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\(\frac{2}{n}+\frac{2}{n+1}=\frac{2\left(n+1\right)}{n\left(n+1\right)}+\frac{2n}{n\left(n+1\right)}\)\(=\frac{2\left(n+1\right)+2n}{n\left(n+1\right)}=\frac{2n+2+2n}{n\left(n+1\right)}=\frac{4n+2}{n\left(n+1\right)}\)
\(\frac{1}{n\left(n+1\right)}+\frac{-2}{n+1}=\frac{1}{n\left(n+1\right)}+\frac{-2n}{n\left(n+1\right)}\)\(=\frac{1+\left(-2n\right)}{n\left(n+1\right)}=\frac{1-2n}{n\left(n+1\right)}\)
a/ \(\frac{5}{6n}\)và \(\frac{7}{15}\)
=> MSC = \(6n\cdot15=90n\)
\(\Rightarrow\frac{5}{6n}=\frac{5\cdot15}{90n}=\frac{75}{90n}\)
\(\Rightarrow\frac{7}{15}=\frac{7\cdot6n}{90n}=\frac{42n}{90n}\)
b/ \(\frac{9x}{24}\)và \(\frac{12}{36}\)
=> MSC = 72
\(\Rightarrow\frac{9x}{24}=\frac{9x\cdot3}{72}=\frac{27x}{72}\)
\(\Rightarrow\frac{12}{36}=\frac{12\cdot2}{72}=\frac{24}{72}\)
a)MSC = 6n . 15 = 90n
5/6n = 5 . 15/60n . 15 = 75/90n
7/15 = 7 . 6n/15 . 6n =42n/90n
#Louis
\(\left(\frac{3}{5}-\frac{1}{2}+\frac{7}{3}\right)-\left(\frac{1}{3}-\frac{5}{2}+\frac{1}{5}\right)-\left(\frac{-3}{5}+3-\frac{5}{3}\right)\)
\(=\frac{3}{5}-\frac{1}{2}+\frac{7}{3}-\frac{1}{3}+\frac{5}{2}-\frac{1}{5}+\frac{3}{5}-3+\frac{5}{3}\)
\(=\frac{3}{5}+\frac{-1}{2}+\frac{7}{3}+\frac{-1}{3}+\frac{5}{2}+\frac{-1}{5}+\frac{3}{5}+\left(-3\right)+\frac{5}{3}\)
\(=\left(\frac{3}{5}+\frac{-1}{5}+\frac{3}{5}\right)+\left(\frac{-1}{2}+\frac{5}{2}\right)+\left(\frac{7}{3}+\frac{-1}{3}+\frac{5}{3}\right)+\left(-3\right)\)
\(=\frac{5}{5}+\frac{4}{2}+\frac{11}{3}+\left(-3\right)\)
\(=1+2+\frac{11}{3}+\left(-3\right)\)
\(=0+\frac{11}{3}=\frac{11}{3}\)
Mk bỏ qua bước đầu bài nhé
= 3/5 - 1/2 + 7/3 - 1/3 - 5/2 + 1/5 - 3/5 + 3 - 5/3 (Phá ngoặc nên đổi dấu )
=(3/5 - 3/5 - 1/5) - (1/2 + 5/2) + (7/3 - 1/3 - 5/3) + 3
= -1/5 - 3 + 1/3 + 3
Tích cho mk nhé
\(\text{ Bài giải }\)
\(a,\text{ }\frac{7n}{15}\text{ và }\frac{20}{39}\)
\(BCNN\left(15,39\right)=195\)
\(\frac{7n}{15}=\frac{7n\cdot13}{15\cdot13}=\frac{91n}{195}\) \(\frac{20}{39}=\frac{20\cdot5}{39\cdot5}=\frac{100}{195}\)
\(b,\text{ }\frac{14}{41}\text{ và }\frac{17n}{54}\)
\(BCNN\left(41,54\right)=2214\)
\(\frac{14}{41}=\frac{14\cdot54}{41\cdot54}=\frac{756}{2214}\) \(\frac{17n}{54}=\frac{17n\cdot41}{54\cdot41}=\frac{697n}{2214}\)
\(\frac{2^2.3^3.5^7}{2^3.3^4.5^6}=\frac{1.1.5}{2.3.1}=\frac{5}{6}\)
Làm tương tự
Ta có : x+75%.x=\(\frac{-5}{8}\)
=> x+0,75.x=\(\frac{-5}{8}\)
=> x+\(\frac{3}{4}\).x=\(\frac{-5}{8}\)
=> x.(1+\(\frac{3}{4}\))=\(\frac{-5}{8}\)
=> x.\(\frac{7}{4}\)=\(\frac{-5}{8}\)
=> x=\(\frac{-5}{14}\)
Vậy x=\(\frac{-5}{14}\)
Các bạn hãy tk cho mk nha !!!
\(\dfrac{2}{7}-\dfrac{1}{14}=\dfrac{4}{14}-\dfrac{1}{14}=\dfrac{4-1}{14}=\dfrac{3}{14}\)