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Ta có:
\(12:\left\{390:\left[500-\left(5^3+7^2.5\right)\right]\right\}\)
\(=12:\left\{390:\left[500-125-245\right]\right\}\)
\(=12:\left(390:130\right)\)
\(=12:3=4\)
a, 6^2 : 4 . 3 + 2 . 5^2
= 36 : 12 + 2 . 25
= 4 + 50
= 54
b, 5 . 4^2 - 18 : 3^2
= 5 . 16 - 18 : 9
= 80 - 2
= 78
a) \(6^2:4\cdot3+2\cdot5^2\)
\(=36:4\cdot3+2\cdot25\)
\(=9\cdot3+2\cdot25\)
\(=27+50\)
\(=77\)
\(77=7\cdot11\)
b) \(5\cdot4^2-18:3^2\)
\(=5\cdot16-18:9\)
\(=80-2\)
\(=78\)
\(78=2\cdot3\cdot13\)
a) 43.27 - 43.23
= 43.(27-23)
= 43.4
= 44
b) 35.77+23.35+53.23
= 35.(77+23) + (5.2)3
= 35.100 + 103
= 35.102+ 102.10
= 102.(35+10)
= 100.45
= 4500
c) 32.5 + 23.10 - 81 : 3
= 9.5 + 8.2.5 - 27
= 5.(9+8.2) - 27
= 5.25 - 27
= 53 - 27
= 98
d) 151-291:288+13.3
= 151 - 23+3
= 151 - 8 + 3
= 146
\(\frac{3}{5}:\frac{7}{3}+\frac{3}{5}:\frac{7}{4}-1\frac{3}{5}\)
\(=\frac{3}{5}.\frac{3}{7}+\frac{3}{5}.\frac{4}{7}-1\frac{3}{5}\)
\(=\frac{3}{5}.\left(\frac{3}{7}+\frac{4}{7}\right)-1\frac{3}{5}\)
\(=\frac{3}{5}.1-1+\frac{3}{5}\)
\(=\frac{3}{5}-\frac{3}{5}-1\)
\(=-1\)
a) 35 :73 +35 :74 −135
\(=\frac{49}{20}-\frac{8}{5}\)
= \(\frac{17}{20}\)
\(36:\left\{180:\left[2\cdot5^2-\left(5^3-3\cdot5\cdot7\right)\right]\right\}\)
\(=36:\left\{180:\left[2\cdot25-\left(125-15\cdot7\right)\right]\right\}\)
\(=36:\left\{180:\left[50-\left(125-105\right)\right]\right\}\)
\(=36:\left[180:\left(50-20\right)\right]\)
\(=36:\left(180:30\right)\)
\(=36:6\)
\(=6\)
\(=\dfrac{36}{180:\left[2\cdot25-5^3+15\cdot7\right]}=\dfrac{36}{180:30}=\dfrac{36}{6}=6\)
\(4.\left\{3^2.\left[\left(5^2+2^3\right):11\right]-26\right\}+2009\)
\(=4.\left\{9.\left[\left(25^{ }+8\right):11\right]-26\right\}+2009\)
\(=4.\left\{9.\left[33:11\right]-26\right\}+2009\)
\(=4.\left\{9.3-26\right\}+2009\) \(=4.\left(27-26\right)+2009\)
\(=4.1+2009=2013\)
54-2.53
=5.53-2.53
=53.(5-2)
=53.3
=125.3
=375
k nhé!
Thank you ! + 1 k