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\(\left(1+x\right)+\left(2+x\right)+\left(3+x\right)+\)\(\left(4+x\right)+\left(5+x\right)=10\times5\)
\(\left(1+2+3+4+5\right)+\left(x+x+x+x+x\right)=50\)
\(15+5x=50\)
\(5x=35\)
\(x=7\)
Vậy \(x=7\)
\(\left(1+x\right)+\left(2+x\right)+\left(3+x\right)+\left(4+x\right)+\left(5+x\right)=10\times5\)
\(\Rightarrow1+x+2+x+3+x+4+x+5+x=50\)
\(\Rightarrow\left(1+2+3+4+5\right)+\left(x+x+x+x+x\right)=50\)
\(\Rightarrow15+5x=50\)
\(\Rightarrow5x=50-15\)
\(\Rightarrow5x=35\)
\(\Rightarrow x=35:5\)
\(\Rightarrow x=7\).
\(71+65\cdot4=\frac{x+140}{x}+260\)
\(\Rightarrow71+260=\frac{x}{x}+\frac{140}{x}+260\)
\(\Rightarrow71=1+\frac{140}{x}\)
\(\Rightarrow\frac{140}{x}=70\)
\(\Rightarrow x=2\)
71+65*4=x+140 +260
x
=>71+260= x + 140 +260
x x
=>71=1+ 140
x
=> 71-1 = 140
x
=> 70=140:x
=>x=140:70=2
a) \(\frac{1}{3}-\frac{2}{x}=\frac{1}{6}\)
=> \(\frac{2}{x}=\frac{1}{3}-\frac{1}{6}\)
=> \(\frac{2}{x}=\frac{1}{6}\)
\(\Rightarrow x=12\)
Vậy x = 12
b) \(\frac{x-1}{2}=\frac{3}{4}\)
\(\Rightarrow\left(x-1\right).4=2.3\)
=> 4x - 4 = 6
=> 4.(x-1) = 6
=> x-1 = 6:4 = 1,5
=> x = 1,5 + 1
=> x = 2,5
Vậy x = 2,5
\(71+52,5\times4=\frac{x+140}{x}+210\)
\(71+210=\frac{x+140}{x}+210\)
\(=>\frac{x+140}{x}=71\)
\(71=\frac{142}{2}\)\(\Rightarrow x=142-140=2\)
a) ( x + 1 ) + ( x + 4 ) + ( x + 7 ) + ( x + 10 ) + ... + ( x + 28 ) = 155
\(\Rightarrow\)( x + x + x + ... + x ) + ( 1 + 4 + 7 + 10 + ... + 28 ) = 155
\(\Rightarrow\)x10 + ( SSH: ( 28 - 1 ) : 3 + 1 = 10 ) = 155
\(\Rightarrow\)x10 + ( Tổng: ( 1 + 28 ) . 10 : 2 = 145 ) = 155
\(\Rightarrow\)x10 + 145 = 155
\(\Rightarrow\)x10 = 155 - 145 = 10
\(\Rightarrow\)x = 10 : 10 = 1
vậy x = 1
b) ( x . 0,25 + 1999 ) . 2000 = ( 53 + 1999 ) .2000
\(\Rightarrow\)500x + 3998000 = 106000 + 3998000
\(\Rightarrow\)500x + 3998000 = 4104000
\(\Rightarrow\)500x = 4104000 - 3998000 = 106000
\(\Rightarrow\)x = 106000 : 500 = 212
a) \(\left(x+\frac{3}{4}\right):5=\frac{5}{6}\)
\(x+\frac{3}{4}=\frac{5}{6}\text{x}5\)
\(x+\frac{3}{4}=\frac{25}{6}\)
\(x=\frac{25}{6}-\frac{3}{4}\)
\(x=\frac{41}{12}\)
b) \(\left(\frac{4}{3}+x\right)\text{x}\frac{1}{11}=\frac{7}{11}\)
\(\frac{4}{3}+x=\frac{7}{11}:\frac{1}{11}\)
\(\frac{4}{3}+x=7\)
\(x=7-\frac{4}{3}\)
\(x=\frac{17}{3}\)
a) \(x+\frac{3}{4}\div5=\frac{5}{6}\)
\(x+\frac{3}{4}=\frac{5}{6}\times5\)
\(x+\frac{3}{4}=\frac{25}{6}\)
\(x=\frac{25}{6}-\frac{3}{4}\)
\(x=\frac{41}{21}\)
b) \(\left(\frac{4}{3}+x\right)\times\frac{1}{11}=\frac{7}{11}\)
\(\frac{4}{3}+x=\frac{7}{11}\div\frac{1}{11}\)
\(\frac{4}{3}+x=7\)
\(x=7-\frac{4}{3}\)
\(x=\frac{17}{3}\)
5,6 : x = 4
x = 1,4
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