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\(\frac{\left(-5\right)^3.40.4^3}{125.\left(-2\right)^{14}.\left(-1000\right)^0}\)
\(=\frac{\left(-125\right).40.64}{125.16384.1}\)
\(=\frac{\left(-1\right).5}{1.32.1}=-\frac{5}{32}\)
\(\frac{\left(-5\right)^3.40.4^3}{125.\left(-2\right)^{14}.\left(-1000\right)^0}\)
\(=\frac{\left(-5\right)^3.2^3.5.\left(2^2\right)^3}{5^3.2^{14}.1}\)
\(=\frac{\left(-5\right)^3.2^3.5.2^6}{5^3.2^{14}}\)
\(=\frac{\left(-5\right)^3.2^9.5}{5^3.2^{14}}\)
\(=\frac{-5}{2^5}\)
\(=\frac{-5}{32}\)
3*13-13*18=3*(3-18)=3*(-15)
15*40-80=15*(40-20)=15*20
\((-5)^3*10*4^3=(-5)^3*4^3*40 =(-20)^40 135*(-2)^14*(-100)= tự làm nhé k mk nha \)
\(A=2^0+2^1+2^2\)\(+2^3+...+\)\(2^{50}\)
\(2A=2+2^2+2^3+...+2^{51}\)
\(2A-A=A=2^{51}-2^0\)
\(B=5+5^2+5^3+...+5^{99}+5^{100}\)
\(5B=5^2+5^3+5^4+...+5^{100}+5^{101}\)
\(5B-B=4B=5^{101}-5\)
\(B=\frac{5^{101}-5}{4}\)
\(C=3-3^2+3^3-3^4+...+\)\(3^{2007}-3^{2008}+3^{2009}-3^{2010}\)
\(3C=3^2-3^3+3^4-3^5+...-3^{2008}+3^{2009}-3^{2010}+3^{2011}\)
\(3C+C=4C=3^{2011}+3\)
\(C=\frac{3^{2011}+3}{4}\)
\(S_{100}=5+5\times9+5\times9^2+5\times9^3+...+5\times9^{99}\)
\(S_{100}=5\times\left(1+9+9^2+9^3+...+9^{99}\right)\)
\(9S_{100}=5\times\left(9+9^2+9^3+...+9^{99}+9^{100}\right)\)
\(9S_{100}-S_{100}=8S_{100}=5\times\left(9^{100}-1\right)\)
\(S_{100}=\frac{5\times\left(9^{100}-1\right)}{8}\)
A=20+21+22+23+...++23+...+250250
2�=2+22+23+...+2512A=2+22+23+...+251
2�−�=�=251−202A−A=A=251−20
�=5+52+53+...+599+5100B=5+52+53+...+599+5100
5�=52+53+54+...+5100+51015B=52+53+54+...+5100+5101
5�−�=4�=5101−55B−B=4B=5101−5
�=5101−54B=45101−5
�=3−32+33−34+...+C=3−32+33−34+...+32007−32008+32009−3201032007−32008+32009−32010
3�=32−33+34−35+...−32008+32009−32010+320113C=32−33+34−35+...−32008+32009−32010+32011
3�+�=4�=32011+33C+C=4C=32011+3
�=32011+34C=432011+3
�100=5+5×9+5×92+5×93+...+5×999S100=5+5×9+5×92+5×93+...+5×999
�100=5×(1+9+92+93+...+999)S100=5×(1+9+92+93+...+999)
9�100=5×(9+92+93+...+999+9100)9S100=5×(9+92+93+...+999+9100)
9�100−�100=8�100=5×(9100−1)9S100−S100=8S100=5×(9100−1)
�100=5×(9100−1)8S100=85×(9100−1)
=-(2.3^3.5^3.7.2^3)/3.2^3.3.5^3.2.7
=-(2^4.3^3.5^3.7)/3^2.2^4.5^3.7
=-(1.3.1.1)/1.1.1.1
=-3/1=-3
\(\frac{9^{14}.25^5.8^7}{8^{12}.615^3.25^3}\)
\(=\frac{\left(3^3\right)^{14}.\left(5^2\right)^5.8^7}{8^{12}.\left(3.5.41\right)^3.\left(5^2\right)^3}\)
\(=\frac{3^{42}.5^{10}.8^7}{8^{12}.3^3.5^7.41^3}\)
\(=\frac{3^{39}.5^3}{8^5.41^3}\)
có phân số nào mà rút gọn bạn
cái trên là tử số cái dưới là mẫu số