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\(\frac{4}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)< x< \frac{2}{3}.\left(\frac{-1}{6}+\frac{3}{4}\right)\)
⇒ \(\frac{4}{3}.\left(\frac{-1}{3}\right)< x< \frac{2}{3}.\left(\frac{7}{12}\right)\)
⇒ \(\frac{-4}{9}< x< \frac{7}{18}\)
⇒ \(\frac{-8}{18}< x< \frac{7}{18}\)
mà -8<x<7
⇒ x ϵ \(\left\{-7;-6;-5;-4;....;5;6\right\}\)
\(\frac{1}{2}+\frac{1}{3}-2\frac{1}{5}\le x< 4\frac{1}{5}+3\frac{1}{2}\)
\(\frac{1}{2}+\frac{1}{3}-\frac{11}{5}\le x< \frac{21}{5}+\frac{7}{2}\)
\(\frac{15}{30}+\frac{10}{30}-\frac{66}{30}\le x< \frac{42}{10}+\frac{35}{10}\)
\(-\frac{41}{30}\le x< \frac{77}{10}\)
\(-1\frac{11}{30}\le x< 7\frac{7}{10}\)
Vậy \(x\in\){ -1 ; 0 ; 1 ; 2 ; 3 ; 4 ; 5 ; 6 ; 7 }
\(\left(\frac{1}{2}+\frac{3}{4}-\frac{1}{3}\right):\frac{-5}{6}< x< \frac{4}{21}.\frac{4}{7}\)
\(\Rightarrow\left(\frac{6}{12}+\frac{9}{12}-\frac{4}{12}\right):\frac{-10}{12}< x< \frac{16}{147}\)
\(\Rightarrow\frac{11}{12}.\frac{-12}{10}< x< \frac{16}{147}\)
\(\Rightarrow\frac{-11}{10}< x< \frac{16}{147}\)
\(\Rightarrow\frac{-1617}{1470}< x< \frac{16}{1470}\)
\(x=\left\{-1;0\right\}\)
g) \(\left(x+\frac{1}{2}\right)\left(\frac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{2}=0\\\frac{2}{3}-2x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{-1}{2}\\x=\frac{1}{3}\end{cases}}\)
Vây \(x\in\left\{\frac{-1}{2};\frac{1}{3}\right\}\)
\(x\in c???\)
Đề bài là : Tìm \(x\inℤ\)biết :
\(\left[\frac{1}{2}+\frac{3}{4}-\frac{1}{2}\right]:\frac{-5}{6}< x< \frac{4}{21}:\frac{4}{-7}\)
\(\Rightarrow\left[\frac{1}{2}-\frac{1}{2}+\frac{3}{4}\right]:\frac{-5}{6}< x< \frac{4}{21}:\frac{-4}{7}\)
\(\Rightarrow\left[0+\frac{3}{4}\right]:\frac{-5}{6}< x< \frac{4}{21}\cdot\frac{7}{-4}\)
\(\Rightarrow\frac{3}{4}:\frac{-5}{6}< x< \frac{1}{3}\cdot\frac{1}{-1}\)
\(\Rightarrow\frac{3}{4}\cdot\frac{6}{-5}< x< -\frac{1}{3}\)
\(\Rightarrow\frac{-9}{10}< x< -\frac{1}{3}\)
\(\Rightarrow\frac{-27}{30}< x< -\frac{10}{30}\)
Tự tìm :v