K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

15 tháng 7 2019

\(\frac{x+115}{15}+\frac{x+119}{19}=\frac{x+217}{117}+\frac{x+327}{227}\)

\(\Leftrightarrow\left(\frac{x+115}{15}-1\right)+\left(\frac{x+119}{19}-1\right)=\left(\frac{x+217}{117}-1\right)+\left(\frac{x+327}{227}-1\right)\)

\(\Leftrightarrow\frac{x+100}{15}+\frac{x+100}{19}=\frac{x+100}{117}+\frac{x+100}{227}\)

\(\Leftrightarrow\frac{x+100}{15}+\frac{x+100}{19}-\frac{x+100}{117}-\frac{x+100}{227}=0\)

\(\Leftrightarrow\left(x+100\right)\left(\frac{1}{15}+\frac{1}{19}-\frac{1}{117}-\frac{1}{227}\right)=0\)

\(\Leftrightarrow x+100=0\)

\(\Leftrightarrow x=-100\)

5 tháng 11 2015

a, \(\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{524}+1+\frac{x+329}{5}+\frac{20}{5}-4=0\)

\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)

=> x+329=0  => x= -329

b. tương tụ

c,  x=0, x=4

30 tháng 11 2018

a) ta có:

 \(|2x-6|+5x=9\Leftrightarrow|2x-6|=9-5x\)

\(2x-6=9-5x\Leftrightarrow7x=15\Leftrightarrow x=\frac{15}{7}\)

\(2x-6=5x-9\Leftrightarrow3x=3\Leftrightarrow x=1\)

b) Ta có:

\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+329}{5}+4=0\)

\(\Leftrightarrow\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)

do \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\ne0\)nên \(x+329=0\Leftrightarrow x=-329\)

Vậy ............................................. chúc bn hok tốt ^-^

\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0.\)

\(1+\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}-4+\frac{x+349}{5}=0\)

\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)

\(\left(x+329\right).\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)

\(\Rightarrow x+329=0\)

\(\Rightarrow x=-329\)

Study well 

25 tháng 8 2019

\(\Rightarrow\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}+1+\frac{x+349}{5}-4=0\)

\(\Rightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)

\(\Rightarrow\left(x+329\right).\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)

Mà \(\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)\ne0\)

Nên \(x+329=0\Rightarrow x=-329\)

Vậy \(x=-329\)

Chúc bạn học tốt !!!

a, \(13.|x|-\frac{16}{3}=\frac{23}{3}\)

\(\Rightarrow13.|x|=13\)

\(\Rightarrow|x|=1\)

\(\Rightarrow x=\left(-1;1\right)\)

\(b,19-\left(|x|+1\right)=18\)

\(\Rightarrow|x|+1=1\)

\(\Rightarrow|x|=0\)

\(\Rightarrow x=0\)

\(c,|x|=5-x\)

\(Th1:x>0\)

\(\Rightarrow x=5-x\)

\(\Rightarrow x+x=5\)

\(\Rightarrow2x=5\)

\(\Rightarrow x=\frac{5}{2}\)

\(Th2:x< 0\)

\(\Rightarrow-x=5-x\)

\(\Rightarrow-x+x=5\)VN 

\(a,13.|x|-\frac{16}{3}=\frac{23}{3}\)

\(13.|x|=13\)

TH1:\(13.x=13\)

x=13:13

x=1

TH2:\(13.x=-13\)

x=-13:13

x=-1

\(b,19-\left(|x|+1\right)=18\)

\(|x|+1=1\)

TH1:x+1=1

x=1-1

x=0

TH2:x+1=-1

x=-1+1

x=0

(lạ thật )

\(c,|x|=5-x\)

TH1=>x=5-x

=>x-x=5

=>x=5

TH2:-x=5-x

-x+x=5

Làm theo ý tưởng 

7 tháng 7 2019

a, Lời giải

TH1 : 13.x=13

x=13:13

x=1

13.x=-13

x=-13:13

x=-1

mấy câu kia tương tự 

11 tháng 1 2016

a. gia tri nho nhat cua M la 0 khi x= -15/19

b. gia tri nho nhat cua N la 1/2 

tu tinh x