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\(\frac{1}{2}\cdot4^n+4\cdot4^n=9\cdot2^{n+1}\)
\(\Rightarrow4^n\left(\frac{1}{2}+4\right)=9\cdot2^{n+1}\)
\(\Rightarrow2^{2n}\cdot\frac{9}{2}=9\cdot2^{n+1}\)
\(\Rightarrow2^{2n}=9\cdot2^{n+1}:\frac{9}{2}\)
\(\Rightarrow2^{2n}=9\cdot2^{n+1}\cdot\frac{2}{9}\)
\(\Rightarrow2^{2n}=2^{n+2}\)
\(\Rightarrow2n=n+2\)
\(\Rightarrow n=2\)
#)Giải :
\(\frac{1}{9}.3^4.3^n=3^7\)
\(\frac{1}{9}.81.3^n=3^7\)
\(9.3^n=3^7\)
\(3^2.3^n=3^7\)
\(\Rightarrow2+n=7\)
\(\Rightarrow n=5\)
#~Will~be~Pens~#
a/\(\frac{1}{9}.3^4.3^n=3^7\)
\(\frac{1}{9}.81.3^n=3^7\)
\(\frac{81}{9}.3^n=3^7\)
\(9.3^n=3^7\)
\(3^2.3^n=3^7\)
\(3^2.3^n=3^2.3^5\)
vậy \(n=5\)
b/ \(\frac{1}{2}.2^n+4.2^n=9.2^5\)
\(2^n\left(\frac{1}{2}+4\right)=9.2^5\)
\(2^n.\frac{9}{2}=9.32\)
\(2^n.\frac{9}{2}=288\)
\(2^n=288:\frac{9}{2}\)
\(2^n=64\)
\(2^n=2^6\)
Vậy \(n=6\)
1/9 x 34 x 3n = 37
9 x 3n = 37
3n = 37 : 9
3n = 2187 : 9
3n = 243
Ta có : 243 = 3 x 3 x 3 x 3 x 3 = 35
Vây n = 5
\(a,2.16\le2^n< 4\)
\(\Rightarrow2^5\le2^n< 2^2\)
\(\Rightarrow n\in5,4,3\)
\(b,3^2.3^n=3^5\)
\(\Rightarrow3^n=3^5:3^2\)
\(\Rightarrow3^n=3^2\)
\(\Rightarrow n=2\)
\(c,\left(2^2:4\right):2^n=4\)
\(\Rightarrow1:2^n=4\)
\(\Rightarrow2^n=1:4=\frac{1}{4}\)
mà \(n\in N\)nên n ko có giá trị nào
\(d,\frac{1}{9}.3^4.3^n=3^7\)
\(\Rightarrow\left(\frac{1}{3}\right)^2.3^2.3^2.3^n=3^7\)
\(\Rightarrow3^2.3^n=3^7\)
\(\Rightarrow3^n=3^7:3^2\)
\(\Rightarrow3^n=3^5\)
\(\Rightarrow n=5\)
e,f làm tự làm tiếp nhé,mỏi tay wa
Trl :
\(\frac{1}{9}.27^n=3^{n+2}\)
\(3^{-2}.\left(3^3\right)^n=3^{n+2}\)
\(3^{-2}.3^{3n}=3^{n+2}\)
\(\Rightarrow-2+3n=n+2\)
\(\Rightarrow3n=n+4\)
\(\Rightarrow2n=4\)\(\Rightarrow n=2\)
Hok tốt
Trl :
\(\frac{1}{9}3^4.3^n=3^7\)
\(3^{-2}.3^4.3^n=3^7\)
\(\Rightarrow-2+4+n=7\)
\(\Rightarrow2+n=7\)
\(\Rightarrow n=7-2\)
\(\Rightarrow n=5\)
Hok tốt !