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1.2.3...9 - 1.2.3...8 - 1.2.3...7.82
= 1.2.3....8.9 - 1.2.3....8 - 1.2.3...7.8.8
= (1.2.3...8).9 - (1.2.3...8).1 - (1.2.3....7.8).8
= (1.2.3...8). (9 - 1 - 8) = (1.2.3...8) . 0 = 0
Câu 1 dễ mà :
1.2.3...9 - 1.2.3...8 - 1.2.3...7.82
= 1.2.3...8.9 - 1.2.3...8.1 - 1.2.3...7.8.8
= 1.2.3...8.( 9 - 1 - 8 )
= 1.2.3...8.0
= 0
=1.2.3.4.5.6.7.8 .(9-1-8)
1.2.3.4.5.6.7.8.0=0
Ủng hộ mk nha
\(D=\frac{30}{1.2.30}+\frac{30}{2.3.4}+\frac{30}{3.4.5}+...+\frac{30}{98.99.100}\)
\(=15.\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{98.99.100}\right)\)
\(=15.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{98.99}-\frac{1}{99.100}\right)\)
\(=15.\left(\frac{1}{1.2}-\frac{1}{99.100}\right)\)
\(=15.\frac{8249}{9900}=\frac{8249}{660}\)
\(D=\frac{30}{1.2.3}+\frac{30}{2.3.4}+\frac{30}{3.4.5}+...+\frac{30}{98.99.100}\)
\(=15\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{98.99.100}\right)\)
\(=15\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{98.99}-\frac{1}{99.100}\right)\)
\(=15\left(\frac{1}{1.2}-\frac{1}{99.100}\right)\)
\(=15.\frac{4949}{9900}=\frac{4949}{660}\)
Vậy \(D=\frac{4949}{660}\).
bang 0 nha