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a) \(4^x=2^{x+1}\)
\(2^{2x}=2^{x+1}\)
\(\Rightarrow2x=x+1\)
\(\Rightarrow2x-x=1\)
\(\Rightarrow x=1\)
b) \(16=\left(x-1\right)^4\)
\(2^4=\left(x-1\right)^4\)
\(\Rightarrow x-1=2\)
\(\Rightarrow x=3\)
c) \(x^{10}=1^x\)
\(x^{10}=1\)
\(x^{10}=1^{10}\)
\(\Rightarrow x=1\)
d) \(x^{10}=x\)
\(x^{10}-x=0\)
\(x\left(x^9-1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x^9-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}}\)
e) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\left(2x-15\right)^5-\left(2x-15\right)^3=0\)
\(\left(2x-15\right)^3\left[\left(2x-15\right)^2-1\right]=0\)
\(\Rightarrow\orbr{\begin{cases}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x-15=0\\2x-15=\pm1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{15}{2}\\x=\left\{8;7\right\}\end{cases}}\)
\(A,4^X=2^{X+1}\)
\(\left(2^2\right)^X=2^{X+1}\)
\(\Rightarrow2^{2X}=2^{X+1}\)
\(\Rightarrow2X=X+1\)
\(\Rightarrow2X-X=1\Leftrightarrow X=1\)
\(B,16=\left(x-1\right)^4\)
\(\Rightarrow x-1=\hept{\begin{cases}2\\-2\end{cases}}\)
\(\Rightarrow x=\hept{\begin{cases}3\\-1\end{cases}}\)
1/
a. \(x^3-2=25\)
\(x^3=25+2\)
\(x^3=27\)
\(\Rightarrow x=3\)
b.\(\left(x-3\right)^2=25\)
\(\left(x-3\right)^2=5^2\)
\(\Rightarrow x-3=5\)
\(\Rightarrow x=8\)
1,a, x^3-2=25 b, (x-3)^2=25 c, x^3-x^2=55 d,[(8.x-12):4].3^7=3^10
x^3=27 (x-3)^2=5^2 không có giá trị x (8.x-12):4=3^3
x^3=3^3 x-3=5 8.x-12=108
x=3 x=8 8.x=120
x=15
2, a, \(7^6:7^4+3^4.3^2-3^7:3\) b, 1736-(21-16).32+6.7^2 c,56.17+17.44-4^3.5+6.(3^2-2)
=\(7^2+3^6-3^6\) =1736-5.32+6.49 =17.(56+44)-320+42
=\(49\) =1736-160+294 =17.10-278
=1736+134 =170-278
=1870 =-108
d, 3.10^2-[1200-(4^2-2.3)^3]
=300-[1200-(16-6)^3]
=300-(1200-10^3)
=300-(1200-1000)
=300-200
=100
V )x+(x+1)+(x+2)+....+(x+30)=1240
31 . x + (1 + 2 + 3 + 4 +...+ 29 + 30) = 1240
31 . x + 31.15 = 1240
31 . x = 1240 - 31.15
31 . x = 775
x = 775 : 31
x = 25
b) 230 và 320
Ta có :
230 = ( 23 )10 = 810
320 = ( 32 )10 = 910
Vì 8 < 9 Nên 230 < 320
c) 1020 và 9010
Ta có :
1020 = ( 102 )10 = 10010
Vì 10010 > 9010
Nên 1020 > 9010
a) \(\left(x-2\right).\left(2x-1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-2=0\\2x-1=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=2\\2x=1\end{cases}}\Rightarrow\orbr{\begin{cases}x=2\\x=\frac{1}{2}\end{cases}}\)
b) \(\left(3x+9\right).\left(1-3x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}3x+9=0\\1-3x=0\end{cases}}\Rightarrow\orbr{\begin{cases}3x=-9\\3x=1\end{cases}\Rightarrow}\orbr{\begin{cases}x=-3\\x=\frac{1}{3}\end{cases}}\)
c) (31 - 2x)3 =27
(31 - 2x)3 = 33
=> 31 - 2x = 3
2x = 31 - 3
2x = 28
x = 14
a. \(\left(x-2\right).\left(2x-1\right)=0\Leftrightarrow\orbr{\begin{cases}x-2=0\\2x-1=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=\frac{1}{2}\end{cases}}}\)
Vậy \(x=2\)hoặc \(x=\frac{1}{2}\)
b.\(\left(3x+9\right).\left(1-3x\right)=0\Leftrightarrow\orbr{\begin{cases}3x+9=0\\1-3x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-3\\x=\frac{1}{3}\end{cases}}}\)
Vậy \(x=-3\)hoặc \(x=\frac{1}{3}\)
c.\(\left(31-2x\right)^3=-27\)
\(\Leftrightarrow\left(31-2x\right)^3=\left(-3\right)^3\)
\(\Leftrightarrow31-2x=-3\)
\(2x=34\)
\(x=17\)
d.\(\left(x-2\right).\left(7-x\right)=0\Leftrightarrow\orbr{\begin{cases}x-2=0\\7-x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=7\end{cases}}}\)
Vậy \(x=2\)hoặc \(x=7\)
e.\(\left(x-5\right)^5=32\)
\(\Leftrightarrow\left(x-5\right)^5=2^5\)
\(\Leftrightarrow x-5=2\Leftrightarrow x=7\)
f.\(\left(2-x\right)^4=81\)
\(\Leftrightarrow\left(2-x\right)^4=3^4\)
\(2-x=3\Leftrightarrow x=-1\)
g.\(\left|x-7\right|< 3\Leftrightarrow-3< x-7< 3\Leftrightarrow4< x< 10\)
\(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\Rightarrow\orbr{\begin{cases}2x-15=1\\2x-15=-1\end{cases}}\)Hoặc 2x - 15 = 0
<=> x = 8 hoặc x = 7 hoặc x = 15/2
Ơ chị k5 mà ạ ?
a) 52 . x = 62 + 82
\(5^2\cdot x=36+64\)
\(5^2\cdot x=100\)
\(x=100\div5^2\)
\(x=100\div25\)
\(x=4\)
b) ( 22 + 42 ) . x + 24 . 5 . x = 102
\(\left(4+16\right)\cdot x+16\cdot5\cdot x=100\)
\(x\cdot\left(20+80\right)=100\)
\(x\cdot100=100\)
\(x=100\div100\)
\(x=1\)
c ) 24 . x = 26
\(x=2^6\div2^4\)
\(x=2^{6-4}\)
\(x=2^2\)
\(x=4\)
d) 33 . x + 23 . x = 102
\(x\cdot\left(23+27\right)=100\)
\(x\cdot50=100\)
\(x=100\div50\)
\(x=2\)
e) 78 . x = 710
\(x=7^{10}\div7^8\)
\(x=7^{10-8}\)
\(x=7^2\)
\(x=49\)
\(3^{2x-4}-x^0=8\)
\(3^{2x-4}=9\)
\(3^{2x-4}=3^3\)
\(\Rightarrow2x-4=3\)
\(2x=7\)
\(x=3,5\)
\(3^{2.x-4}-x^0=8\)
\(3^{2.x}:3^4-1=8\)
\(3^{2.x}:81=8+1\)
\(3^{2.x}:81=9\)
\(3^{2.x}=9.81\)
\(3^{2.x}=729\)
\(3^{2.x}=3^6\)
\(\Rightarrow2.x=6\)
\(\Rightarrow x=6:2=3\)
Vậy x = 3