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bài 4 tìm X biết
a)(X-36):18=12
X-36= 12*18
X-36= 216
X= 216 + 36
X= 252
b)5X-3-2 . 52 =52 . 3
5X-3 = 52 . 3 + 2 . 52
5X-3 = 52 . ( 3+2)
5X-3 = 52 . 5
5X-3 = 52 . 5\(^1\)
5X-3 = 5\(^3\)
=> X-3=3
X= 3+3
X=6
c)X . (X - 3)=0
\(\rightarrow\) \(\orbr{\begin{cases}x=0\\x-3=0\end{cases}}\)
\(\rightarrow\orbr{\begin{cases}x=0\\x=3\end{cases}}\)
D)3X+1-32=2 .32
3X+1 = 2 .32 + 32
3X+1 = 2 .32 + 32 .1
3X+1 = 32 . ( 2+1)
3X+1 = 32 .3
3X+1 = 32 .3\(^1\)
3X+1 = 3\(^3\)
=> X+1= 3
X= 3+1
X= 4
Bài 1:
a) \(x^{10}=1^x\Rightarrow\orbr{\begin{cases}x=1\\x=10\end{cases}}\)
b) \(x^{10}=x\Rightarrow x=1\)
c) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\left(2x-15\right)^5.\left(2x-15\right)^3=\left(2x-15\right)^3\)
\(\left(2x-15\right)^2=1\Rightarrow x=8\)
Bài 2:
\(a;2^{16}=2^{13}\cdot2^3=2^{13}\cdot8>7\cdot2^{13}\)
\(b;49^8\cdot27^5=7^{16}\cdot3^{15}=21^{15}\cdot7>21^5\)
C;Ta có:\(199^{20}< 200^{20}=2^{20}\cdot10^{40}=2^{15}\cdot10^{40}\cdot2^5\)
\(2003^{15}>2000^{15}=2^{15}\cdot10^{45}=2^{15}\cdot10^{40}\cdot10^5\)
Vì 25<105 nên 19920<200315
\(d;3^{39}< 3^{40}=9^{20}< 11^{20}< 11^{21}\)
a) \(\frac{3}{2}-\left(x-\frac{7}{3}\right)=\left|-\frac{3}{4}-\frac{9}{8}\right|\)
=> \(\frac{3}{2}-x+\frac{7}{3}=\left|-\frac{15}{8}\right|\)
=> \(\frac{3}{2}-x+\frac{7}{3}=\frac{15}{8}\)
=> \(\frac{3}{2}-x=-\frac{11}{24}\)
=> \(x=\frac{47}{24}\)
b) \(\frac{5}{2}-\left(\frac{3}{2}-\frac{7}{3}+x\right)=\frac{8}{15}-\left(\frac{1}{4}-\frac{7}{10}\right)\)
=> \(\frac{5}{2}-\frac{3}{2}+\frac{7}{3}-x=\frac{8}{15}-\left(-\frac{9}{20}\right)\)
=> \(\frac{10}{3}-x=\frac{59}{60}\)
=> \(x=\frac{10}{3}-\frac{59}{60}=\frac{47}{20}\)
c) \(2\left(\frac{3}{4}-5x\right)=\frac{4}{5}-3x\)
=> \(\frac{3}{2}-10x-\frac{4}{5}+3x=0\)
=> \(\left(\frac{3}{2}-\frac{4}{5}\right)+\left(-10x+3x\right)=0\)
=> \(\frac{7}{10}-7x=0\)
=> \(7x=\frac{7}{10}\)
=> x = 1/10
Bài giải
a, \(\left(x-5\cdot9\right)\cdot2=0\)
\(x-45=0\)
\(x=45\)
b, \(40\cdot\left(x-2\right)=40\)
\(x-2=1\)
\(x=3\)
c, \(\left(x-4\right)\cdot3+2=101\)
\(\left(x-4\right)\cdot3=99\)
\(x-4=33\)
\(x=37\)
Bài làm :
\(a,\left(x-5.9\right).2=0\)
\(\Rightarrow x-45=0\)
\(\Rightarrow x=0+45\)
\(\Rightarrow x=45\)
\(b,40.\left(x-2\right)=40\)
\(\Rightarrow x-2=40:40\)
\(\Rightarrow x-2=1\)
\(\Rightarrow x=3\)
\(c,\left(x-4\right).3+2=101\)
\(\Rightarrow\left(x-4\right).3=99\)
\(\Rightarrow x-4=99:3\)
\(\Rightarrow x-4=33\)
\(\Rightarrow x=37\)
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