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a) \(25^2-15^2=\left(25-15\right)\left(25+15\right)\)
= 400
b) \(87^2+73^2-27^2-13^2\)
\(\Leftrightarrow\left(87^2-13^2\right)\)+\(\left(73^2-27^2\right)\)
\(\Leftrightarrow\left(87+13\right)\left(87-13\right)+\left(73+27\right)\left(73-27\right)\)
\(\Leftrightarrow7400+4600=12000\)
Giải:
1). \(25^2-15^2\)
\(=\left(25-15\right)\left(25+15\right)\)
\(=10.40\)
\(=400\)
2). \(87^2+73^2-27^2-13^2\)
\(=\left(87^2-13^2\right)+\left(73^2-27^2\right)\)
\(=\left(87-13\right)\left(87+13\right)+\left(73-27\right)\left(73+27\right)\)
\(=74.100+46.100\)
\(=100\left(74+46\right)\)
\(=100.120\)
\(=12000\)
Chúc bạn học tốt!!!
Bài giải:
a) 732 – 272 = (73 + 27)(73 – 27) = 100 . 46 = 4600
b) 372 - 132 = (37 + 13)(37 – 13) = 50 . 25 = 100 . 12 = 1200
c) 20022 – 22 = (2002 + 2)(2002 – 2) = 2004 . 2000 = 400800
Câu 1:
a. \(\frac{1}{4}x^2-64\)
\(=\left(\frac{1}{2}x\right)^2-8^2\)
\(=\left(\frac{1}{2}x+8\right)\left(\frac{1}{2}x-8\right)\)
b. \(\frac{1}{27}+x^3\)
\(=\left(\frac{1}{3}\right)^3+x^3\)
\(=\left(\frac{1}{3}+x\right)\left(\frac{1}{9}-\frac{1}{3}x+x^2\right)\)
c. \(\left(a+b\right)^3-\left(a-b\right)^3\)
\(=\left(a^3+3a^2b+3ab^2+b^3\right)-\left(a^3-3a^2b+3ab^2-b^3\right)\)
\(=a^3+3a^2b+3ab^2+b^3-a^3+3a^2b+3ab^2+b^3\)
\(=6a^2b+2b^3\)
\(=2b\left(3a^2+b^2\right)\)
Bài 1:
\(A=23^2+46\cdot37+37^2=23^2+2\cdot23\cdot37+37^2=\left(23+37\right)^2=60^2=3600\)
\(B=27^2-44\cdot27+22^2=27^2-2\cdot27\cdot22+22^2=\left(27-22\right)^2=5^2=25\)
Bài 2:
\(A=x^2-4x+5=x^2-4x+4+1=\left(x-2\right)^2+1\)
Vì: \(\left(x-2\right)^2\ge0\) với mọi x
=> \(\left(x-2\right)^2+1\ge1\)
Vậy GTNN của A là 1 khi x=2
\(A=23^2+2.23.37+37^2=\left(23+37\right)^2=60^2=3600\)
\(B=27^2-2.27.22+22^2=\left(27-22\right)^2=5^2=25\)
\(A=x^2-4x+5=\left(x-2\right)^2+1\ge1\)
=> A min=1 khi x=2
a) 262 + 52.24 + 242
= 262 + 2.26.24 + 242
= ( 26 + 24 )2
= 502 = 2500
b) 30032 - 32
= ( 3003 + 3 ) ( 3003 - 3 )
= 3006 . 3000 = 9018000
c) 872 + 732 - 272 -132
= ( 872 - 132 ) + ( 732 - 272 )
= [ ( 87 + 13 )( 87- 13 )] + [ ( 73 - 27 )( 73 + 27 ) ]
= ( 100 . 74 ) + ( 46 . 100 )
= 7400 + 4600 = 12000
d)792 - 79.58 + 292
= 792 - 2.79.29 + 292
= ( 79 - 29 )2
= 502 = 2500
a) 262 + 52 . 24 + 242 = 262 + 2 . 26 . 24 + 242
= ( 26 + 24 )2
= 502
= 2500
b) 30032 - 32 = ( 3003 - 3 ) . ( 3003 + 3 )
= 3000. 3006
= 9018000
c) 872 + 732 - 272 - 132 = ( 872 - 272 ) + ( 732 - 132 )
= ( 87 - 27 ) . ( 87 + 27 ) + ( 73 - 13 ) . ( 73+13)
= 60 . 114 + 60 . 86
= 60 . ( 114 + 86 )
= 60 . 200
= 12000
d) 792 - 79 . 58 + 292 = 792 - 2 . 79 . 29 + 292
= ( 79 - 29 )2
= 502
= 2500
bài 1
a(x+y)2-(x-y)2
=[(x+y)-(x-y)][(x+y)+(x-y)]
=(x+y-x+y)(x+y+x-y)
=2y.2x
b,(3x+1)2-(x+1)2
=[(3x+1)-(x+1)][(3x+1)+(x+1)]
=(3x+1-x-1)(3x+1+x+1)
=2x.(4x+2)
4x.(x+10
bài 2
x3-0,25x=0
=>x(x2-0,25)=0
=>x=0 hoặc x2-0,25=0
=> x=0 hoặc x=\(\pm0,5\)
Bài 1:
a, \(x^2+10x+26+y^2+2y\)
\(=x^2+2.x.5+5^2+y^2+2.y.1+1^2\)
\(=\left(x+5\right)^2+\left(y+1\right)^2\)
b, \(x^2-2xy+2y^2+2y+1\)
\(=x^2-2.x.y+y^2+y^2+2.y.1+1^2\)
\(=\left(x-y\right)^2+\left(y+1\right)^2\)
c, \(4x^2+2z^2-4xz-2z+1\)
\(=\left(2x\right)^2-2.2x.z+z^2+z^2-2.z.1+1^2\)
\(=\left(2x-z\right)^2+\left(z-1\right)^2\)
Chúc bạn học tốt!!!
Bài1:
Bn kia giải r nhé
Bài 2:
a)\(127^2+146.127+73^2=127^2+2.73.127+73^2\)
=\(\left(127+73\right)^2=200^2=40000\)
b)\(31,8^2-63,6.21,8+21,8^2=\left(31,8-21,8\right)^2=10^2=100\)
c)\(2018^2-2017^2+2016^2-2015^2+...+2^2-1\)
=\(\left(2018+2017\right)+\left(2015+2016\right)+...+\left(2+1\right)\)
=4025+4031+...+3
=...(bn tự tính)
d)\(2017^2-2016.2018=2017^2-\left(2017^2-1\right)=1\)
732 – 272
= (73 + 27)(73 – 27)
= 100.46
= 4600