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FC
16 tháng 12 2018
\(\dfrac{4^6.9^5+6^9.120}{8^4.3^2-6^{11}}\)
\(=\dfrac{\left(2^2\right)^6.\left(3^2\right)^5+\left(2.3\right)^9.120}{\left(2^3\right)^4.3^2-\left(2.3\right)^{11}}\)
\(=\dfrac{2^{12}.3^{10}+2^9.3^9.120}{2^{12}.3^2-2^{11}.3^{11}}\)
\(=\dfrac{1.3^8+1.1.120}{1.1-4.9}\)
\(=\dfrac{1.6561+120}{1-36}=\dfrac{6681}{-35}\)
Chắc sai đấy!!!! 
MC
16 tháng 12 2018
\(\dfrac{4^6.9^5+6^9.120}{8^4.3^2-6^{11}}\)
\(=\dfrac{\left(2^2\right)^6.\left(3^2\right)^5+\left(2.3\right)^9.\left(2^3.3.5\right)}{\left(2^3\right)^4.3^2-\left(2.3\right)^{11}}\)
\(=\dfrac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{12}.3^2-2^{11}.3^{11}}\)
\(=\dfrac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^2-2^{11}.3^{11}}\)
\(=\dfrac{2^{12}.3^{10}\left(1+5\right)}{2^{11}.3^2\left(2-3^9\right)}\)
\(=\dfrac{2.3^8.6}{2-3^9}=\dfrac{2.3^8.2.3}{2-3^9}=\dfrac{2^2.3^9}{2-3^9}\)
3 tháng 10 2018
ta có : \(\dfrac{4^6.9^5+6^9.120}{-8^4.3^{12}-6^{11}}=\dfrac{4\left(4^5.9^5+5.6^{10}\right)}{-2^{12}.3^{12}-6^{11}}=\dfrac{4\left(2^{10}.3^{10}+5.6^{10}\right)}{-2^{12}.3^{12}-6^{11}}\)
\(=\dfrac{4\left(6^{10}+5.6^{10}\right)}{-6^{12}-6^{11}}=\dfrac{4.6^{11}}{-6^{11}\left(6+1\right)}=-\dfrac{4}{7}\)
12 tháng 6 2022
\(=\dfrac{2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5}{-2^{12}\cdot3^{12}+2^{11}\cdot3^{11}}\)
\(=-\dfrac{2^{12}\cdot3^{10}\left(1+5\right)}{2^{11}\cdot3^{11}\cdot\left(2\cdot3-1\right)}=\dfrac{-2}{3}\)
QH
1
7 tháng 12 2022
\(=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}=\dfrac{2^{12}\cdot3^{10}\cdot6}{2^{11}\cdot3^{11}\cdot\left(2\cdot3-1\right)}\)
\(=\dfrac{2}{3}\cdot\dfrac{6}{5}=\dfrac{12}{15}=\dfrac{4}{5}\)
D
1
6 tháng 12 2022
\(=\dfrac{5^3\left(2^3+2+1\right)}{55}-\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}\)
\(=5^2-\dfrac{2^{12}\cdot3^{10}\cdot\left(1+5\right)}{2^{11}\cdot3^{11}\left(2\cdot3-1\right)}=25-\dfrac{2}{3}\cdot\dfrac{6}{5}\)
=25-4/5
=24,2
DT
3
DT
4
K
25 tháng 3 2018
\(\dfrac{4^6.9^5+6^9.120}{-8^4.3^{12}+6^{11}}\)
\(=\dfrac{\left(2^2\right)^6.\left(3^2\right)^5+\left(2.3\right)^9.2^3.3.5}{-\left(2^3\right)^4.3^{12}+\left(2.3\right)^{11}}\)
\(=\dfrac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{-2^{12}.3^{12}+2^{11}.3^{11}}\)
\(=\dfrac{2^{12}.3^{10}+2^{12}.3^{10}.5}{-2^{12}.3^{12}+2^{11}.3^{11}}\)
\(=\dfrac{2^{12}.3^{10}\left(1+5\right)}{-6^{12}+6^{11}}\)
\(=\dfrac{2^{12}.3^{10}.6}{6^{11}-6^{12}}\)
\(=\dfrac{2^{12}.3^{10}.2.3}{6^{11}\left(1-6\right)}\)\(=\dfrac{2^{13}.3^{11}}{6^{11}.\left(-5\right)}\) \(=\dfrac{2^{11}.3^{11}.2^2}{6^{11}.\left(-5\right)}=\dfrac{6^{11}.4}{6^{11}.\left(-5\right)}=\dfrac{4}{-5}=-\dfrac{4}{5}\)
25 tháng 3 2018
bài này mk làm ròi ak, tại do lỗi trang wed nên mới bị đăng lên
CM
0
HT
24 tháng 11 2018
46.95+69.120−84.312−611
\(=\dfrac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(=\dfrac{2^{12}.3^{10}+3^9.2^9.3.2^3.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\dfrac{2^{12}.3^{10}\left(1+5\right)}{2^{11}3^{11}\left(6-1\right)}\)
\(=\dfrac{2^{13}3^{11}}{2^{11}.3^{11}.5}\)
\(=\dfrac{2^2}{5}=\dfrac{4}{5}\)
\(=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}=\dfrac{2^{12}\cdot3^{10}\cdot6}{2^{11}\cdot3^{11}\cdot\left(2\cdot3-1\right)}\)
\(=\dfrac{2}{3}\cdot\dfrac{6}{5}=\dfrac{12}{15}=\dfrac{4}{5}\)