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5 tháng 10 2021

\(=\left(x-\dfrac{1}{3}\right)\left(\dfrac{4}{3}x+\dfrac{1}{9}-x+\dfrac{1}{3}\right)\\ =\left(x-\dfrac{1}{3}\right)\left(\dfrac{1}{3}x+\dfrac{4}{9}\right)\\ =\dfrac{1}{3}x^2+\dfrac{4}{9}x-\dfrac{1}{9}x-\dfrac{4}{27}\\ =\dfrac{1}{3}x^2+\dfrac{1}{3}x-\dfrac{4}{27}\)

5 tháng 10 2021

a) \(=x^3-\dfrac{1}{27}-x^2+\dfrac{2}{3}x-\dfrac{1}{9}=x^3-x^2+\dfrac{2}{3}x-\dfrac{2}{27}\)

b) \(=x^6-6x^4+12x^2-8-x^3+x+x^2-3x=x^6-6x^4-x^3+13x^2-2x-8\)

5 tháng 10 2021

\(=x^6-6x^4+12x^2-8-x^3+x+6x^2-18x\\ =x^6-6x^4-x^3+18x^2-17x-8\)

27 tháng 4 2017

a)\(x\left(2x^2-3\right)-x^2\left(5x+1\right)+x^2\)

=\(2x^3-3x-5x^3-x^2+x^2=-3x^3-3x\)

b) \(3x\left(x-2\right)-5x\left(1-x\right)-8\left(x^2-3\right)\)

\(=3x^2-6x-5x+5x^2-8x^2+24=-11x+24\)

c) \(\dfrac{1}{2}x^2\left(6x-3\right)-x\left(x^2+\dfrac{1}{2}\right)+\dfrac{1}{2}\left(x+4\right)\)

\(=3x^3-\dfrac{3}{2}x^2-x^3-\dfrac{1}{2}x+\dfrac{1}{2}x+2=2x^3-\dfrac{3}{2}x^2+2\)

22 tháng 7 2017

a) \(\left(\dfrac{3x}{1-3x}+\dfrac{2x}{3x+1}\right):\dfrac{6x^2+10x}{9x^2-6x+1}\)

\(=-\dfrac{9x^2+3x+2x-6x^2}{\left(3x-1\right)\left(3x+1\right)}.\dfrac{\left(3x-1\right)^2}{2x\left(3x+5\right)}\)

\(=-\dfrac{x\left(3x+5\right)}{\left(3x-1\right)^2}.\dfrac{\left(3x-1\right)^2}{2x\left(3x+5\right)}\)

\(=\dfrac{-1}{2}\)

b) \(\left(\dfrac{9}{x^3-9x}+\dfrac{1}{x+3}\right):\left(\dfrac{x-3}{x^2+3x}-\dfrac{x}{3x+9}\right)\)

\(=\left(\dfrac{9+x^2-3x}{x\left(x-3\right)\left(x+3\right)}\right):\left(\dfrac{3x-9-x^2}{3x\left(x+3\right)}\right)\)

\(=\dfrac{x^2-3x+9}{x\left(x-3\right)\left(x+3\right)}.\dfrac{3x\left(x+3\right)}{-x^2+3x-9}\)

\(=\dfrac{x^2-3x+9}{x-3}.\dfrac{3}{-\left(x^2-3x+9\right)}\)

\(=-\dfrac{3}{x-3}\)

17 tháng 7 2017

Nguyễn Huy Tú :v

17 tháng 7 2017

a,\(\dfrac{3}{x-3}\) - \(\dfrac{6x}{9-x^2}\) + \(\dfrac{x}{x+3}\) (*)

đkxđ: x khác 3, x khác -3

(*) \(\dfrac{3(x+3)}{\left(x-3\right).\left(x+3\right)}\)- \(\dfrac{6x}{\left(x-3\right).\left(x+3\right)}\) + \(\dfrac{x\left(x+3\right)}{\left(x-3\right).\left(x+3\right)}\)

=>3x+9 -6x + x2+3x

<=>x2 + 3x-6x+3x + 9

<=>x2 +9

<=>(x-3).(x+3)

5 tháng 12 2017

\(P=\left[\dfrac{x^2}{2x-9}\left(\dfrac{3}{x}-\dfrac{1}{x-3}\right)-\dfrac{x+6}{2\left(x-3\right)}\right]:\dfrac{x+2}{2\left(x-3\right)}\)

\(\Leftrightarrow P=\left[\dfrac{x^2}{2x-9}\left(\dfrac{3\left(x-3\right)}{x\left(x-3\right)}-\dfrac{x}{x\left(x-3\right)}\right)-\dfrac{x+6}{2\left(x-3\right)}\right]:\dfrac{x+2}{2\left(x-3\right)}\)

\(\Leftrightarrow P=\left[\dfrac{x^2}{2x-9}.\dfrac{3x-9-x}{x\left(x-3\right)}-\dfrac{x+6}{2\left(x-3\right)}\right]:\dfrac{x+2}{2\left(x-3\right)}\)

\(\Leftrightarrow P=\left[\dfrac{x^2}{2x-9}.\dfrac{2x-9}{x\left(x-3\right)}-\dfrac{x+6}{2\left(x-3\right)}\right]:\dfrac{x+2}{2\left(x-3\right)}\)

\(\Leftrightarrow P=\left[\dfrac{x^2.\left(2x-9\right)}{\left(2x-9\right)x\left(x-3\right)}-\dfrac{x+6}{2\left(x-3\right)}\right]:\dfrac{x+2}{2\left(x-3\right)}\)

\(\Leftrightarrow P=\left[\dfrac{x}{x-3}-\dfrac{x+6}{2\left(x-3\right)}\right]:\dfrac{x+2}{2\left(x-3\right)}\)

\(\Leftrightarrow P=\left[\dfrac{2x}{2\left(x-3\right)}-\dfrac{x+6}{2\left(x-3\right)}\right]:\dfrac{x+2}{2\left(x-3\right)}\)

\(\Leftrightarrow P=\dfrac{2x-\left(x+6\right)}{2\left(x-3\right)}:\dfrac{x+2}{2\left(x-3\right)}\)

\(\Leftrightarrow P=\dfrac{2x-x-6}{2\left(x-3\right)}:\dfrac{x+2}{2\left(x-3\right)}\)

\(\Leftrightarrow P=\dfrac{x-6}{2\left(x-3\right)}:\dfrac{x+2}{2\left(x-3\right)}\)

\(\Leftrightarrow P=\dfrac{x-6}{2\left(x-3\right)}.\dfrac{2\left(x-3\right)}{x+2}\)

\(\Leftrightarrow P=\dfrac{\left(x-6\right).2\left(x-3\right)}{2\left(x-3\right).\left(x+2\right)}\)

\(\Leftrightarrow P=\dfrac{x-6}{x+2}\)