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a ) \(\left(x-3\right).\left(x+2\right)+\left(x-1\right).\left(x+1\right)-\left(2x-1\right)x\)
\(=x.\left(x+2\right)-3.\left(x+2\right)+x.\left(x+1\right)-1.\left(x+1\right)-\left(2x-1\right)x\)
\(=x^2+2x-3x-6+x^2+x-x-1-2x^2+x\)
\(=-6\)
\(\RightarrowĐPCM\)
x/4=6/8 3x+1/3=5/2 x-3-1/7=0
x.8=4.6=24 3x=5/2-1/3=13/6 x-3=0+1/7=1/7
x=24:8=3 x=13/6:3=13/18 x=1/7+3=22/7
\(\frac{x}{4}=\frac{6}{8}\Rightarrow x\times8=4.6\Rightarrow x=\frac{4.6}{8}3\)
Vậy x=3
3x\(+\frac{1}{3}=\frac{5}{2}\)
3x =\(\frac{5}{2}-\frac{1}{3}\)
3x =\(\frac{13}{6}\)
x =\(\frac{13}{6}:3=\frac{13}{6}.\frac{1}{3}\)
x =\(\frac{13}{18}\)
x-3-\(\frac{1}{7}=0\)
x-3 =0+\(\frac{1}{7}\)
x-3 =\(\frac{1}{7}\)
x =\(\frac{1}{7}+3\)
x =3\(\frac{1}{7}\)
a) Ta có: \(\frac{x-4}{x+1}=\frac{x-15}{x+6}\)
\(\Rightarrow\)\(x^2+6x-4x-24=x^2-15x+x-15\)(nhân chéo)
\(\Rightarrow x^2+2x-24=x^2-14x-15\)
\(\Rightarrow16x=9\)
\(\Rightarrow x=\frac{9}{16}\)
ta có: \(\frac{7}{6}-\frac{5}{2}x=\frac{13}{9}+\frac{7}{4}x\)
<=> \(\frac{7}{6}-\frac{13}{9}=\frac{7}{4}x+\frac{5}{2}x\)
<=> \(-\frac{5}{18}=\frac{17}{4}x\)
=> \(x=-\frac{10}{153}\)
đầu bài trên tớ làm luôn nhá !!!
a, / 3x+1/= 5-3
/ 3x+1/= 2
3x+1=2
x+1 = 2:3
x+1 = 2 phần 3
x= 2/3 -1
x= -1/3
\(\frac{2}{3}x-\frac{5}{4}=\frac{7}{6}-\frac{1}{2}x\)
\(\frac{2}{3}x+\frac{1}{2}x=\frac{7}{6}+\frac{5}{4}\)
\(\frac{7}{6}x=\frac{29}{12}\)
\(x=\frac{29}{12}:\frac{7}{6}\)
\(x=\frac{29}{14}\)
Ta có: \(\frac{2}{3}x-\frac{5}{4}=\frac{7}{6}-\frac{1}{2}x\)
\(\Rightarrow\frac{2}{3}x-\frac{1}{2}x=\frac{5}{4}+\frac{7}{6}\)
\(\Rightarrow\frac{1}{6}x=\frac{48}{24}=2\)
\(\Rightarrow x=2:\frac{1}{6}=12\)
X= 7 =>
\(P=\left(x-4\right)^{\left(x-5\right)^{\left(x-6\right)^{\left(x+6\right)^{\left(x+5\right)}}}}=\left(7-4\right)^{^{\left(7-5\right)^{\left(7-6\right)^{\left(7+6\right)^{\left(7+5\right)}}}}}\)
-> P= \(3^{2^{1^{13}}}\)
Tạch máy tính ta đc : 9
Thay x = 7 vào P , ta được P = (7 - 4)^(7 - 5)^(7 - 6)^(7 + 6)^(7 + 5) = 3^2^1^13^12 = 3^2 x 1^13^12 = 9 x 1 = 9
Vậy P = 9