Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Bài 1: 25 + 3(x - 8) = 106
3(x - 8) = 106 - 25
3(x - 8) = 81
(x - 8) = 81 : 3
(x - 8) = 27
x = 27 + 8
x = 25
Bài 2: 720 : [41 - (2x - 5)] = 23 . 5
720 : [41 - (2x - 5)] = 8 . 5
720 : [41 - (2x - 5)] = 40
[41 - (2x - 5)] = 720 : 40
[41 - (2x - 5)] = 18
(2x - 5) = 41 - 18
(2x - 5) = 23
2x = 23 + 5
2x = 28
x = 28 : 2
x = 14
a, \(3^2\left(x+14\right)-5^2=5.4\)
\(\Rightarrow9\left(x+14\right)-25=20\)
\(\Rightarrow9x+126=20+25\)
\(\Rightarrow9x+126=45\)
\(\Rightarrow9x=45-126\)
\(\Rightarrow9x=-81\Rightarrow x=-9\)
Vậy x = 9
a,\(3^2\left(x+14\right)-5^2=5.4\)
\(\Rightarrow9\left(x-14\right)-25=20\)
\(\Rightarrow9\left(x-14\right)=20+25=45\)
\(\Rightarrow x-14=45:9=5\)
\(\Rightarrow x=5+14\)
\(\Rightarrow x=19\)
Vậy x = 19
b,\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(720:\left[41-2x+5\right]=40\)
\(\Rightarrow41+5-2x=720:40\)
\(\Rightarrow46-2x=18\)
\(\Rightarrow2x=46-18=28\)
\(\Rightarrow x=28:2\)
\(\Rightarrow x=14\)
Vậy x = 14
~Study well~
\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(720:\left[41-\left(2x-5\right)\right]=8.5\)
\(720:\left[41-\left(2x-5\right)\right]=40\)
\(41-\left(2x-5\right)=720:40\)
\(41- \left(2x-5\right)=18\)
\(2x-5=41-18\)
\(2x-5=23\)
\(2x=23+5\)
\(2x=28\)
\(x=28:2\)
\(\Rightarrow x=14\)
a) 2^x.2^4=128
=>2^x.2^2=2^7
=>2^x=2^7:2^2
=>2^x=2^5
=>x=5
b)x^15=x
=>x^15-x=0
=>x(x^16-x)=0
=>2 trượng hợp:x=0 và x^16-1=0(x^16-1=0 cx 2 th nha)
b),d),e) như nhau nha!
c) dễ rồi
\(a)2^x\cdot4=128\)
\(\Rightarrow2^x=\frac{128}{4}\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
\(b)x^{15}=x\)
\(\Rightarrow x^{15}-x=0\)
\(\Rightarrow x(x^{14}-1)=0\)
\(\Rightarrow\hept{\begin{cases}x=0\\x^{14}-1=0\end{cases}}\)\(\Rightarrow\hept{\begin{cases}x=0\\x^{14}=1\end{cases}\Rightarrow}\hept{\begin{cases}x=0\\x=1\end{cases}}\)
\(c)(2x+1)^3=125\)
\(\Rightarrow(2x+1)^3=5^3\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=5-1\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=4:2=2\)
\(d)(x-5)^4=(x-5)^6\)
\(\Rightarrow(x-5)^6-(x-5)^4=0\)
\(\Rightarrow(x-5)^4\cdot\left[(x-5)^2-1\right]=0\)
\(\Rightarrow\orbr{\begin{cases}(x-5)^4=0\\(x-5)^2-1=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=0\\x=6\end{cases}}\)
\(e)(2x-15)^5=(2x-15)^3\)
\(\Rightarrow(2x-15)^5-(2x-15)^3=0\)
\(\Rightarrow(2x-15)^3-\left[(2x-15)^2-1\right]=0\)
\(\Rightarrow\orbr{\begin{cases}(2x-15)^3=0\\(2x-15)^2-1=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=\varnothing\\x=8\end{cases}}\)
Chúc bạn hoc tốt :>
\(2^x.4=128\)
\(2^x=128:4\)
\(2^x=32\)
\(\Leftrightarrow2^x=2^5\Leftrightarrow x=5\)
\(x^{15}=x\Leftrightarrow x\in\left\{-1;0;1\right\}\)
\(\left(2x+1\right)^3=125\)
\(\Leftrightarrow\left(2x+1\right)^3=5^3\)
\(\Leftrightarrow2x+1=5\)
\(\Leftrightarrow2x=4\)
\(\Leftrightarrow x=2\)
\(\left(x-5\right)^6=\left(x-5\right)^4\)
\(\Leftrightarrow\hept{\begin{cases}x-5=-1\\x-5=0\\x-5=1\end{cases}}\Leftrightarrow\hept{\begin{cases}x=4\\x=5\\x=6\end{cases}}\)
\(\text{Vậy:}\)\(x\in\left\{4;5;6\right\}\)
\(2^x.4=128\Rightarrow2^x=32\Rightarrow2^x=2^5\Rightarrow x=5.\)
\(x^{15}=x\Rightarrow\orbr{\begin{cases}x=\pm1\\x=0\end{cases}}\)
\(\left(2x+1\right)^3=125\)
<=> \(\left(2x+1\right)^3=5^3\)
<=> \(2x+1=5\)
<=> \(x=2\)
\(\left(x-5\right)^6=\left(x-5\right)^4\)
<=> \(\left(x-5\right)^6-\left(x-5\right)^4=0\)
<=> \(\left(x-5\right)^4.\left[\left(x-5\right)^2-1\right]=0\)
<=> \(\orbr{\begin{cases}\left(x-5\right)^4=0\\\left(x-5\right)^2-1=0\end{cases}}\)
<=> \(\orbr{\begin{cases}x-5=0\\\left(x-5\right)^2=1\end{cases}}\)
Giải ra được x = 5 ; x = 6 ; x = 4 .
[X-1]^3=125
[x-1]^3=5^3
x-1=5
x=5+1
x=6
Vậy x=6
a) \(\left(x-1\right)^3=125\)
\(\Rightarrow x-1=5\)
\(\Rightarrow x=6\)
b) \(2^{x+2}-2^x=96\)
\(\Rightarrow2^x.2^2-2^x=96\)
\(\Rightarrow2^x.3=96\)
\(\Rightarrow2^x=32=2^5\)
\(\Rightarrow x=5\)
c) \(\left(2x+1\right)^3=343=7^3\)
\(\Rightarrow2x+1=7\)
\(\Rightarrow x=3\)