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a) 16x2(x - y)2 - 10y(y - x)3
= 16x2(y - x)2 - 10y(y - x)3
= 2(y - x)2[8x2 - 5y(y - x)]
= 2(y - x)2(8x2 + 5xy - 5y2)
b) a2 -b2 + 4ab - 9 (sai đề)
a) ax2 - 2bxy + 2bx2 - axy
= ( ax2 - axy ) + ( 2bx2 - 2bxy )
= ax( x - y ) + 2bx( x - y )
= ( x - y )( ax + 2bx )
= x( x - y )( a + 2b )
b) x2 + 2x - 4y2 + 8y - 3 < đã sửa >
= ( x2 + 2x + 1 ) - ( 4y2 - 8y + 4 )
= ( x + 1 )2 - ( 2y - 2 )2
= [ ( x + 1 ) - ( 2y - 2 ) ][ ( x + 1 ) + ( 2y - 2 ) ]
= ( x + 1 - 2y + 2 )( x + 1 + 2y - 2 )
= ( x - 2y + 3 )( x + 2y - 1 )
c) x4 + 5x3 + 20x - 16
= x4 + 5x3 + 4x2 - 4x2 + 20x - 16
= ( x4 + 5x3 - 4x2 ) + ( 4x2 + 20x - 16 )
= x2( x2 + 5x - 4 ) + 4( x2 + 5x - 4 )
= ( x2 + 5x - 4 )( x2 + 4 )
phân tích đa thức thành nhân tử
a/x2(x+1)-2x(x+1)+(x+1)=(x+1)(x^2-2x+1)=(x+1)(x-1)^2
b/a2+b2+2a-2b-2ab=(a^2-ab)+(b^2-ab)+2(a-b)=a(a-b)-b(a-b)+2(a-b)=(a-b)(a-b+2)
c/ 4x2-8x+3=(2x-2)^2-1=(2x-2-1)(2x-2+1)=(2x-3)(2x-1)
d/25-16x2=5^2-(4x)^2=(5-4x)(5+4x)
a) \(x^2-xy+4x-2y+4\)
\(=\left(x^2+4x+4\right)-\left(xy+2y\right)\\ =\left(x+2\right)^2-y.\left(x+2\right)\)
\(=\left(x+2\right).\left(x+2-y\right)\)
b) \(2x^2-5x-3\)
\(=2x^2+x-6x-3\)
\(=\left(2x^2+x\right)-\left(6x+3\right)=x\left(2x+1\right)-3\left(2x+1\right)\)
\(=\left(2x+1\right).\left(x-3\right)\)
c)\(\)
c);d);e) tạm thời tớ chưa nghĩ ra-.-"
tham khả tạm 2 câu ạ, chúc học tốt'.'
1.a) 2x4-4x3+2x2
=2x2(x2-2x+1)
=2x2(x-1)2
b) 2x2-2xy+5x-5y
=2x(x-y)+5(x-y)
=(2x+5)(x-y)
2.
a) 4x(x-3)-x+3=0
=>4x(x-3)-(x-3)=0
=>(4x-1)(x-3)=0
=> 2 TH:
*4x-1=0 *x-3=0
=>4x=0+1 =>x=0+3
=>4x=1 =>x=3
=>x=1/4
vậy x=1/4 hoặc x=3
b) (2x-3)^2-(x+1)^2=0
=> (2x-3-x-1).(2x-3+x+1)=0
=>(x-4).(3x-2)=0
=> 2 TH
*x-4=0
=> x=0+4
=> x=4
*3x-2=0
=>3x=0-2
=>3x=-2
=>x=-2/3
vậy x=4 hoặc x=-2/3
a) \(x^2+4x+3\)
\(=x^2+3x+x+3\)
\(=x\left(x+3\right)+\left(x+3\right)\)
\(=\left(x+1\right)\left(x+3\right)\)
\(a,x^3+9x^2+27x+27-27z^3\)
\(=\left(x+3\right)^3-\left(3z\right)^3\)
\(=\left(x+3-3z\right)\left(x^2+6x+9+3xz+9z+9z^2\right)\)
.........
\(b,\)
\(=\left(x+1\right)^2\left(x-3\right)+x\left(x-3\right)\)
\(=\left(x-3\right)\left(x^2+3x+1\right)\)
\(c,\)
\(=x^2\left(x^2+10\right)-2x\left(x^2+10\right)\)
\(=x\left(x-2\right)\left(x+10\right)\)
a) \(x^3-2x^2+x+xy^2\)
\(=x\left(x^2-2x+1+y^2\right)\)
\(=x\left[\left(x-1\right)^2+y^2\right]\)
\(=-x\left[\left(x-1\right)^2-y^2\right]\)
\(=-x\left(x-1+y\right)\left(x-1-y\right)\)
b) \(4x^2+16x+16\)
\(=4\left(x^2+4x+4\right)\)
\(=4\left(x+2\right)^2\)
\(a,x^3+8y^3=\left(x+2y\right)\left(x^2-2xy+4y^2\right)\\ v,x^3-2x^2-x+2=\left(x^3-2x^2\right)-\left(x-2\right)=x^2\left(x-2\right)-\left(x-2\right)=\left(x-2\right)\left(x^2-1\right)=\left(x-1\right)\left(x+1\right)\left(x-2\right)\\ c,25-16x^2=\left(5-4x\right)\left(5+4x\right)\)
\(a,=\left(x+2y\right)\left(x^2-2xy+4y^2\right)\\ b,=x^2\left(x-2\right)-\left(x-2\right)\\ =\left(x-2\right)\left(x^2-1\right)=\left(x-1\right)\left(x-2\right)\left(x+2\right)\\ c,=\left(5-4x\right)\left(5+4x\right)\)