.\left(5-6\right)\)
\(=127-18.\left(-1\right)\)
\(=127-\left(-18\right)\)
\(=145\)
\(c,17-25+55-17\)
\(=\left(17-17\right)+\left(55-25\right)\)
\(=0+30\)
\(=30\)
a)
25 - (-75) + 32 - ( 32 + 75 )
= 25 + 75 + 32 - 107
=100+32 - 107
=132 - 107
=25
a) 2011 + 5[300 - (17 - 7)2 ]
= 2011 + 5[300 - 100]
= 2011 + 5.200
= 2011 + 1000
= 3011
b) 695 - [200 + (11 - 1)2 ]
= 695 - [200 + 100]
= 695 - 300
= 395
c) 129 - 5[29 - (6-1)2 ]
= 129 - 5[29 - 25]
= 129 - 5 . 4
= 129 - 20
= 109
d) 2345 - 1000 : [19 - 2(21-18)2 ]
= 2345 - 1000 : [19 - 2 . 9]
= 2345 - 1000 : 1
= 2345 - 1000
= 1345
a, 2011+5 [300-(17-7)2 ] =2011+5[300-102]
=2011+5[300-100]=2011+5.200
=2011+1000=3011
b, 695-[200+(11-1)2]=695-[200+102]
=695-[200+100]=695-300=395
\(\left\{\left[3^{14}.69+12.3^{14}\right]:3^{16}-7\right\}:2^4\)
\(=\left\{\left[3^{14}.\left(69+12\right)\right]:3^{16}-7\right\}:16\)
\(=\left\{\left[3^{14}.81\right]:3^{16}-7\right\}:16\)
\(=\left\{\left[3^{14}.3^4\right]:3^{16}-7\right\}:16\)
\(=\left\{3^{18}:3^{16}-7\right\}:16\)
\(=\left\{3^2-7\right\}:16\)
\(=\left\{9-7\right\}:16\)
\(=2:16\)
\(=\frac{1}{8}\)
a,\(\frac{5}{3}.\frac{3}{7}+\frac{5}{3}.\frac{5}{7}-\frac{5}{3}\)
=\(\frac{5}{3}.\left(\frac{3}{7}+\frac{5}{7}\right)-\frac{5}{3}\)
= \(\frac{5}{21}\)
a, \(3^6:3^3+2^3.2^2\\ =3^3+2^5=27+32=59\)
b, \(\left(39.42-37.42\right):42\\ =42.\left(39-37\right):42\\ =39-37=2\)
a, 36 : 32 + 23 . 22 = 34 + 25 = 81 + 32 = 113
b, ( 39.42 - 37.42 ) : 42
= 42. ( 39 - 37 ) : 42
= 42 . 2 : 42
= 84 : 42
= 2
nhầm = -69
\(\left(42-69+17\right)-\left(42+17\right)=42-69+17-42-17=-69\)