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aa) -(345+96345+96)+(−155+1996−155+1996)
=−345−96−155+1996=−345−96−155+1996
== (−345−155−345−155) - (96−199696−1996)
=−500+1900=−500+1900
=1400=1400
bb) (−456+95−456+95)-(-456+95456+95)-192192
=−456+95+456−95−192=−456+95+456−95−192
== (−456+456−456+456) + (95−9595−95) -192192
=−192=−192
cc) (a−b+ca−b+c)- (c−bc−b)+aa
=a−b+c−c+b+a=a−b+c−c+b+a
== (a+aa+a) + (−b+b−b+b) + (c−cc−c)
=2a=2a
dd)-(a−b+ca−b+c)+(c−bc−b)+aa
=−a+b−c+c−b+a=−a+b−c+c−b+a
== (−a+a−a+a) + (b−bb−b) + (−c+c−c+c)
=0=0
ee) (a−b+ca−b+c)+(c−bc−b)+aa
=a−b+c+c−b+a=a−b+c+c−b+a
== (a+aa+a) + (−b−b−b−b) + (c+cc+c)
=2a−2b+2c
a, =-25.21.4.(-3).(-1)
=-25.4.21.4
=-100.21.4
=-2100.4
=-8400
b, =-125.67.(-8).1
=-125.(-8).67
=1000.67
=67000
c, =35.18-35.28
=35.(18-28)
=35.(-10)
=-350
d, =24.11-16.24+16.5
=24.(11-16)+16.5
=24.(-5)+16.5
=5.(-24+16)
=5.(-8)
=-40
e, =29.6-19.29+19.13
=29.(6-19)+19.13
=29.(-13)+19.13
=13.(-29+19)
=13.(-10)
=-130
1)-(a+b-c)+(a-b-c)=a-b+c+a-b-c=-2b
2)a(b+c)-a(b+d)=a(b+c-b-d)=a(c-d)
3)a(b-c)+a(d+c)=a(b-c+d+c)=a(b+d)
chúc hok tốt :))))))
ak ở câu 1 sửa lại chút
1)-(a+b-c)+(a-b-c)=-a-b+c+a-b-c=-2b
\(A=\left(-8\right).25.\left(-2\right).4.\left(-5\right).125\)
\(=\left(-8\right).\left(-125\right).25.4.\left(-2\right).\left(-5\right)\)
\(=1000.100.10\)
\(=1000000\)
Vay \(A=1000000\)
\(B=19.25+9.25+19.50\)
\(=25.\left(19+9\right)+19.50\)
\(=25.28+19.50\)
\(=50.14+19.50\)
\(=50.\left(14+19\right)\)
\(=50.33\)
\(=1650\)
Vay \(B=1650\)
a) Ta co :
\(\left(a+b\right)\left(a-b\right)=a^2-ab+ab-b^2=a^2-b^2\)
\(\RightarrowĐPCM\)
b) Ta co :
\(a^2+2ab+b^2=a\left(a+b\right)+b\left(a+b\right)=\left(a+b\right)\left(a+b\right)=\left(a+b\right)^2\)
\(\RightarrowĐPCM\)
c) Ta co :
\(\left(x+1\right)\left(y+1\right)=xy+x+y+1\)
\(\RightarrowĐPCM\)
d) Ta có :
\(\left(a-b\right)-\left(c-d\right)=a-b-c+d=\left(a+d\right)-\left(b+c\right)\)
\(\RightarrowĐPCM\)
a, x - a = 2
==>x=a+2
b, x+b=4
==>x=4-b
c, a-x=21
==>x=a-21
d, 14-x=b+9
==>x=14-b-9=5-b
mk k chắc là đúng đâu
Làm mẫu 1 phần ko hiểu thì bảo mình làm típ
a) Ta có: \(\left(x+3\right)^2\ge0;\forall x\)
\(\left(x+3\right)^2-2\ge0-2;\forall x\)
Hay \(A\ge-2;\forall x\)
Dấu "=" xảy ra \(\Leftrightarrow\left(x+3\right)^2=0\)
\(\Leftrightarrow x=-3\)
VẬY MIN A=-2 \(\Leftrightarrow x=-3\)