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\(\frac{1}{8}\times58,35+0,125\times41+12,5\%\times0,65\)
\(=0,125\times58,35+0,125\times41+0,125\times0,65\)
\(=0,125\times\left(58,35+41+0,65\right)\)
\(=0,125\times100\)
\(=12,5\)
\(\frac{1}{8}\)x 58,35 + 0,125 x 41 + 12,5% x 0,65
= \(\frac{1}{8}\)x 58,35 + \(\frac{1}{8}\)x 41 + \(\frac{1}{8}\)x 0,65
= \(\frac{1}{8}\)x ( 58,35 + 41 + 0,65 )
= \(\frac{1}{8}\)x 100
= 12,5
\(17\cdot\frac{3}{4}-17\cdot0,25+17\cdot\frac{1}{2}\)
\(=17\cdot0,75-17\cdot0,25+17\cdot0,5\)
\(=17\cdot\left(0,75-0,25+0,5\right)\)
\(=17\cdot1\)
\(=17\)
\(17\times\frac{3}{4}-17\times0,25+17\times\frac{1}{2}\)\(=17\times\frac{3}{4}-17\times\frac{1}{4}+17\times\frac{1}{2}\)\(=17\times\left(\frac{3}{4}-\frac{1}{4}+\frac{1}{2}\right)\)
\(=17\times\left(1\right)\)\(=17\)
201,7 x 8,02 + 201,7 : \(\frac{4}{3}\)+ 201,7 x 1,98 - 0,75 x 201,7
= 201,7 x 8,02 + 201,7 x \(\frac{3}{4}\)+ 201,7 x 1,98 - 0,75 x 201,7
= 201,7 x ( 8.02 + \(\frac{3}{4}\)+ 1,98 - 0,75)
= 201,7 x ( 8,02 + 1,98, + \(\frac{3}{4}\)- 0,75)
= 201,7 x 10
= 2017
\(=\left(15\frac{2}{3}+12\frac{1}{3}\right):3-\frac{8}{3}\)
\(=28:3-\frac{8}{3}\)
\(=\frac{28}{3}-\frac{8}{3}\)
\(=\frac{20}{3}\)
\(15\frac{2}{3}:3+12\frac{1}{3}:3-\frac{8}{3}\)
\(=\left(15\frac{2}{3}+12\frac{1}{3}\right):3-\frac{8}{3}\)
\(=28:3-\frac{8}{3}\)
\(\frac{28}{3}-\frac{8}{3}\)
\(\frac{20}{3}\)
\(=427\times\left(12-1\right)\\ =427\times11\\ =4697\)