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\(A=5+8+...+302\)
\(=\frac{\left(5+302\right)\left[\left(302-5\right):3+1\right]}{2}\)
\(=\frac{30700}{2}=15350\)
\(B=7+11+15+...+203\)
\(=\frac{\left(7+203\right)\left[\left(203-7\right):4+1\right]}{2}\)
\(=\frac{10500}{2}=5250\)
M=8/3.2/5.3/8.10.19/92
=(8/3.3/8).(2/5.10).19/92
=1.4.19/2
=4.19/92
=19/23
N=5/7.5/11+5/7.2/11-5/7.14/11
=5/7.(5/11+2/11-14/11)
=5/7. -7/11= -5/11
Q=(1/99+12/999 +123/9999).(1/2-1/3-1/6)
=(1/99+12/999+123/9999).(3/6+ -2/6+ -1/6)
=(1/99+12/999+123/9999). 0
=0
\(\frac{-7}{11}.\frac{11}{19}+\frac{-7}{11}.\frac{8}{19}+\frac{-4}{11}\)
\(=\frac{-7}{11}.\left(\frac{11}{19}+\frac{8}{19}\right)+\frac{-4}{11}\)
\(=\frac{-7}{11}.1+\frac{-4}{11}\)
\(=\frac{-7}{11}+\frac{-4}{11}=\frac{-11}{11}=-1\)
~ Hok tốt ~
Đặt \(B=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{2018.2019}\)
\(\Rightarrow B=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2018}-\frac{1}{2019}\)
\(\Rightarrow B=1-\frac{1}{2019}\)
\(\Rightarrow B=\frac{2018}{2019}\)
*tính nhanh
=1*27*25*3+27*25-25*11
=25*(1*27*3+27-11)
=25*97=2425
mình chỉ làm được ý thôi nhá
it's so hard
\(\frac{3}{11}\times\frac{7}{19}+\frac{3}{11}\times\frac{8}{19}-\frac{4}{9}:\frac{11}{3}\)
\(=\frac{3}{11}\times\frac{7}{9}+\frac{3}{11}\times\frac{8}{9}-\frac{4}{9}\times\frac{3}{11}\)
\(=\frac{3}{11}\times\left(\frac{7}{9}+\frac{8}{9}-\frac{4}{9}\right)\)
\(=\frac{3}{11}\times\frac{11}{9}\)
\(=\frac{1}{2}\)