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\(\frac{3.4+3.7}{6.5+9}=\frac{3\left(4+7\right)}{30+9}=\frac{3.11}{39}=\frac{33}{39}=\frac{11}{13}\)
ko
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A.\(\frac{2^3.9^2}{2^2.3^2.5}=\frac{2^2.2.\left(3^2\right)^2}{2^2.3^2.5}=\frac{2.3^2}{5}=\frac{18}{5}\)
B.\(\frac{2^4.5^5.11^2.7}{2^3.5^3.7^2.11}=\frac{2^3.2.5^3.5^2.11.11.7}{2^3.5^3.7.7.11}=\frac{2.5^2.11}{7}=\frac{61}{7}\)
\(\frac{3.4+3.7}{6.5+9}\)và \(\frac{6.9-2.17}{63.3-119}\)
\(\frac{3.4+3.7}{6.5+9}=\frac{3\left(4+7\right)}{30+9}=\frac{3.11}{39}=\frac{33}{39}=\frac{11}{13}\)
\(\frac{6.9-2.17}{63.3-119}=\frac{54-54}{63.3-11}=0\)
a) -15/90= -5/30= -1/6
120/600=1/5
-75/150= -25/50= -1/2
b)3.4+3.7/6.5+9
=3.(4+7)/3.2+3 .3
=11/2+3.3
=11/11=1
6.9-2.17/63.3-11.9
=2.3.3.3-2.17/7.3.3-11.3.3
=2-2.17/7.3-11
= 2-2.17/10
=2-2.17/2.5
=2-17/5
=-15/5=-3
\(=\frac{3\left(7+4\right)}{3\left(2+7\right)}=\frac{11}{9}\)
k mk nhé ^_^ Cảm ơn ^_^
\(\frac{3.7+3.4}{2.3+3.7}=\frac{3.\left(7+4\right)}{3\cdot\left(7+3\right)}=\frac{3.11}{3.10}=3\)