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A, \(\dfrac{7}{9}\) = \(\dfrac{7\cdot5}{9\cdot5}\) = \(\dfrac{35}{45}\) \(\dfrac{3}{5}\) = \(\dfrac{3\cdot9}{5\cdot9}\) = \(\dfrac{27}{45}\)
Vậy \(\dfrac{7}{9}\) > \(\dfrac{3}{5}\)
B, \(\dfrac{3}{4}\) = \(\dfrac{3\cdot6}{4\cdot6}\) = \(\dfrac{18}{24}\) \(\dfrac{5}{6}\) = \(\dfrac{5\cdot4}{6\cdot4}\) = \(\dfrac{20}{24}\)
Vậy \(\dfrac{3}{4}\) < \(\dfrac{5}{6}\)
C, \(\dfrac{1}{4}\) = \(\dfrac{1\cdot3}{4\cdot3}\) = \(\dfrac{3}{12}\) \(\dfrac{2}{3}\) = \(\dfrac{2\cdot4}{3\cdot4}\) = \(\dfrac{8}{12}\)
Vậy \(\dfrac{1}{4}\) < \(\dfrac{2}{3}\)
D, \(\dfrac{8}{9}\) = \(\dfrac{8\cdot2}{9\cdot2}\) = \(\dfrac{16}{18}\) \(\dfrac{1}{2}\) = \(\dfrac{1\cdot9}{2\cdot9}\) = \(\dfrac{9}{18}\)
Vậy \(\dfrac{8}{9}\) > \(\dfrac{1}{2}\)
\(\cdot\) là dấu nhân
`a,MSC:30`
`1/2=(1xx15)/(2xx15)=15/30`
`2/3=(2xx10)/(3xx10)= 20/30`
`3/5=(3xx6)/(5xx6)=18/30`
`b,MSC:12`
`2/3=(2xx4)/(3xx4)=8/12`
`3/4=(3xx3)/(4xx3)=9/12`
`7/12` giữ nguyên
bài3
1. \(\frac{4}{3}\)= \(\frac{4x4}{3x4}\)=\(\frac{20}{12}\)
\(\frac{3}{4}\)=\(\frac{3x3}{4x3}\)=\(\frac{9}{12}\)
2.\(\frac{5}{4}\)=\(\frac{5x6}{4x6}\)=\(\frac{30}{24}\)
\(\frac{5}{6}\)=\(\frac{5x4}{6x4}\)=\(\frac{20}{24}\)
3.\(\frac{3}{8}\)=\(\frac{3x6}{8x6}\)=\(\frac{18}{48}\)
\(\frac{1}{6}\)=\(\frac{1x6}{6x8}\)=\(\frac{6}{48}\)
4.\(\frac{2}{5}\)=\(\frac{2x7}{5x7}\)=\(\frac{14}{35}\)
\(\frac{4}{7}\)=\(\frac{4x5}{7x5}\)=\(\frac{20}{35}\)
Bài 3 :
a: \(MSC:12\\ \dfrac{4}{3}=\dfrac{4\times4}{3\times4}=\dfrac{16}{12};\dfrac{3}{4}=\dfrac{3\times3}{3\times4}=\dfrac{9}{12}\)
b: \(MSC:12\\ \dfrac{5}{4}=\dfrac{5\times3}{4\times3}=\dfrac{15}{12};\dfrac{5}{6}=\dfrac{5\times2}{6\times2}=\dfrac{10}{12}\)
c:\(MSC:24\\ \dfrac{3}{8}=\dfrac{3\times3}{8\times3}=\dfrac{9}{24};\dfrac{1}{6}=\dfrac{1\times2}{6\times2}=\dfrac{2}{12}\)
d: \(MSC:35\\ \dfrac{2}{5}=\dfrac{2\times7}{5\times7}=\dfrac{14}{35};\dfrac{4}{7}=\dfrac{4\times5}{7\times5}=\dfrac{20}{35}\)
Bài 3:
a: 4/3=16/12
3/4=9/12
b: 5/4=30/24
5/6=20/24
c: 3/8=18/48
1/6=8/48
d: 2/5=14/35
4/7=20/35
Bài 4:
a: 7/12=28/48
5/48=5/48
b: 4/100=4/100
8/25=32/100
\(\frac{1}{3};\frac{2}{15};\frac{4}{45}\)
Ta có : Mẫu số chung là 45 vì \(45\) \(⋮3;15\)
\(\frac{1}{3}=\frac{1.15}{3.15}=\frac{15}{45}\)
\(\frac{2}{15}=\frac{2.3}{15.3}=\frac{6}{45}\)
Còn \(\frac{4}{45}\)ta giữ nguyên.
Ta có : (MSC:30)
1/6=1.5=5 / 6.5=30
4/5=4.6=24 /5.6=30
Vậy QĐMS 2PS 1/6 và 4/5 được 5/30 và 24/30
Ta có : (MSC:45)
12/5=12.9= 108/ 5.9=45
5/9=5.5=25 / 9.5=45
Vậy QĐMS 2PS 12/5 và 5/9 được 108/45 và 25/45
\(\dfrac{7}{12};\dfrac{13}{6}\)
⇒\(\dfrac{7}{12};\dfrac{26}{12}\)
ta đc 2 phân số 7/12 và 26/12 vậy đc 2 phân số 7/12 và 26/12 hok tốt fan conan kb nha
\(\dfrac{11}{12}=\dfrac{11.4}{12.4}=\dfrac{44}{48}\) và \(\dfrac{7}{48}\)
\(\dfrac{61}{200};\dfrac{9}{50}=\dfrac{9.4}{50.4}=\dfrac{36}{200}\)
\(\dfrac{1}{3}=\dfrac{1.15}{3.15}=\dfrac{15}{45}\); \(\dfrac{2}{15}=\dfrac{2.3}{15.3}=\dfrac{6}{45}\) và 4/45
\(a.\dfrac{3}{4}=\dfrac{3.9}{4.9}=\dfrac{27}{36}\)
\(\dfrac{5}{9}=\dfrac{5.4}{9.4}=\dfrac{20}{36}\)
\(b.\dfrac{5}{6}=\dfrac{5.3}{6.3}=\dfrac{15}{18}\) giữ nguyên phân số còn lại
c. \(\dfrac{3}{8}=\dfrac{3.3}{8.3}=\dfrac{9}{24}\)
\(\dfrac{7}{12}=\dfrac{7.2}{12.2}=\dfrac{14}{24}\)
d. \(\dfrac{11}{12}=\dfrac{11.4}{12.4}=\dfrac{44}{48}\)
giữ nguyên phân số còn lại.
e. \(\dfrac{9}{50}=\dfrac{9.4}{50.4}=\dfrac{36}{200}\)
giữ nguyên phân số còn lại
\(f.\dfrac{1}{3}=\dfrac{1.3}{15.3}=\dfrac{3}{45}\)
\(\dfrac{2}{15}=\dfrac{2.3}{15.3}=\dfrac{6}{45}\)
giữ nguyên phân số còn lại
\(a,\dfrac{1}{4},\dfrac{5}{6}và\dfrac{7}{12}\)
\(\dfrac{1}{4}=\dfrac{1\times3}{4\times3}=\dfrac{3}{12};\dfrac{5}{6}=\dfrac{5\times2}{6\times2}=\dfrac{10}{12};\dfrac{7}{12}\)
\(b,\dfrac{1}{9},\dfrac{3}{5},\dfrac{11}{45}\)
\(\dfrac{1}{9}=\dfrac{1\times5}{9\times5}=\dfrac{5}{45};\dfrac{3}{5}=\dfrac{3\times9}{5\times9}=\dfrac{27}{45};\dfrac{11}{45}\)