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â) (81+19)+ 243
= 100 + 243
= 343
b) 168+ 79+132
= (168+132)+79
= 300 +132
=432
c) 5.25.2.16.4
=(5.2).(25.4).16
= 10.100.16
= 1000.16
= 16000
d) 32.17+32.53
= 32.(47+53)
= 32.100
= 3200
a) 81 + 243 + 19
= (81 + 19) + 243
= 100 + 243
= 343
b) 168 + 79 + 132
= (168 + 132) + 79
= 300 + 79
= 379
c) 5 . 25 . 2 . 16 . 4
= (5 . 2) . (25 . 4) . 16
= 10 . 100 . 16
= 1000 . 16
= 16000
d) 32 . 47 + 32 . 53
= 32 . (47 + 53)
= 32 . 100
= 3200
A=81+243+19
=(81+19)+243
=100+243
A=343
B=2.5.2.16.4
=2.5.2.4.4.4
=(2.5).(2.4).(4.4)
=10.8.16
=1280
A=81+243+19
=(81+19)+243
=100+243
A=343
B=2.5.2.16.4
=2.5.2.4.4.4
=(2.5).(2.4).(4.4)
=10.8.16
=1280
\(A=3.727.3^6+3^5.3^4.3^3\)
\(A=3^7.727+3^5.3^7\)
\(A=3^7\left(727+3^5\right)\)
\(A=3^7.970\)
\(A=2121390\)
\(a)\) \(427-98=329\)
\(b)\) \(2\cdot19\cdot15+3\cdot43\cdot10+62\cdot80\)
\(=\left(2\cdot15\right)\cdot19+\left(3\cdot10\right)\cdot43+62\cdot80\)
\(=30\cdot19+30\cdot43+62\cdot80\)
\(=30\cdot\left(19+43\right)+62\cdot80\)
\(=30\cdot62+62\cdot80\)
\(=62\cdot\left(30+80\right)\)
\(=62\cdot110=6820\)
\(c)\) Đặt \(M=\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}+\frac{1}{243}+\frac{1}{729}\)
\(=\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+\frac{1}{3^5}+\frac{1}{3^6}\)
\(\Rightarrow3M=1+\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+\frac{1}{3^5}\)
\(\Rightarrow3M-M=\left(1+\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+\frac{1}{3^5}\right)-\left(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+\frac{1}{3^5}+\frac{1}{3^6}\right)\)
\(\Rightarrow2M=1-\frac{1}{3^6}\)
\(\Rightarrow M=\frac{728}{2\cdot729}=\frac{364}{729}\)
Vậy \(M=\frac{364}{729}\)
a) 81 + 243 +19 = (81 + 19) + 243 = 100 + 243 = 343
b) 134 + 237 + 166 + 563 = (134 + 166) + (237 + 563) = 300 + 800 = 1100
c) 15.7.20 = (15.20).7 = 300.7 = 2100
d) 8.12.125.4 = (8.125).(12.4) = 1000.48 = 48000