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1.2.3...2013-1.2.3...2012-1.2.3...20122= (1.2.3...2013-1.2.3...2012) - 1.2.3...20122 = [1.2.3...2012(2013-1)] - 1.2.3...20122 = 1.2.3...2012.2012 - 1.2.3...20122 = 1.2.3...20122 - 1.2.3...20122 = 0
1 . 2 . 3 . ...... 2012 . ( 2013 - 1 - 2012 )
1 . 2 . 3 ..........2012 . ( 0 ) = 0
b/1.2.3.....2013 - 1.2.3....2012-1.2.3...20122
= (1.2.3...2012.2013-1.2.3...2012)-1.2.3...2012.2012
= 1.2.3...2012(2013-1-2012)
=1.2.3...2012.0=0
a) \(1.2.3....9-1.2.3...8-1.2.3...7.8^2\)
\(=1.2.3....8.\left(9-1-8\right)\)
\(=1.2.3...8.0\)
\(=0\)
1.2.3.......9-1.2.3...8-1.2.3....82
=1.2.3.......9-1.2.3.........8-1.2.3....8.8
= 1.2.3....8(9-1-8)
=1.2.3......8.0
=0
mk làm đk câu b thui àk : (câu b dễ lắm)
b, 1.2.3...2013-1.2.3...2012-1.2.3...20122
=1.2.3...2012(2013-1-2012)
=1.2.3...2012.0
=0