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23 tháng 5 2015

A= 1/30 + 1/42+1/56+1/72+....+1/210

A= 1/5.6+1/6.7+1/7.8+1/8.9+....+1/14.15

A= 1/5 - 1/6+1/6-1/7+1/7-1/8+1/8-1/9+.....+1/14-1/15

A= 1/5 - 1/15

A = 2/15

4 tháng 4 2019

\(A=\frac{-1}{20}+\frac{-1}{30}+\frac{-1}{42}+\frac{-1}{56}+\frac{-1}{72}+\frac{-1}{90}\)

\(A=\frac{-1}{4.5}+\frac{-1}{5.6}+\frac{-1}{6.7}+\frac{-1}{7.8}+\frac{-1}{8.9}+\frac{-1}{9.10}\)

\(-1A=\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}\)

\(-1A=\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\)

\(-1A=\frac{1}{4}-\frac{1}{10}\)

\(-1A=\frac{3}{20}\)

\(A=\frac{-3}{20}\)

4 tháng 4 2019

\(\frac{-1}{20}+\frac{-1}{30}+\frac{-1}{42}+\frac{-1}{56}+\frac{-1}{72}+\frac{-1}{90}\)

=\(\frac{-1}{4.5}+\frac{-1}{5.6}+\frac{-1}{6.7}+\frac{-1}{7.8}+\frac{-1}{8.9}+\frac{-1}{9.10}\)

=\(\frac{-1}{4}-\frac{-1}{5}_{ }+\frac{-1}{5}-\frac{-1}{6}+\frac{-1}{6}-\frac{-1}{7}+\frac{-1}{7}-\frac{-1}{8}+\frac{-1}{8}-\frac{-1}{9}+\frac{-1}{9}-\frac{-1}{10}\)

=\(\frac{-1}{4}+\frac{1}{5}+\frac{-1}{5}+\frac{1}{6}+\frac{-1}{6}+\frac{1}{7}+\frac{-1}{7}+\frac{1}{8}+\frac{-1}{8}+\frac{1}{9}+\frac{-1}{9}+\frac{1}{10}\)

=\(\frac{-1}{4}+\frac{1}{10}\)

=\(\frac{-3}{20}\)

17 tháng 5 2015

A= 1/30 +1/42+1/56+1/72+....+1/210

A=1/5x6 +1/6x7+1/7x8+1/8x9+...+1/14x15

A=1/5 -1/6+1/6-1/7+1/7-1/8+1/8-1/9+.....+1/14-1/15

A= 1/5 - 1/15 

A= 2/15

17 tháng 5 2015

\(\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+...+\frac{1}{210}\)

=\(\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+...+\frac{1}{14.15}\)

\(=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+...+\frac{1}{14}-\frac{1}{15}\)=\(\frac{1}{5}-\frac{1}{15}\)

=\(\frac{3}{15}-\frac{1}{15}\)

=\(\frac{2}{15}\)

 

11 tháng 5 2017

\(A=\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+...+\frac{1}{210}\)

\(A=\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}+...+\frac{1}{14\cdot15}\)

\(A=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{14}-\frac{1}{15}\)

\(A=\frac{1}{5}-\frac{1}{15}=\frac{2}{15}\)

11 tháng 5 2017

\(A=\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+...+\frac{1}{210}\)

\(A=\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+...+\frac{1}{14.15}\)

\(A=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+...+\frac{1}{14}-\frac{1}{15}\)

\(A=\frac{1}{5}-\frac{1}{15}\)

\(A=\frac{2}{15}\)

13 tháng 8 2015

= 1/ 5.6 + 1/ 6.7 + 1/7.8 + 1/8.9 +.....+ 1/ 14.15 
= 1/ 5 - 1/6 + 1/6 - 1/7 +......+1/14 - 1/15 
= 1/5 - 1/ 15 
= 3/15 - 1/15 = 2/ 15 

2 tháng 5 2015

  1/30+1/42+1/56+1/72+....+1/210

=1/5.6+1/6.7+1/7.8+1/8.9+...+1/14.15

=1/5-1/6+1/6-1/7+1/7-1/8+....+1/14-1/15

=1/5-1/15

=2/15

 

7 tháng 6 2017

\(A=\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{14.15}\)

\(A=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{14}-\frac{1}{15}\)

\(A=\frac{1}{5}-\frac{1}{15}\)

\(A=\frac{2}{15}\)

7 tháng 6 2017

\(A=\frac{1}{30}+\frac{1}{40}+\frac{1}{56}+\frac{1}{72}+...+\frac{1}{210}\)

\(A=\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+...+\frac{1}{14.15}\)

\(A=\frac{6-5}{5.6}+\frac{7-6}{6.7}+\frac{8-7}{7.8}+\frac{9-8}{8.9}+...+\frac{15-14}{14.15}\)

\(A=1-\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+...+\frac{1}{14}-\frac{1}{15}\)

\(A=1-\frac{1}{15}\)

\(A=\frac{14}{15}\)

12 tháng 6 2021

\(\frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{110}+....+\frac{1}{240}=\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}+\frac{1}{10.11}+...+\frac{1}{15.16}\)

\(=\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}+\frac{1}{10}-\frac{1}{11}+...+\frac{1}{15}-\frac{1}{16}=\frac{1}{7}-\frac{1}{16}=\frac{9}{112}\)

12 tháng 6 2021

\(=\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}+\frac{1}{10.11}+\frac{1}{11.12}+\frac{1}{12.13}+\frac{1}{13.14}+\frac{1}{14.15}+\frac{1}{15.16}\)

\(=\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}+\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+\frac{1}{13}-\frac{1}{14}+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{16}\)

\(=\frac{1}{7}-\frac{1}{16}\)

\(=\frac{9}{112}\)

13 tháng 5 2016

\(A=\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+....+\frac{1}{14.15}\)

     \(=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+.....+\frac{1}{14}-\frac{1}{15}\)

     \(=\frac{1}{5}-\frac{1}{15}\)

     \(=\frac{2}{15}\)