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a,\(\frac{7}{10}\cdot\frac{4}{9}+\frac{3}{10}\cdot\frac{4}{9}-1\frac{7}{9}\)
\(=\frac{14}{45}+\frac{2}{15}-\frac{16}{9}\)
\(=\frac{14}{45}+\frac{6}{45}-\frac{80}{45}\)
\(=\frac{-60}{45}=\frac{-4}{3}\)
b,\(\frac{-5}{6}+\frac{4}{9}\cdot\left(\frac{5}{4}-\frac{2}{3}\right)\cdot\left(-3\right)^2+\frac{5}{9}\cdot30\%\)
\(=\frac{-5}{6}+\frac{4}{9}\cdot\left(\frac{7}{12}\right)\cdot9+\frac{5}{9}\cdot\frac{3}{10}\)
\(=\frac{-5}{6}+\frac{7}{3}+\frac{1}{6}\)
\(=\frac{-5}{6}+\frac{14}{6}+\frac{1}{6}\)
=\(=\frac{10}{6}=\frac{5}{3}\)
= (1-2) + (3-4) +..... +(2017- 2018)
= (-1) + (-1) +.... + (-1) (1004 lần)
= -1004
1 - 2 + 3 - 4 +...+ 2017 - 2018 có 2018 số
= (1 - 2) + (3 - 4) + ..+ (2017 - 2018) có 2018 : 2 = 1009 cặp
= -1 + (-1) +...+ (-1) có 1009 số -1
= (-1).1009
= -1009
\(\frac{0,5+\frac{2}{43}-\frac{2}{2017}}{\frac{3}{4}+\frac{3}{43}-\frac{3}{2017}}:\frac{\frac{4}{91}+\frac{4}{34}+\frac{4}{2017}}{\frac{5}{91}+\frac{5}{34}+\frac{5}{2017}}\)
\(=\frac{\frac{2}{4}+\frac{2}{43}-\frac{2}{2017}}{\frac{3}{4}+\frac{3}{43}-\frac{3}{2017}}:\frac{4\left(\frac{1}{91}+\frac{1}{34}+\frac{1}{2017}\right)}{5\left(\frac{1}{91}+\frac{1}{34}+\frac{1}{2017}\right)}\)
\(=\frac{2\left(\frac{1}{4}+\frac{1}{43}-\frac{1}{2017}\right)}{3\left(\frac{1}{4}+\frac{1}{43}-\frac{1}{2017}\right)}:\frac{4}{5}\)
\(=\frac{2}{3}.\frac{5}{4}=\frac{5}{6}\)
a, 13/6+5/8 : -3/4 - 7/12.4
= 13/6 + -5/6-7/3
=8/6-7/3
= -6/6
= -1
b, ( 73/5 - 21/3) + ( 4/3-43/5 )
= 73/5-21/3+4/3-43/5
=( 73/5-43/5)-(21/3-4/3)
= 6-17/3
=1/3
c, 7/5.4/9 +7/5: 9/16- 14/10.2/9
= 7/5.4/9 +7/5.16/9 - 14/45
=7/5.(4/9+16/9)-14/45
=7/5.20/9-14/45
= 140/45 - 14/45
= 126/45
Xong rùi nè! Nhưng bạn kiểm tra lại giùm nhé vì làm vào ban đêm nên hơi bất tiện
\(\left(13\frac{4}{9}+2\frac{1}{9}\right)-3\frac{4}{9}\)
\(=\left(\frac{121}{9}+\frac{19}{9}\right)-\frac{31}{9}\)
\(=\frac{140}{9}-\frac{31}{9}\)
\(=\frac{109}{9}\)
\(1,25\div\frac{15}{20}+\left(25\%-\frac{5}{6}\right)\div4\frac{2}{3}\)
\(=1,25\div\frac{3}{4}+\left(\frac{25}{100}-\frac{5}{6}\right)\div\frac{14}{3}\)
\(=1,25\times\frac{4}{3}+\left(\frac{6}{24}-\frac{20}{24}\right)\div\frac{14}{3}\)
\(=\frac{5}{3}+\frac{-14}{24}\times\frac{14}{3}\)
\(=\frac{60}{36}+\frac{-98}{36}\)
\(=\frac{-38}{36}=\frac{-19}{18}\)
\(D=1-4+4^2-4^3+4^4-...+4^{2016}-4^{2017}\) (sửa \(2^{2017}\) thành \(4^{2017}\))
\(\Rightarrow D=\left(1-4\right)+4^2\left(1-4\right)+4^4\left(1-4\right)-...+4^{2016}\left(1-4\right)\)
\(\Rightarrow D=\left(-3\right)+4^2.\left(-3\right)+4^4.\left(-3\right)-...+4^{2016}.\left(-3\right)\)
\(\Rightarrow D=\left(-3\right)\left(1+4^2+4^4+...+4^{2016}\right)\)
\(\Rightarrow4D=\left(-3\right)\left(4+4^3+4^5+...+4^{2017}\right)\)
\(\Rightarrow4D+D=\left(-3\right)\left(1+4+4^2+4^3+4^4+...+4^{2016}+4^{2017}\right)\)
\(\Rightarrow5D=\left(-3\right)\dfrac{4^{2017+1}-1}{4-1}\)
\(\Rightarrow D=\left(-3\right)\dfrac{4^{2018}-1}{3.5}\)
\(\Rightarrow D=\left(-1\right)\dfrac{4^{2018}-1}{5}=\dfrac{1-4^{2018}}{5}\)