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a, \(\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{524}+1+\frac{x+329}{5}+\frac{20}{5}-4=0\)
\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
=> x+329=0 => x= -329
b. tương tụ
c, x=0, x=4
a) ta có:
\(|2x-6|+5x=9\Leftrightarrow|2x-6|=9-5x\)
\(2x-6=9-5x\Leftrightarrow7x=15\Leftrightarrow x=\frac{15}{7}\)
\(2x-6=5x-9\Leftrightarrow3x=3\Leftrightarrow x=1\)
b) Ta có:
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+329}{5}+4=0\)
\(\Leftrightarrow\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)
do \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\ne0\)nên \(x+329=0\Leftrightarrow x=-329\)
Vậy ............................................. chúc bn hok tốt ^-^
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0.\)
\(1+\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}-4+\frac{x+349}{5}=0\)
\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
\(\left(x+329\right).\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)
\(\Rightarrow x+329=0\)
\(\Rightarrow x=-329\)
Study well
\(\Rightarrow\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}+1+\frac{x+349}{5}-4=0\)
\(\Rightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
\(\Rightarrow\left(x+329\right).\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)
Mà \(\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)\ne0\)
Nên \(x+329=0\Rightarrow x=-329\)
Vậy \(x=-329\)
Chúc bạn học tốt !!!
a, \(13.|x|-\frac{16}{3}=\frac{23}{3}\)
\(\Rightarrow13.|x|=13\)
\(\Rightarrow|x|=1\)
\(\Rightarrow x=\left(-1;1\right)\)
\(b,19-\left(|x|+1\right)=18\)
\(\Rightarrow|x|+1=1\)
\(\Rightarrow|x|=0\)
\(\Rightarrow x=0\)
\(c,|x|=5-x\)
\(Th1:x>0\)
\(\Rightarrow x=5-x\)
\(\Rightarrow x+x=5\)
\(\Rightarrow2x=5\)
\(\Rightarrow x=\frac{5}{2}\)
\(Th2:x< 0\)
\(\Rightarrow-x=5-x\)
\(\Rightarrow-x+x=5\)VN
\(a,13.|x|-\frac{16}{3}=\frac{23}{3}\)
\(13.|x|=13\)
TH1:\(13.x=13\)
x=13:13
x=1
TH2:\(13.x=-13\)
x=-13:13
x=-1
\(b,19-\left(|x|+1\right)=18\)
\(|x|+1=1\)
TH1:x+1=1
x=1-1
x=0
TH2:x+1=-1
x=-1+1
x=0
(lạ thật )
\(c,|x|=5-x\)
TH1=>x=5-x
=>x-x=5
=>x=5
TH2:-x=5-x
-x+x=5
Làm theo ý tưởng
a, Lời giải
TH1 : 13.x=13
x=13:13
x=1
13.x=-13
x=-13:13
x=-1
mấy câu kia tương tự
a. gia tri nho nhat cua M la 0 khi x= -15/19
b. gia tri nho nhat cua N la 1/2
tu tinh x
\(\frac{x+115}{15}+\frac{x+119}{19}=\frac{x+217}{117}+\frac{x+327}{227}\)
\(\Leftrightarrow\left(\frac{x+115}{15}-1\right)+\left(\frac{x+119}{19}-1\right)=\left(\frac{x+217}{117}-1\right)+\left(\frac{x+327}{227}-1\right)\)
\(\Leftrightarrow\frac{x+100}{15}+\frac{x+100}{19}=\frac{x+100}{117}+\frac{x+100}{227}\)
\(\Leftrightarrow\frac{x+100}{15}+\frac{x+100}{19}-\frac{x+100}{117}-\frac{x+100}{227}=0\)
\(\Leftrightarrow\left(x+100\right)\left(\frac{1}{15}+\frac{1}{19}-\frac{1}{117}-\frac{1}{227}\right)=0\)
\(\Leftrightarrow x+100=0\)
\(\Leftrightarrow x=-100\)