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a) = 2 * x^5 - x^4 - 7 / 2x^2
b) = 15x^5 - 12x^4 + 18x^2 - 5/4 x^4 + x^3 - 3/2 x = 15 x^5 - 53/4x^4 + x^3 + 18 x^2 - 3/2x
mk đang bị âm bạn jup mk nha
) \(\dfrac{x^3+8y^3}{2y+x}\)
\(=\dfrac{x^3+\left(2y\right)^3}{x+2y}\)
\(=\dfrac{\left(x+2y\right)\left[x^2+x.2y+\left(2y\right)^2\right]}{x+2y}\)
\(=x^2+2xy+4y^2\)
b) \(\dfrac{a-1}{2\left(a-4\right)}+\dfrac{a}{a-4}\) MTC: \(2\left(a-4\right)\)
\(=\dfrac{a-1}{2\left(a-4\right)}+\dfrac{2a}{2\left(a-4\right)}\)
\(=\dfrac{a-1+2a}{2\left(a-4\right)}\)
\(=\dfrac{3a-1}{2\left(a-4\right)}\)
c) \(\dfrac{x^3+3x^2y+3xy^2+y^3}{2x+2y}\)
\(=\dfrac{\left(x+y\right)^3}{2\left(x+y\right)}\)
\(=\dfrac{\left(x+y\right)^2}{2}\)
d) \(\left(x-5\right)^2+\left(7-x\right)\left(x+2\right)\)
\(=\left(x^2-2.x.5+5^2\right)+\left(7x+14-x^2-2x\right)\)
\(=x^2-10x+25+7x+14-x^2-2x\)
\(=39-5x\)
e) \(\dfrac{3x}{x-2}-\dfrac{2x+1}{2-x}\)
\(=\dfrac{3x}{x-2}+\dfrac{2x+1}{x-2}\)
\(=\dfrac{3x+2x+1}{x-2}\)
\(=\dfrac{5x+1}{x-2}\)
h) \(\dfrac{1}{3x-2}-\dfrac{1}{3x+2}-\dfrac{3x+6}{4-9x^2}\)
\(=\dfrac{1}{3x-2}-\dfrac{1}{3x+2}+\dfrac{3x+6}{9x^2-4}\)
\(=\dfrac{1}{3x-2}-\dfrac{1}{3x+2}+\dfrac{3x+6}{\left(3x-2\right)\left(3x+2\right)}\) MTC: \(\left(3x-2\right)\left(3x+2\right)\)
\(=\dfrac{3x+2}{\left(3x-2\right)\left(3x+2\right)}-\dfrac{3x-2}{\left(3x-2\right)\left(3x+2\right)}+\dfrac{3x+6}{\left(3x-2\right)\left(3x+2\right)}\)
\(=\dfrac{\left(3x+2\right)-\left(3x-2\right)+\left(3x+6\right)}{\left(3x-2\right)\left(3x+2\right)}\)
\(=\dfrac{3x+2-3x+2+3x+6}{\left(3x-2\right)\left(3x+2\right)}\)
\(=\dfrac{3x+10}{\left(3x-2\right)\left(3x+2\right)}\)
b) \(=y^3-1+\frac{2}{3}x^3y-2xy+\frac{1}{3}x^2y^3-y^3\)
\(=\frac{2}{3}x^3y+\frac{1}{3}x^2y^3-2xy-1\)
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Bài 1:
a: \(x^2\left(3x+2\right)=3x^3+2x^2\)
b: \(\left(x-2\right)\left(3x^2-4x+1\right)\)
\(=3x^3-4x^2+x-6x^2+8x-2\)
\(=3x^2-10x^2+9x-2\)
c: \(\left(3x+2\right)\left(9x^2-6x+4\right)-\left(x-3\right)\left(x+3\right)\)
\(=27x^3+8-x^2+9=27x^3-x^2+17\)
d: \(=\left(x+y-x-y+z\right)\left(x+y+x+y-z\right)\)
\(=z\left(2x+2y-z\right)\)
\(=2xz+2yz-z^2\)
a) = -18x^4*y^4 + 3x^3*y^3 - 6/5x^2*y^4
b) = x^4 + 6x^3 + 9x^2 + 9x^2 - 6x^3 -18x^2 = x^4
bn dùng phương pháp nhân đơn thức vs đa thức đó dễ mà!!!!
chúc bạn học tốt!! ^^
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