Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\left(a+b+c\right)^2=a^2+b^2+c^2+2ab+2bc+2ac\)
\(\left(a+b-c\right)^2=a^2+b^2+c^2+2ab-2bc-2ac\)
\(\left(a-b-c\right)^2=a^2+b^2+c^2-2ab+2bc-2ac\)
\(\left(x-2y+1\right)^2=x^2+4y^2+1-4xy-4y+2x\)
\(\left(3x+y-2\right)^2=9x^2+y^2+4+6xy-12x-4y\)
( 2x - 6 ) ( x - 5 ) = ( 2x - 6 ) ( 2x - 4 )
<=> ( 2x - 6 ) ( x - 5 ) - ( 2x - 6 ) ( 2x - 4 ) = 0
<=> ( 2x - 6 ) ( x - 5 - 2x + 4 ) = 0
<=> ( 2x - 6 ) ( - x - - ) = 0
<=> \(\orbr{\begin{cases}2x-6=0\\-x-1=0\end{cases}}\)<=>\(\orbr{\begin{cases}x=3\\x=-1\end{cases}}\)
( 2x - 6) . ( x - 5) = ( 2x - 6) . ( 2x-4 )
x = 3
x = -1
chúc bạn học tốt
a) \(\left(a^2-4\right)\left(a^2+4\right)\)
\(=a^4-8\)
c) \(\left(a-b\right)\left(a+b\right)\left(a^2+b^2\right)\left(a^4+b^4\right)\)
=\(\left(a^2-b^2\right)\left(a^2+b^2\right)=a^4-b^4\)
d) \(\left(a-b+c\right)\left(a+b+c\right)\)
=\(a^2-\left(b+c\right)^2\)
e) \(\left(x+2-y\right)\left(x-2-y\right)\)
=\(x-\left(2-y\right)\)
mik lm tắt có gì sai cho mik xin lỗi
( a2 - 4 )( a2 + 4 ) = a4 - 16
( x3 - 3y )( x3 + 3y ) = x6 - 9y2
( a - b )( a + b )( a2 + b2 )( a4 + b4 ) = ( a2 - b2 )( a2 + b2 )( a4 + b4 ) = ( a4 - b4 )( a4 + b4 ) = a8 - b8
( a - b + c )( a + b + c ) = ( a + c )2 - b2 = a2 - b2 + c2 + 2ac
( x + 2 - y )( x - 2 - y ) = ( x - y )2 - 22 = x2 - 2xy + y2 - 4
a, \(\left(y-2\right)\left(y+2\right)\left(y^2+4\right)-\left(y+3\right)\left(y-3\right)\left(y^2+9\right)\)
\(=\left(y^2-4\right)\left(y^2+4\right)-\left(y^2-9\right)\left(y^2+9\right)\)
\(=y^4-16-y^4+81=65\)
b, \(2\left(x^2-xy+y^2\right)\left(x-y\right)\left(x^2+xy+y^2\right)\left(x+y\right)-2\left(x^6-y^6\right)\)
\(=2\left(x^3-y^3\right)\left(x^3+y^3\right)-2\left(x^6-y^6\right)\)
\(=2\left(x^6-y^6\right)-2\left(x^6-y^6\right)=0\)
lỗi