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A=4+4^2+4^3+...+4^50
A=(4+4^2)+(4^3+4^4)+...+(4^49+4^50)
A=(4+4^2)+4^2(4+4^2)+...+4^48(4+4^2)
A=4+4^2(4^2 +4^4+...+4^48)\(⋮\)10 (vì 4+4^2=20\(⋮\)10)
Vậy A\(⋮\)10
b/ Ta co : \(3^{15}-9^6=3^{15}-\left(3^2\right)^6=3^{15}-3^{12}=3^{12}.\left(3^3-1\right)=3^{12}.26\)
\(Do\)\(26⋮13\Rightarrow3^{12}.26⋮13\)\(hay\)\(3^{15}-9^6⋮13\)
a)1020=(102)10=10010
vì 100>90 nên 10010>9010
hay: 1020>9010
b) (-5)30=[(-5)3]10=(-125)10=12510 (10 là số chẵn)
(-3)50=[(-3)5]10=(-243)10=24310(10 là số chẵn)
vì 125<234 nên 12510<24310
hay (-5)30<(-3)50
1020=(102)10=10010>9010
vậy 1020>9010
(-5)30=[(-5)3]10=(-125)10
(-3)50=[(-3)5]10=(-243)10
=>(-5)30>(-3)50
mình trả lời đầu tiên
350 = 32.25 = (32)25 = 925
275 = 23.25 = (23)25 = 825
Vì 9 > 8
=> 925 > 825
=> 350 > 275
2.
a,\(50-\left[\left(50-2^3.5\right):2+3\right]\)
\(=50-\left[\left(50-40\right):2+3\right]\)
\(=50-\left(10:2+3\right)\)
\(=50-8\)
\(=42\)
b,\(8697-\left[3^7:3^5+2\left(13-3\right)\right]\)
\(=8697-\left(3^2+2.10\right)\)
\(=8697-\left(9+20\right)\)
\(=8697-29\)
\(=8668\)
c,\(205-\left[1200-\left(4^2-2.3\right)^3\right]:40\)
\(=205-200:40\)
\(=200\)
2)
a) \(50-\left[\left(50-2^3.5\right):2+3\right]\)
\(=50-\left[\left(50-8.5\right):2+3\right]\)
\(=50-\left[\left(50-40\right):2+3\right]\)
\(=50-\left(10:2+3\right)\)
\(=50-\left(5+3\right)\)
\(=50-8\)
\(=42\)
b) \(8697-\left[3^7:3^5+2\left(13-3\right)\right]\)
\(=8697-\left(3^7:3^5+2.10\right)\)
\(=8697-\left(3^{7-5}+2.10\right)\)
\(=8697-\left(3^2+2.10\right)\)
\(=8697-\left(9+2.10\right)\)
\(=8697-\left(9+20\right)\)
\(=8697-29\)
\(=8668\)
c) \(205-\left[1200-\left(4^2-2.3\right)^3\right]:40\)
\(=205-\left[1200-\left(16-2.3\right)^3\right]:40\)
\(=205-\left[1200-\left(16-6\right)^3\right]:40\)
\(=205-\left(1200-10^3\right):40\)
\(=205-\left(1200-1000\right):40\)
\(=205-200:40\)
\(=205-5\)
\(=200\)