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1\(\frac{5}{7}\)x\(\frac{3}{4}\)
=\(\frac{35}{7}\)x \(\frac{3}{4}\)
=5x\(\frac{3}{4}\)
=\(\frac{23}{4}\)
\(\frac{10}{11}\):\(1\frac{1}{3}\)
=\(\frac{10}{11}\):\(\frac{4}{3}\)
=\(\frac{10}{11}\)x\(\frac{3}{4}\)
=\(\frac{30}{44}\)
=\(\frac{15}{22}\)
3,57x4,1+2,43x4,1
=(3,57+2,43)x 4,1
=6x4,1
=24,6
còn câu cúi mik ko bik làm
1/5/7 x 3/4
=(1+5/7)x3/4
=1x3/4+5/7x3/4
=3/4+15/28
=21/28+15/28
=36/28
=9/7
10/11 : 1/1/3
=10/11:(1+1/3)
=10/11:1+10/11:1/3
=10/11+10/11x3
=10/11+30/11
=40/11
3,57x4,1+2,43x4,1
=4,1x(3,57+2,43)
=4,1x6
=24,6
3,42:0,57x8,4-6,8
=342/100:57/100x84/10-68/10
=342/100x100/57x16/10
=342/57x8/5
=6x8/5
=48/5
=9.6
mình giải rất rõ ràng và cụ thể
nên hãy k cho mình nha
Ta có: 9,5. x= 47,4+ 24,8
=> 9,5. x= 72,2
=> x= 72,2: 9,5= 7,6
Vậy x= 7,6
Ta có: x: 8,4+ x: 1,6= 26,3
=> x: \(\frac{42}{5}\)+ x: \(\frac{8}{5}\)= 26,3
=> x. \(\frac{5}{42}\)+ x. \(\frac{5}{8}\)= 26,3
=> x. \(\left(\frac{5}{42}+\frac{5}{8}\right)\)= 26,3
=> x. \(\frac{20+21}{168}\)= 26,3
=> x. \(\frac{41}{168}\)= \(\frac{263}{10}\)
=> x= \(\frac{263}{10}:\frac{41}{168}\)
=> x= \(\frac{263}{10}.\frac{168}{41}\)
=> x\(\approx107,8\)
Vậy x\(\approx107,8\)
Dấu \(\approx\)nghĩa là xấp xỉ nha! Đây là toán lớp 5 nhưng mik làm có hơi xen vào toán lớp 6; 7 một tí. Bạn đọc cho hiểu nha! Có gì ko hiểu thì cứ hỏi mik mik sẽ giải đáp cho!!!!!!!!!!!!!!!!!!!!!!!!!!! Mik mong là bạn sẽ k cho mik
\(x+x\times\frac{1}{3}\div\frac{2}{9}+x\div\frac{2}{7}=252\)
\(\Leftrightarrow x+x\times\frac{1}{3}\times\frac{9}{2}+x\times\frac{7}{2}=252\)
\(\Leftrightarrow x\left(1+\frac{1}{3}\times\frac{9}{2}+\frac{7}{2}\right)=252\)
\(\Leftrightarrow x\left(\frac{6}{6}+\frac{9}{6}+\frac{21}{6}\right)=252\)
\(\Leftrightarrow x\times\frac{36}{6}=252\)
\(\Leftrightarrow x\times6=252\)
\(\Leftrightarrow x=252\div6\)
\(\Leftrightarrow x=43\)
\(\frac{x+9}{13-x}=\frac{6}{5}\)
\(\Rightarrow\orbr{\begin{cases}x+9=6\\13-x=5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-3\\x=8\end{cases}}\)
\(\frac{120-x}{30}=3\frac{1}{2}\)
\(\Rightarrow\frac{120-x}{30}=\frac{7}{2}\)
\(\Rightarrow\frac{120-x}{30}=\frac{105}{30}\)
\(\Rightarrow120-x=105\)
\(\Rightarrow x=120-105\)
\(\Rightarrow x=15\)
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+...+\left(x+\frac{1}{512}\right)=1\)
\(9x+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{512}\right)=1\)
\(9x+\left[\left(1-\frac{1}{2}\right)+\left(\frac{1}{2}-\frac{1}{4}\right)+\left(\frac{1}{4}-\frac{1}{8}\right)+....+\left(\frac{1}{256}-\frac{1}{512}\right)\right]=1\)
\(9x+\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+...+\frac{1}{512}\right)=1\)
\(9x+\left(1-\frac{1}{512}\right)=1\)
\(9x+\frac{511}{512}=1\)
\(9x=1-\frac{511}{512}\)
\(9x=\frac{1}{512}\)
\(\Rightarrow x=\frac{1}{512}\div9=\frac{1}{4608}\)
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
\(x\cdot4+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(x\cdot4+\left(\frac{8}{16}+\frac{4}{16}+\frac{2}{16}+\frac{1}{16}\right)=1\)
\(x\cdot4+\frac{13}{16}=1\)
\(x\cdot4=1-\frac{13}{16}\)
\(x\cdot4=\frac{3}{16}\)
\(x=\frac{3}{16}:4\)
\(x=\frac{3}{64}\)
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
\(=\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(=4x+\frac{15}{16}=1\)
\(\Rightarrow4x=1-\frac{15}{16}=\frac{1}{16}\)
\(\Rightarrow x=\frac{1}{16}:4=\frac{1}{64}\)
- 2^y + 2^x - 224 = 0
- ( 2^y - 2^x + 224 ) = 0
2^y - 2^x + 224 = 0
Tìm cá số nguyên dương x,y biết:
\(2^x\)\(-\) \(2^y\)= \(224\)
=> \(2^x-2^y=2^{10}\)
=> \(2^y=2^{10}\)
=> y = 10
=> \(2^x=2^{10}+2^{10}\)
=> \(2^x=2^{11}\)
=> x = 11
Vậy x = 11; y = 10
X – 23,4 = 8,4 x 2
X – 23,4 = 16,8
X = 23,4 + 16,8
X = 40,2
X – 23,4 = 8,4 x 2
X – 23,4 = 8,4 x 2
X – 23,4 = 16,8
X = 23,4 + 16,8
X = 40,2