Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{16.17-5}{16.16+11}\)
\(=\frac{16.16+16-5}{16.16+11}\)
\(=\frac{16.16+11}{16.16+11}\)
\(=1\)
\(\frac{16\cdot17-5}{16\cdot16+11}\)
\(=\frac{16\cdot17-5}{16\cdot17-16-11}\)
\(=\frac{16\cdot17-5}{16\cdot17-5}\)
\(=1\)
mk ko copy của Trần Thùy Dung nhé
\(\frac{16.17-5}{16.16+11}\)
\(=\frac{16.\left(16+1\right)-5}{16^2+11}\)
\(=\frac{16^2+16-5}{16^2+11}\)
\(=\frac{16^2+11}{16^2+11}\)
\(=1\)
(Nhớ k cho mình với nhé!)
\(\frac{16x17-5}{16x16+11}\)
=\(\frac{16x\left(16+1\right)-5}{16x16+11}\)
=\(\frac{16x16+16x1-5}{16x16+11}\)
= \(\frac{16x16+11}{16x16+11}\)
= 1 ( vì TS = MS )
\(\frac{16.17-5}{16.16+11}\)
\(=\frac{16.\left(16+1\right)-5}{16^2+11}\)
\(=\frac{16^2+16-5}{16^2+11}\)
\(=\frac{16^2+11}{16^2+11}=1\)
(Nhớ k cho mình với nhé!)
a: A=16*16+16-5=16*16+11
=>A=B
b: A=2000*2000=2000^2
B=1998*2002=(2000-2)(2000+2)=2000^2-4
=>A<B
d: B=(2020-1)(2020+1)=2020^2-1
=>B<A
\(\frac{-5}{18}+\frac{5}{9}-\frac{11}{36}\)
\(=\frac{-10}{36}+\frac{20}{36}-\frac{11}{36}\)
\(=-\frac{1}{36}\)
vậy_
\(\frac{-5}{18}+\frac{5}{9}-\frac{11}{36}\)
\(=\frac{5}{18}-\frac{11}{36}\)
\(=\frac{-1}{36}\)
___________________________
\(\frac{-39}{44}:1\frac{2}{11}\)
\(=\frac{-39}{44}:\frac{13}{11}\)
\(=\frac{-3}{4}\)
_________________________
\(\frac{-7}{11}.\frac{11}{19}+\frac{-7}{11}.\frac{8}{19}+\frac{-4}{11}\)
\(=\frac{-7}{11}.\left(\frac{11}{19}+\frac{8}{19}\right)+\frac{-4}{11}\)
\(=\frac{-7}{11}.1+\frac{-4}{11}\)
\(=\frac{-7}{11}+\frac{-4}{11}\)
\(=\frac{-11}{11}=-1\)
\(\frac{16.17-5}{16.16+11}\)
\(=\frac{17-5}{16+11}\)
\(=\frac{12}{27}\)
Bài làm
\(\frac{16x17-5}{16x16+11}\)
\(=\frac{272-5}{256+11}\)
\(=\frac{267}{267}\)
\(=1\)
# Học tốt #